Concept explainers
Interpretation:
The structures of A, B, and C are to be determined with the help of given information.
Concept introduction:
舧 Infrared spectroscopy is a simple, instrumental technique, which helps to determine the presence of various
舧 It depends on the interactions of atoms or molecules with the
舧 The molecules that have dipole moment are IR active and the molecules that do not have dipole moment are IR inactive.
舧 Electrophiles are electron-deficient species, which has positive or partially positive charge. Lewis acids are electrophiles, which accept electron pair.
舧 Nucleophiles are electron-rich species, which has negative or partially negative charge. Lewis bases are nucleophiles, which donate electron pair.
舧 Substitution reaction: A reaction in which one of the hydrogen atoms of a hydrocarbon or a functional group is substituted by any other functional group is called substitution reaction.
舧 Elimination reaction: A reaction in which two substituent groups are detached and a double bond is formed is called elimination reaction.
舧 Addition reaction: It is the reaction in which unsaturated bonds are converted to saturated molecules by the addition of molecules.
舧 The reaction in which there is addition of hydrogen molecule is called hydrogenation reaction.
舧 Symmetrical
舧 Osmium tetroxide is an oxidizing agent.
舧 The reaction of alkyne with
舧 Sodium bisulfite acts as a reducing agent.
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Organic Chemistry
- Cr(VI) compounds are common reagents for the oxidation of alcohols. Primary alcohols are oxidized to carboxylic acids and secondary alcohols are oxidized to ketones. The mechanism involves a reaction similar to the E2 elimination, whereby a C=O double bond is formed with a reduced Cr(IV) compound as the leaving group.Draw curved arrows to show the movement of electrons in this step of the mechanism.arrow_forwardA chemist synthesized compound X as a racemic mixture. When the ketone group in X was enzymatically reduced to the corresponding alcohol, a 100% yield was obtained of the product shown below. Choose the statement that best describes this result. ОН enzyme C;H1 `OCH,CH; pH 4.0 C3H1 `OCH,CH3 ОН ÕH X (racemic) (100% yield) One enantiomer of compound X reacts quickly with the enzyme. The other enantiomer of compound X is unreactive, but rapidly equilibrates with the reactive enantiomer under the reaction conditions. Since compound X was racemic, it makes sense that only a single product was obtained. O The product is a meso compound, so either enantiomer of compound X gives the same product. One enantiomer of compound X reacts quickly with the enzyme, while the other enantiomer of compound X remains unchanged.arrow_forwardNitromethane is reacted with ethyl prop-2-enoate with EtO-Na+, EtOH 3 equivalents to give the product X(C16). X then reacts with H2/Raney Ni to give the product Y(C14), which in turn reacts with Na to give Z (C12). Indicate which products X, Y and Z are.arrow_forward
- Compound A (C6H12O2) reacts with water, acid, and heatto yield compound B (C5H10O2) and compound C (CH4O).Compound B is acidic. Deduce possible structures of compounds A, B, and Carrow_forwardA compound, C2H2O4, reacts with excess diazomethane to produce C4H,O4. Draw the structure of each compound. CH,N2 (excess) C2H2O4 C4H,O4arrow_forwardReaction of (CH3)3CH with Cl2 forms two products: (CH3)2CHCH2Cl (63%) and (CH3)3CCl (37%). Why is the major product formed by cleavage of the stronger 1° C–H bond?arrow_forward
- The reaction of N−bromosuccinimide with 4−methyl−3−nitroanisole has been reported in the chemical literature. This reaction yields a single product in 95% yield. Identify the product formed from this starting material.arrow_forwardSharpless epoxidation of allylic alcohol X forms compound Y. Treatment of Y with NaOH and C6H5SH in an alcohol–water mixture forms Z. Identify the structure of Y and draw a mechanism for the conversion of Y to Z. Account for the stereochemistry of the stereogenic centers in Z. Z has been used as an intermediate in the synthesis of chiral carbohydrates.arrow_forwardSharpless epoxidation of allylic alcohol X forms compound Y. Treatment of Y with NaOH and C6H5SH in an alcohol–water mixture forms Z. Identify the structure of Y and draw a mechanism for the conversion of Y to Z. Account for the stereochemistry of the stereogenic centers in Z. Z has been used as an intermediate in the synthesis of chiral carbohydrates.arrow_forward
- Compound A (C3H17B1) undergo dehydrohalogenation to produce major compound B. Compound C was formed when compound B undergo halogenation in room temperature. Compound B undergo halogenation in aqueous solution to form compound D. Compound B undergo hydrohalogenation in the presence of H202 to form Compound E. Compound B undergo oxidation with hot acidified KMN04 to produce compound F and Compound G. Compound H was produced when Compound B react with cold KMN04. Compound B undergo ozonolysis to form Compound I and Compound J. Compound K was formed when compound B reacted with hydrogen in the presence of platinum. Compound A reacted with sodium hydroxide to form compound L. Compound M was produced when compound A reacted with ammonia in ethanol while compound N was formed when compound A reacted with sodium cyanide. Reaction X happened when compound K reacted with bromine in the presences of UV light. a) Identify the possible structural formulae for compound A to N. The number of carbon…arrow_forwardHydrocarbon X has the formula C6H12.X reacts with one molar equivalent of hydrogen in the presence of a palladium catalyst to form a product having 12 primary hydrogens.Treatment of X with ozone followed by zinc in aqueous acid gives a mixture two aldehydes.What is the structure of X?arrow_forwardHow many rings and π(pi) bonds are contained in compound A and draw one possible structure for this compound A. Compound A has molecular formula C6H10 and is hydrogenated to a compound having molecular formula C6H12arrow_forward