
(a)
Interpretation :
Reactant and product graphs must be labeled.
Concept Introduction :
Concentration of reactants gradually decreases and that of product increases.
(a)

Answer to Problem 5E
Blue and green graphs are for reactants. Red graph is for product.
Explanation of Solution
As per the graphs it is clear that with time blue and green graphs are coming downward, i.e., concentration decreases. Red graph is going upward, i.e., concentration is increasing. Thus blue and green graphs are for reactants and red graph is for product.
b)
Interpretation :
Equilibrium concentrations of reactant and product must be read from the graph.
Concept Introduction :
At equilibrium
b)

Answer to Problem 5E
Equilibrium concentrations of blue graph and green graph reactants are 0.5 M and 0.25 M respectively. equilibrium concentration of product (red graph) is 1.25 M.
Explanation of Solution
Equilibrium concentration is the concentration where the graphs are parallel to x-axis(time). At this point there is no change in concentration as the forward and backward reactions are taking place in same rate. From the graphs all the concentrations are found.
c)
Interpretation :
The time taken to reach equilibrium must be found out.
Concept Introduction :
Time when the forward reaction and backward reaction is taking place in same speed then equilibrium is attained.
c)

Answer to Problem 5E
It took around 25 s to reach equilibrium.
Explanation of Solution
From the graphs it is clear that all the three graphs become parallel after 25 s. At this time point forward and backward reaction is taking place in same speed. So it took 25 s for the attainment of equilibrium.
d)
Interpretation :
The variable which is equal at equilibrium must be explained.
Concept Introduction :
At equilibrium rate of forward and backward reactions are same.
d)

Answer to Problem 5E
At equilibrium rate of forward reaction is “equal” to rate of backward reaction.
Explanation of Solution
After 25 s the reaction has attained equilibrium. At this point all the three graphs are parallel to time axis which means there is no change in concentration of reactants or product with time. So rate of forward reaction is “equal” to rate of backward reaction at equilibrium.
Chapter U6 Solutions
Living by Chemistry
Additional Science Textbook Solutions
Biology: Life on Earth (11th Edition)
Human Physiology: An Integrated Approach (8th Edition)
Campbell Biology in Focus (2nd Edition)
Genetic Analysis: An Integrated Approach (3rd Edition)
Microbiology: An Introduction
Chemistry: An Introduction to General, Organic, and Biological Chemistry (13th Edition)
- Blocking Group are use to put 2 large sterically repulsive group ortho. Show the correct sequence toconnect the reagent to product with the highest yield possible. * see image **NOTE: The compound on the left is the starting point, and the compound on the right is the final product. Please show the steps in between to get from start to final, please. These are not two different compounds that need to be worked.arrow_forwardI dont understand this.arrow_forwardCan you please explain this prooblem to me, show me how the conjugation is added, did I add them in the correct places and if so please show me. Thanks!arrow_forward
- Basic strength of organic bases.arrow_forwardNucleophilic Aromatic Substitution: What is the product of the reaction? What is the name of the intermediate complex? *See imagearrow_forwardPredict the final product. If 2 products are made, list which should be “major” and “minor” *see attachedarrow_forward
- Nucleophilic Aromatic Substitution: What is the product of the reaction? *see imagearrow_forwardShow the correct sequence to connect the reagent to product. * see imagearrow_forwardThe answer here says that F and K have a singlet and a doublet. The singlet and doublet are referring to the H's 1 carbon away from the carbon attached to the OH. Why don't the H's two carbons away, the ones on the cyclohexane ring, cause more peaks on the signal?arrow_forward
- Draw the Birch Reduction for this aromatic compound and include electron withdrawing groups and electron donating groups. *See attachedarrow_forwardShow the correct sequence to connect the reagent to product. * see imagearrow_forwardBlocking Group are use to put 2 large sterically repulsive group ortho. Show the correct sequence toconnect the reagent to product with the highest yield possible. * see imagearrow_forward
- ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistryChemistryISBN:9781259911156Author:Raymond Chang Dr., Jason Overby ProfessorPublisher:McGraw-Hill EducationPrinciples of Instrumental AnalysisChemistryISBN:9781305577213Author:Douglas A. Skoog, F. James Holler, Stanley R. CrouchPublisher:Cengage Learning
- Organic ChemistryChemistryISBN:9780078021558Author:Janice Gorzynski Smith Dr.Publisher:McGraw-Hill EducationChemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage LearningElementary Principles of Chemical Processes, Bind...ChemistryISBN:9781118431221Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. BullardPublisher:WILEY





