Organic Chemistry
Organic Chemistry
11th Edition
ISBN: 9781118133576
Author: T. W. Graham Solomons, Craig Fryhle
Publisher: Wiley, John & Sons, Incorporated
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Chapter FRP, Problem 13P

An alkane (A) with the formula C 6 H 14 reacts with chlorine to yield three compounds with the formula C 6 H 13 C l ; B, C, and D. Of these only C and D undergo dehydrohalogenation with sodium ethoxide in ethanol to produce an alkene. Moreover C and D yield the same alkene E ( C 6 H 12 ) . Hydrogenation of E produces A. Treating E with HCl produces a compound (F) that is an isomer of B, C, and D. Treating F with magnesium in dry ether followed by aqueous acid gives a compound (G) that is isomeric with A. Propose structures for A-G.

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Compound A has molecular formula C4H10. Compound A gives two monochlorides, B and C, on photochemical chlorination. Treatment of either of these monochlorides with potassium tert-butoxide gives the same alkene (C4H8) as the product, but B leads to just one isomer of the alkene, D, whereas C gives D and another isomer of the alkene, E. Treatment of monochlorides B and C with aqueous ethanol gives products F and G, respectively, both of which are of molecular formula C4H100. What are the chemical names of compounds A-G?
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4. Compound A has the formula C 8H 8.  It reacts rapidly with KMnO 4 to give CO 2 and a carboxylic acid, B (C 7H 6O 2), but reacts with only 1 molar equivalent of H 2 on catalytic hydrogenation over a palladium catalyst.  On hydrogenation under conditions that reduce aromatic rings, 4, equivalents of H 2 are taken up and hydrocarbon C (C 8H 16) is produced.  What are the structures of A, B, and C.
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