Chapter EP, Problem 1.2.3EP

To determine

To find: The set of the numbers to which the given number belongs.

Answer to Problem 1.2.3EP

The number $\sqrt{36}$ belongs to the set $\sqrt{36}\in \left\{N,W,Z,R\right\}$ .

Explanation of Solution

Given:

The number is $\sqrt{36}$ .

Calculation:

The number $\sqrt{36}$ can be written as follows.

  $\begin{array}{c}\sqrt{36}=\sqrt{6\cdot 6}\\ =6\end{array}$

The number 6 is a counting number so it is whole number.

The number 6 is also a natural number.

The number 6 is also a positive integer.

No decimal value is included. So, 6 is not a rational number.

The number 6 has no imaginary part. So, it is also a real number.

Therefore, the number $\sqrt{36}$ belongs to the set $\sqrt{36}\in \left\{N,W,Z,R\right\}$ .