Chapter F, Problem A.22E

Interpretation Introduction

Interpretation:

Volume of lead has to be calculated that has the same mass of $\text{215}{\text{cm}}^{\text{3}}$ of redwood with density of $0.38\text{g}\cdot {\text{cm}}^{-3}$.

Concept Introduction:

Density is a physical property and specific for each substance under fixed conditions.  It is defined as the ratio of mass of a substance to the volume of the substance.  They are usually expressed as grams per cubic centimeter (${\text{g/cm}}^{\text{3}}$) for solids and grams per milliliter ($\text{g/mL}$) for liquids.

  $\text{Density}\text{=}\frac{\text{mass}}{\text{volume}}$

From the above formula volume can be calculated if the mass and density is known by rearranging the formula as shown below;

    $\text{Volume}\text{=}\frac{\text{mass}}{\text{density}}$