Concept explainers
(a)
Interpretation:
The structure for the given IUPAC name is to be drawn.
Concept introduction:
In naming ester, the alkyl group is cited first followed by the carboxylate group separated by a space. Thus, the general form of the ester name is alkyl alkanoate. The alkyl group bonded to the oxygen atom in ester and alkanoate is a part of the carbonyl group. ‘alkan’ is the root name and the suffix ‘oate’ is added to the root name for the
(b)
Interpretation:
The structure for the given IUPAC name is to be drawn.
Concept introduction:
In naming ester, the alkyl group is cited first followed by the carboxylate group separated by a space. Thus, the general form of ester name is alkyl alkanoate. The alkyl group bonded to the oxygen atom in ester and alkanoate is a part of carbonyl group. The ‘alkan’ is the root name and the suffix ‘oate’ is added to the root name for the functional group ester. The root name in the IUPAC name ‘alkan’ is derived from the analogous alkane having the same number of carbon atoms. The substituents are attached to the desired carbon number according to the locator in the IUPAC name. The prefix indicates the number of same substituents in the molecule.
(c)
Interpretation:
The structure for the given IUPAC name is to be drawn.
Concept introduction:
In naming ester, the alkyl group is cited first followed by the carboxylate group separated by a space. Thus, the general form ofester name is alkyl alkanoate. The alkyl group bonded to the oxygen atom in ester and alkanoate is a part of carbonyl group. The ‘alkan’ is the root name and the suffix ‘oate’ is added to the root name for the functional group ester. The root name in the IUPAC name ‘alkan’ is derived from the analogous alkane having the same number of carbon atoms. The substituents are attached to the desired carbon number according to the locator in the IUPAC name. The prefix indicates the number of same substituents in the molecule.
Want to see the full answer?
Check out a sample textbook solutionChapter F Solutions
EBK ORGANIC CHEMISTRY: PRINCIPLES AND M
- Draw the structures of the following compounds. (a) tert-pentyl iodidearrow_forwardCiprofloxacin is a member of the fluoroquinolone class of antibiotics.(a) Which of its rings are aromatic?arrow_forward(a) Propose a reasonable synthesis for the formation of nonane from CH3CH2CH2I and any other organic/inorganic reagent. (b) Suggest three (3) different Grignard reactions leading to 2-phenyl-2-butanol.arrow_forward
- Which of the following accurately depicts the resonance for a carbonyl? 可以 (A) (B) 可是… (C) (D) 又一家 贺arrow_forwardGive detailed answer with explanation please don't give Handwritten answerarrow_forward(a) Give an acceptable name for each compound, (b) Draw the organic products formed when A or B is treated with each reagent: [1] H3O+; [2] −OH, H2O; [3] CH3CH2CH2MgBr (excess), then H2O; [4] LiAlH4, then H2O.arrow_forward
- 1. Draw structures corresponding to the following IUPAC names: (a) 4-Methylpentanoic acid (b) o-Hydroxybenzoic acid (c) 2,2-Dimethylpropanoyl chloride (d) trans-2-Methylcyclohexanecarboxamide (e) p-Methylbenzoic anhydride (f) p-Bromobenzonitrilearrow_forwardWrite complete reaction (with structures) for the following reactions: (a) Esterification of ethanoic acid with propanol (b) Reduction of 4-methyl-2-pentanonearrow_forwardDraw structures of the following derivatives.(a) the 2,4-dinitrophenylhydrazone of benzaldehydearrow_forward
- The odor of ripe bananas and many other fruits is due to the presence of esters. For example: Banana oil (isopentyl acetate) (a) Write the name (common or IUPAC) of the ester responsible for the fragrance of the following: pineapple, orange, apple, peach, & lavender (b) Choose one fragrant from (a) and name the alcohol and the carboxylic acid needed to synthesize this ester. (c) Show the detailed mechanism of the Fischer Esterification reaction that will be involved in the synthesis of the fragrant you have chosen in part (a).arrow_forwarda.) Give an acceptable name for compound C. (b) Draw the organicproducts formed when C is treated with each reagent: [1] H3O+; [2] −OH,H2O; [3] CH3CH2CH2MgBr (excess), then H2O; [4] LiAlH4, then H2O.arrow_forwardThe hydrocarbon fluorene was treated with potassium t-butoxide in an acid-base reaction, giving the fluorenide anion and t-butyl alcohol. (a) Which way does the equilibrium lie, and by how much? b) What is the proportion of the fluorenide anion to fluorene? (c) Why is fluorene so highly acidic, considering the pKa of an average alkane is above 50?arrow_forward
- Chemistry for Today: General, Organic, and Bioche...ChemistryISBN:9781305960060Author:Spencer L. Seager, Michael R. Slabaugh, Maren S. HansenPublisher:Cengage Learning