Explanation The reaction of calcium carbonate with HCl is given as shown below; CaCO 3 ( s ) + 2HCl(aq) → CaCl 2 (aq) + CO 2 (g) + H 2 O(l) Neutralization of HCl by CaCO 3 : Moles of CaCO 3 in 400 mg of CaCO 3 is calculated as shown below; n = m M = 400 × 10 − 3 g 100.1 g ⋅ mol − 1 = 4.00 × 10 − 3 mol From the above equation, it is found that one mole of CaCO 3 neutralizes 2 mol of HCl . Therefore, the amount of moles of HCl neutralized can be calculated can be given as follows; Amount of HCl(mol) = 4.00 × 10 − 3 mol of CaCO 3 × 2 mol of HCl 1 mol of CaCO 3 = 8.00 × 10 − 3 mol Thus the amount of HCl neutralized by CaCO 3 will be 8.00 × 10 − 3 mol . Neutralization of HCl by Mg(OH) 2 : The neutralization reaction between magnesium hydroxide and hydrochloric acid is given as shown below; Mg(OH) 2 ( s ) + 2HCl → MgCl 2 ( aq ) + 2H 2 O ( l ) Moles of Mg(OH) 2 in 150 mg of Mg(OH) 2 is calculated as shown below; n = m M = 150 × 10 − 3 g 58

7th Edition

ISBN: 9781319420994

Author: ATKINS

Publisher: MAC HIGHER

See similar textbooks

Concept explainers

Thermochemistry

Thermochemistry can be considered as a branch of thermodynamics that deals with the connections between warmth, work, and various types of energy, formed because of different synthetic and actual cycles. Thermochemistry describes the energy changes that …

Exergonic Reaction

The term exergonic is derived from the Greek word in which ‘ergon’ means work and exergonic means ‘work outside’. Exergonic reactions releases work energy. Exergonic reactions are different from exothermic reactions, the one that releases only heat energ…

Videos

Question

Chapter F, Problem L.11E

Interpretation Introduction

Interpretation:

The mass of HCl that can be neutralized by 400 mg of CaCO3 and 150 mg of Mg(OH)2 has to be calculated.

Concept Introduction:

Mass to mass conversion is done by considering the mass and molar mass of the reactant. From the mass and molar mass of reactant, the number of moles of reactant is calculated. Considering the balanced chemical equation, the number of moles of product formed is calculated using the conversion factor and finally the mass of product obtained is calculated using the molar mass of the product.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Chapter F, Problem L.10E

Chapter F, Problem L.12E

Chapter F Solutions

CHEM PRINCIPLES LL W/ACHIEVE ONE-SEM

Ch. F - Prob. A.1AST Ch. F - Prob. A.1BST Ch. F - Prob. A.2AST Ch. F - Prob. A.2BST Ch. F - Prob. A.3AST Ch. F - Prob. A.3BST Ch. F - Prob. A.4AST Ch. F - Prob. A.4BST Ch. F - Prob. A.5AST Ch. F - Prob. A.5BST

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.

Solution Summary: The author explains that the mass of HCl that can be neutralized by

Concept explainers

Videos

Want to see the full answer?

Chapter F Solutions