Chapter EP, Problem 6.3.3EP

To determine

To find:

The value of $p\left(5\right),p\left(-1\right)$

Answer to Problem 6.3.3EP

The value of, $p\left(-1\right)=9,p\left(5\right)=3165$

Explanation of Solution

Given:

  $p\left(x\right)=5x^4+2x^2-2x$

Concept:

Using the given value of the function

Calculation:

The function

  $p\left(x\right)=5x^4+2x^2-2x\mathrm{.........}\left(1\right)$

Putting the value $x=5,-1$ in equation (1)

  $\begin{array}{l}p\left(x\right)=5x^4+2x^2-2x\\ p\left(-1\right)=5{\left(-1\right)}^4+2{\left(-1\right)}^2-2\left(-1\right)\\ p\left(-1\right)=5+2+2\\ p\left(-1\right)=9\\ p\left(5\right)=5{\left(5\right)}^4+2{\left(5\right)}^2-2\left(5\right)\\ p\left(5\right)=3125+50-10\\ p\left(5\right)=3165\end{array}$