Concept explainers
(a)
Interpretation:
Empirical formula for the oxide that is formed when copper is reacted with oxygen has to be given.
Concept Introduction:
Empirical formula is the one that can be determined from the molar mass of the elements that is present in the compound and the mass percentage of the elements. The mass percentage of the elements present in the compound is converted into the moles of each element considering the molar mass of each element. The relative number of moles for each type of atoms is found out finally.
(b)
Interpretation:
The oxide formed from copper and oxygen has to be named.
Concept Introduction:
Ionic compounds are named considering the cation and anion present in it. The cation part is written first followed by the anion part.
Rules for naming ionic compounds:
- The cation and anion present in the ionic compound has to be identified. Oxidation number of the cation has to be decided in order to cancel the charge of the negative anions.
- Cation is named first. In case, if the metal belongs to
transition metals , then the oxidation number is shown using Roman numeral and entered in parenthesis. - Anion has to be named next. If monoatomic anion is present, then the element name is ended with –ide. If an oxoanion is present then suffix –ate is added for the ion that has large number of oxygen atoms and suffix –ite is added for the ion that has less number of oxygen atoms. If the element can form a series of four oxoanions, then for the oxoanion having the less number of oxygen atoms, prefix hypo- is added and prefix per- is added if the oxoanion contains highest number of oxygen atoms.
- If water molecule is present in the formula of the ionic compound, then the word hydrate is added along with the Greek prefix that correspond to the number of water molecules present in it.
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Chapter F Solutions
CHEM PRINCIPLES LL W/ACHIEVE ONE-SEM
- true or false The equilibrium constant for this reaction is 0.20. N2O4(g) ⇔ 2NO2(g) Based on the above, the equilibrium constant for the following reaction is 0.4. 2N2O4(g) ⇔ 4NO2(g)arrow_forwardtrue or false Using the following equilibrium, if heat is added the equilibrium will shift toward the reactants. N2(g) + 3H2(g) ⇔ 2NH3(g) + heatarrow_forwardTrue or False Using the following equilibrium, if heat is added the equilibrium will shift toward the products. N2O4(g) + heat ⇔ 2NO2(g)arrow_forward
- true or false Using the following equilibrium, if solid carbon is added the equilibrium will shift toward the products. C(s) + CO2(g) ⇔ 2CO(g)arrow_forwardProvide the complete mechanism for the reaction below. You must include appropriate arrows,intermediates, and formal charges. Please also provide a reason to explain why the 1,4-adduct is preferred over the 1,3-adduct.arrow_forwardWhich of the following pairs are resonance structures of one another? I. III. || III IV + II. :0: n P !༠ IV. EN: Narrow_forward
- Predict the major organic product(s) and byproducts (either organic or inorganic) for thefollowing reactions.arrow_forwardA 8.25 g sample of aluminum at 55°C released 2500 J of heat. The specific heat of aluminum is 0.900 J/g°C. The density of aluminum is 2.70 g/mL. Calculate the final temperature of the aluminum sample in °C.arrow_forwardPredict the major organic product(s) and byproducts (either organic or inorganic) for thefollowing reactions.arrow_forward
- Predict the major organic product(s) and byproducts (either organic or inorganic) for thefollowing reaction.arrow_forwardplease helparrow_forwardExperiment 1 Data Table 1: Conservation of Mass - Initial Mass Data Table 1 Data Table 2 Data Table 3 Data Table 4 Panel 1 Photo 1 Data Table 5 Reaction Mass of test tube and 5.0% HC₂H₂O2 (g) # (A) (B) Mass of NaHCO, (g) Mass of balloon and NaHCO, (g) (C) 0.10 1 0829 14.38g 0.20 2 0.929 14.29g 0.35 1.00g 3 14.25g 0.50 1.14g 14.29 Experiment 1 Data Table 2: Moles of HC2H3O2 Reaction Volume of Mass of Moles of HC₂H₂O₂ 5.0% Vinegar (g) (ML) 5.0 0.25 0042 mol 2 5.0 0.25 0042 mol 3 5.0 0.25 0042 mol 5.0 0.25 0042 mol Experiment 1 Data Table 3: Moles of NaHCO3 Reaction Mass of NaHCO (g) 10g 20g 35g 50g Experiment 1 Data Table 4: Theoretical Yield of CO₂ Reaction # 1 2 3 Experiment 1 Total mass before reaction (g) (D=A+C) 15.29 15.21g 15.25g 15.349 Exercise 1 Data Table 1 Data Table 2 Data Table 3 Data Table 4 Panel 1 Photo 1 Data Table 5 Exercise 1- Data Table 1 Data Table 2 DataTable 3 Data Table 4 Panel 1 Photo 1 Data Table 5 Exercise 1- Moles of NaHCO 0012 mol 0025 mol 0044 mol 0062 mol…arrow_forward
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