Chapter E, Problem 8.9EX

To determine

To find the value of $\tan n^{°}$ .

Answer to Problem 8.9EX

Option (c)

Explanation of Solution

Given information: $\sin n^{°}=\frac{3}{5}$

Concept used:

In right angles triangle,

$\sin \theta$	$\cos \theta$	$\tan \theta$
P	B	P
H	H	B

Where, P, B and H be the perpendicular, base and hypotenuse of right angled triangle.

By Pythagoras theorem, $B^2+P^2=H^2$

Here, $\sin n^{°}=\frac{3}{5}=\frac{P}{H}$

By Pythagoras theorem, $B^2+P^2=H^2$

  $\begin{array}{l}{B}^2=H^2-P^2\\ B^2=5^2-3^2=16\\ B=4\end{array}$

  $\tan n^{°}=\frac{P}{B}=\frac{3}{4}$

Hence, $\tan n^{°}=\frac{3}{4}$ .