Chapter EP, Problem 12.6.5EP

To determine

To find: The hypotheses of the function.

Answer to Problem 12.6.5EP

The hypotheses of the function is lie on $17.9195and18.4805$ .

Explanation of Solution

Given information:

The given function $H_0=18,H_1>18$ , $n=125$ , $\stackrel{\leftharpoonup }{X}=18.2$ and $s=1.6$

Calculation:

The expected amount is.

Calculate the function.

$\begin{array}{c}CI=\stackrel{\leftharpoonup }{X}\pm 1.96\frac{S}{\sqrt{n}}\\ =18.2\pm 1.96\frac{1.6}{\sqrt{125}}\\ =18.2\pm 1.96*0.1431\\ =18.2\pm 0.2805\end{array}$

The lower bound of the interval is

$\begin{array}{c}l=18.2\pm 0.2805\\ =17.9195\end{array}$

The upper bound of the interval is

$\begin{array}{c}u=18.2-0.2805\\ =18.4805\end{array}$

Therefore, the hypotheses of the function is lie on $17.9195\text{and}18.4805$ .