![Organic Chemistry: Principles and Mechanisms (Second Edition)](https://www.bartleby.com/isbn_cover_images/9780393663556/9780393663556_smallCoverImage.jpg)
Concept explainers
(a)
Interpretation:
The IUPAC name for the given compound with appropriate stereochemical designation is to be assigned.
Concept introduction:
In naming organic compounds, the
The stereochemical designation and the locators are enclosed in parenthesis at the very beginning of the name. The stereochemistry at the chiral center is determined by assigning the priorities to the groups attached to the chiral center on the basis of
![Check Mark](/static/check-mark.png)
Answer to Problem E.46P
The name of the given compound is
Explanation of Solution
The given compound is:
In this compound, the highest priority functional group is
The ketonic carbon is numbered as
The fourth group, attached to chiral center
In the order of decreasing sequence rule
The fourth group attached to the chiral center
In the order of decreasing sequence rule,
The fourth group, attached to chiral center
In the order of decreasing sequence rule
Hence the given compound is named as:
The given compound is named by identifying the main chain containing the functional group and the substituents attached with appropriate stereochemistry.
(b)
Interpretation:
The IUPAC name for the given compound with appropriate stereochemical designation is to be assigned.
Concept introduction:
In naming organic compounds, the functional groups other than highest priority functional groups are treated as substituents. The root name is established by identifying the longest carbon chain or a ring containing functional group. Remove the “e” from the normal ‘ane’, ‘ene’, or ‘yne’ ending and add the suffix that corresponds to the highest-priority functional group. Prefixes are used to denote number of identical substituents. Number the carbon chain in a way that the functional group and the substituents attached get the lowest number. The position of functional group and substituents on parent chain or ring is indicated by the respective locant number just before the suffix. The substituents are written in alphabetical order when writing the IUPAC name.
The stereochemical designation and the locators are enclosed in parenthesis at the very beginning of the name. The stereochemistry at the chiral center is determined by assigning the priorities to the groups attached to chiral center on the basis of atomic number of directly bonded atom. If the sequence of priority order
![Check Mark](/static/check-mark.png)
Answer to Problem E.46P
The name of the given compound is:
Explanation of Solution
The given compound is:
In this compound, the main ring is of six carbon atoms containing
The ketonic carbon is numbered
The fourth group attached to the chiral center
In the order of decreasing sequence rule
The fourth group attached to chiral center
In the order of decreasing sequence rule
The fourth group attached to chiral center
In the order of decreasing sequence rule
Hence, the given compound is named as:
The given compound is named by identifying the main chain containing functional group and the substituents attached with appropriate stereochemistry.
(c)
Interpretation:
The IUPAC name for the given compound with appropriate stereochemical designation is to be assigned.
Concept introduction:
In naming organic compounds, the functional groups other than highest priority functional groups are treated as substituents. The root name is established by identifying the longest carbon chain or a ring containing functional group. Remove the “e” from the normal ‘ane’, ‘ene’, or ‘yne’ ending and add the suffix that corresponds to the highest-priority functional group. Prefixes are used to denote number of identical substituents. Number the carbon chain in a way that the functional group and the substituents attached gets lowest number. The position of functional group and substituents on parent chain or ring is indicated by the respective locant number just before the suffix. The substituents are written in alphabetical order when writing the IUPAC name.
The stereochemical designation and the locators are enclosed in parenthesis at the very beginning of the name. The stereochemistry at the chiral center is determined by assigning the priorities to the groups attached to chiral center on the basis of atomic number of directly bonded atom. If the sequence of priority order
![Check Mark](/static/check-mark.png)
Answer to Problem E.46P
The name of given compound is:
Explanation of Solution
The given compound is:
In this compound, the main chain is of seven carbon atoms which indicates the root name as ‘heptane’. The highest priority functional group is ketone. The chain has three carbonyl groups, therefore, the suffix ‘trione’ is added to the root name. The substituents are
The ketonic carbons are numbered as
The fourth group attached to chiral center
In the order of decreasing sequence rule
The fourth group attached to chiral center
In the order of decreasing sequence rule
Hence, the given compound is named as:
The given compound is named by identifying the main chain containing functional group and the substituents attached with appropriate stereochemistry.
Want to see more full solutions like this?
Chapter E Solutions
Organic Chemistry: Principles and Mechanisms (Second Edition)
- This deals with synthetic organic chemistry. Please fill in the blanks appropriately.arrow_forwardUse the References to access important values if needed for this question. What is the IUPAC name of each of the the following? 0 CH3CHCNH₂ CH3 CH3CHCNHCH2CH3 CH3arrow_forwardYou have now performed a liquid-liquid extraction protocol in Experiment 4. In doing so, you manipulated and exploited the acid-base chemistry of one or more of the compounds in your mixture to facilitate their separation into different phases. The key to understanding how liquid- liquid extractions work is by knowing which layer a compound is in, and in what protonation state. The following liquid-liquid extraction is different from the one you performed in Experiment 4, but it uses the same type of logic. Your task is to show how to separate apart Compound A and Compound B. . Complete the following flowchart of a liquid-liquid extraction. Handwritten work is encouraged. • Draw by hand (neatly) only the appropriate organic compound(s) in the boxes. . Specify the reagent(s)/chemicals (name is fine) and concentration as required in Boxes 4 and 5. • Box 7a requires the solvent (name is fine). • Box 7b requires one inorganic compound. • You can neatly complete this assignment by hand and…arrow_forward
- b) Elucidate compound D w) mt at 170 nd shows c-1 stretch at 550cm;' The compound has the ff electronic transitions: 0%o* and no a* 1H NMR Spectrum (CDCl3, 400 MHz) 3.5 3.0 2.5 2.0 1.5 1.0 0.5 ppm 13C{H} NMR Spectrum (CDCl3, 100 MHz) Solvent 80 70 60 50 40 30 20 10 0 ppm ppm ¹H-13C me-HSQC Spectrum ppm (CDCl3, 400 MHz) 5 ¹H-¹H COSY Spectrum (CDCl3, 400 MHz) 0.5 10 3.5 3.0 2.5 2.0 1.5 1.0 10 15 20 20 25 30 30 -35 -1.0 1.5 -2.0 -2.5 3.0 -3.5 0.5 ppm 3.5 3.0 2.5 2.0 1.5 1.0 0.5 ppmarrow_forwardShow work with explanation. don't give Ai generated solutionarrow_forwardRedraw the flowchartarrow_forward
- redraw the flowchart with boxes and molecules written in themarrow_forwardPart I. a) Elucidate the structure of compound A using the following information. • mass spectrum: m+ = 102, m/2=57 312=29 • IR spectrum: 1002.5 % TRANSMITTANCE Ngg 50 40 30 20 90 80 70 60 MICRONS 5 8 9 10 12 13 14 15 16 19 1740 cm M 10 0 4000 3600 3200 2800 2400 2000 1800 1600 13 • CNMR 'H -NMR Peak 8 ppm (H) Integration multiplicity a 1.5 (3H) triplet b 1.3 1.5 (3H) triplet C 2.3 1 (2H) quartet d 4.1 1 (2H) quartet & ppm (c) 10 15 28 60 177 (C=0) b) Elucidate the structure of compound B using the following information 13C/DEPT NMR 150.9 MHz IIL 1400 WAVENUMBERS (CM-1) DEPT-90 DEPT-135 85 80 75 70 65 60 55 50 45 40 35 30 25 20 ppm 1200 1000 800 600 400arrow_forward• Part II. a) Elucidate The structure of compound c w/ molecular formula C10 11202 and the following data below: • IR spectra % TRANSMITTANCE 1002.5 90 80 70 60 50 40 30 20 10 0 4000 3600 3200 2800 2400 2000 1800 1600 • Information from 'HAMR MICRONS 8 9 10 11 14 15 16 19 25 1400 WAVENUMBERS (CM-1) 1200 1000 800 600 400 peak 8 ppm Integration multiplicity a 2.1 1.5 (3H) Singlet b 3.6 1 (2H) singlet с 3.8 1.5 (3H) Singlet d 6.8 1(2H) doublet 7.1 1(2H) doublet Information from 13C-nmR Normal carbon 29ppm Dept 135 Dept -90 + NO peak NO peak 50 ppm 55 ppm + NO peak 114 ppm t 126 ppm No peak NO peak 130 ppm t + 159 ppm No peak NO peak 207 ppm по реак NO peakarrow_forward
- Chemistry for Today: General, Organic, and Bioche...ChemistryISBN:9781305960060Author:Spencer L. Seager, Michael R. Slabaugh, Maren S. HansenPublisher:Cengage Learning
![Text book image](https://www.bartleby.com/isbn_cover_images/9781305080485/9781305080485_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9781305960060/9781305960060_smallCoverImage.gif)