McDougal Littell Jurgensen Geometry: Student Edition Geometry
5th Edition
ISBN: 9780395977279
Author: Ray C. Jurgensen, Richard G. Brown, John W. Jurgensen
Publisher: Houghton Mifflin Company College Division
expand_more
expand_more
format_list_bulleted
Concept explainers
Videos
Question
Chapter E, Problem 5.12EX
To determine
To find of the following must be true for any trapezoid.
Expert Solution & Answer
Answer to Problem 5.12EX
Option (b) At least one
Explanation of Solution
Given information: Options are,
a. Any two consecutive angles are supplementary.
b. At least one angle is obtuse.
c. The diagonals bisect each other.
d. The median bisects each base.
Calculation: The required solutions is obtained as,
We have to note that this only works if the consecutive angle are along the same leg of the trapezoid. However, if they are next to each other along a base, they are not supplementary in a trapezoid.
In a trapezoid, the angles must add up to 360. Each set of two angles along a leg must be equal to 180. However, only one pair can have right angles.
Therefore, option (b) At least one angle is obtuse, is correct.
Chapter E Solutions
McDougal Littell Jurgensen Geometry: Student Edition Geometry
Ch. E - Prob. 1.1EXCh. E - Prob. 1.2EXCh. E - Prob. 1.3EXCh. E - Prob. 1.4EXCh. E - Prob. 1.5EXCh. E - Prob. 1.6EXCh. E - Prob. 1.7EXCh. E - Prob. 1.8EXCh. E - Prob. 1.9EXCh. E - Prob. 1.10EX
Ch. E - Prob. 1.11EXCh. E - Prob. 2.1EXCh. E - Prob. 2.2EXCh. E - Prob. 2.3EXCh. E - Prob. 2.4EXCh. E - Prob. 2.5EXCh. E - Prob. 2.6EXCh. E - Prob. 2.7EXCh. E - Prob. 2.8EXCh. E - Prob. 2.9EXCh. E - Prob. 2.10EXCh. E - Prob. 2.11EXCh. E - Prob. 3.1EXCh. E - Prob. 3.2EXCh. E - Prob. 3.3EXCh. E - Prob. 3.4EXCh. E - Prob. 3.5EXCh. E - Prob. 3.6EXCh. E - Prob. 3.7EXCh. E - Prob. 3.8EXCh. E - Prob. 3.9EXCh. E - Prob. 3.10EXCh. E - Prob. 3.11EXCh. E - Prob. 3.12EXCh. E - Prob. 3.13EXCh. E - Prob. 4.1EXCh. E - Prob. 4.2EXCh. E - Prob. 4.3EXCh. E - Prob. 4.4EXCh. E - Prob. 4.5EXCh. E - Prob. 4.6EXCh. E - Prob. 4.7EXCh. E - Prob. 4.8EXCh. E - Prob. 4.9EXCh. E - Prob. 4.10EXCh. E - Prob. 4.11EXCh. E - Prob. 4.12EXCh. E - Prob. 4.13EXCh. E - Prob. 4.14EXCh. E - Prob. 5.1EXCh. E - Prob. 5.2EXCh. E - Prob. 5.3EXCh. E - Prob. 5.4EXCh. E - Prob. 5.5EXCh. E - Prob. 5.6EXCh. E - Prob. 5.7EXCh. E - Prob. 5.8EXCh. E - Prob. 5.9EXCh. E - Prob. 5.10EXCh. E - Prob. 5.11EXCh. E - Prob. 5.12EXCh. E - Prob. 6.1EXCh. E - Prob. 6.2EXCh. E - Prob. 6.3EXCh. E - Prob. 6.4EXCh. E - Prob. 6.5EXCh. E - Prob. 6.6EXCh. E - Prob. 6.7EXCh. E - Prob. 6.8EXCh. E - Prob. 6.9EXCh. E - Prob. 6.10EXCh. E - Prob. 6.11EXCh. E - Prob. 7.1EXCh. E - Prob. 7.2EXCh. E - Prob. 7.3EXCh. E - Prob. 7.4EXCh. E - Prob. 7.5EXCh. E - Prob. 7.6EXCh. E - Prob. 7.7EXCh. E - Prob. 7.8EXCh. E - Prob. 7.9EXCh. E - Prob. 7.10EXCh. E - Prob. 7.11EXCh. E - Prob. 7.12EXCh. E - Prob. 8.1EXCh. E - Prob. 8.2EXCh. E - Prob. 8.3EXCh. E - Prob. 8.4EXCh. E - Prob. 8.5EXCh. E - Prob. 8.6EXCh. E - Prob. 8.7EXCh. E - Prob. 8.8EXCh. E - Prob. 8.9EXCh. E - Prob. 8.10EXCh. E - Prob. 8.11EXCh. E - Prob. 8.12EXCh. E - Prob. 9.1EXCh. E - Prob. 9.2EXCh. E - Prob. 9.3EXCh. E - Prob. 9.4EXCh. E - Prob. 9.5EXCh. E - Prob. 9.6EXCh. E - Prob. 9.7EXCh. E - Prob. 9.8EXCh. E - Prob. 9.9EXCh. E - Prob. 9.10EXCh. E - Prob. 9.11EXCh. E - Prob. 9.12EXCh. E - Prob. 9.13EXCh. E - Prob. 9.14EXCh. E - Prob. 10.1EXCh. E - Prob. 10.2EXCh. E - Prob. 10.3EXCh. E - Prob. 10.4EXCh. E - Prob. 10.5EXCh. E - Prob. 10.6EXCh. E - Prob. 10.7EXCh. E - Prob. 10.8EXCh. E - Prob. 10.9EXCh. E - Prob. 10.10EXCh. E - Prob. 10.11EXCh. E - Prob. 10.12EXCh. E - Prob. 11.1EXCh. E - Prob. 11.2EXCh. E - Prob. 11.3EXCh. E - Prob. 11.4EXCh. E - Prob. 11.5EXCh. E - Prob. 11.6EXCh. E - Prob. 11.7EXCh. E - Prob. 11.8EXCh. E - Prob. 11.9EXCh. E - Prob. 11.10EXCh. E - Prob. 11.11EXCh. E - Prob. 11.12EXCh. E - Prob. 11.13EXCh. E - Prob. 11.14EXCh. E - Prob. 11.15EXCh. E - Prob. 11.16EXCh. E - Prob. 12.1EXCh. E - Prob. 12.2EXCh. E - Prob. 12.3EXCh. E - Prob. 12.4EXCh. E - Prob. 12.5EXCh. E - Prob. 12.6EXCh. E - Prob. 12.7EXCh. E - Prob. 12.8EXCh. E - Prob. 12.9EXCh. E - Prob. 12.10EXCh. E - Prob. 12.11EXCh. E - Prob. 12.12EXCh. E - Prob. 12.13EXCh. E - Prob. 12.14EXCh. E - Prob. 13.1EXCh. E - Prob. 13.2EXCh. E - Prob. 13.3EXCh. E - Prob. 13.4EXCh. E - Prob. 13.5EXCh. E - Prob. 13.6EXCh. E - Prob. 13.7EXCh. E - Prob. 13.8EXCh. E - Prob. 13.9EXCh. E - Prob. 13.10EXCh. E - Prob. 13.11EXCh. E - Prob. 13.12EXCh. E - Prob. 14.1EXCh. E - Prob. 14.2EXCh. E - Prob. 14.3EXCh. E - Prob. 14.4EXCh. E - Prob. 14.5EXCh. E - Prob. 14.6EXCh. E - Prob. 14.7EXCh. E - Prob. 14.8EXCh. E - Prob. 14.9EX
Additional Math Textbook Solutions
Find more solutions based on key concepts
In Exercises 1-14. evaluate the iterated integral.
11.
University Calculus: Early Transcendentals (4th Edition)
For a population containing N=902 individual, what code number would you assign for a. the first person on the ...
Basic Business Statistics, Student Value Edition
Derivatives involving ln x Find the following derivatives. 11.ddx(lnx2)
Calculus: Early Transcendentals (2nd Edition)
In track, the second lane from the inside of the track is longer than the inside lane. Use this information to ...
A Problem Solving Approach To Mathematics For Elementary School Teachers (13th Edition)
1. Celebrities and the Law Here is a 95% confidence interval estimate of the proportion of adults who say that ...
Elementary Statistics (13th Edition)
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, geometry and related others by exploring similar questions and additional content below.Similar questions
- 3) roadway Calculate the overall length of the conduit run sketched below. 2' Radius 8' 122-62 Sin 30° = 6/H 1309 16.4%. 12' H= 6/s in 30° Year 2 Exercise Book Page 4 10 10 10 fx-300MS S-V.PA Topic 1arrow_forwardWhat is a? And b?arrow_forwardMinistry of Higher Education & Scientific Research Babylon University College of Engineering - Al musayab Automobile Department Subject :Engineering Analysis Time: 2 hour Date:27-11-2022 کورس اول تحليلات تعمیر ) 1st month exam / 1st semester (2022-2023)/11/27 Note: Answer all questions,all questions have same degree. Q1/: Find the following for three only. 1- 4s C-1 (+2-3)2 (219) 3.0 (6+1)) (+3+5) (82+28-3),2- ,3- 2-1 4- Q2/:Determine the Laplace transform of the function t sint. Q3/: Find the Laplace transform of 1, 0≤t<2, -2t+1, 2≤t<3, f(t) = 3t, t-1, 3≤t 5, t≥ 5 Q4: Find the Fourier series corresponding to the function 0 -5arrow_forward3. Construct a triangle in the Poincare plane with all sides equal to ln(2). (Hint: Use the fact that, the circle with center (0,a) and radius ln(r), r>1 in the Poincaré plane is equal to the point set { (x,y) : x^2+(y-1/2(r+1/r)a)^2=1/4(r-1/r)^2a^2 }arrow_forwardn. g. = neutral geometry <ABC = angle ABC \leq = less or equal than sqrt{x} = square root of x cLr = the line in the Poincaré plane defined by the equation (x-c)^2+y^2=r^2 1. Find the bisector of the angle <ABC in the Poincaré plane, where A=(0,5), B=(0,3) and C=(2,\sqrt{21})arrow_forward2. Let l=2L\sqrt{5} and P=(1,2) in the Poincaré plane. Find the uniqe line l' through P such that l' is orthogonal to l.arrow_forwardLet A, B and C be three points in neutral geometry, lying on a circle with center D. If D is in the interior of the triangle ABC, then show that m(<ABC) \leq 1/2m(<ADC).arrow_forwardиз Review the deck below and determine its total square footage (add its deck and backsplash square footage together to get the result). Type your answer in the entry box and click Submit. 126 1/2" 5" backsplash A 158" CL 79" B 26" Type your answer here.arrow_forwardIn the graph below triangle I'J'K' is the image of triangle UK after a dilation. 104Y 9 CO 8 7 6 5 I 4 3 2 J -10 -9 -8 -7 -6 -5 -4 -3 -21 1 2 3 4 5 6 7 8 9 10 2 K -3 -4 K' 5 -6 What is the center of dilation? (0.0) (-5. 2) (-8. 11 (9.-3) 6- 10arrow_forwardSelect all that apply. 104 8 6 4 2 U U' -10 -8 -6 4 -2 2 4 6 10 -2 V' W' -4 -6 -8 -10 W V Select 2 correct answerts! The side lengths are equal in measure. The scale factor is 1/5. The figure has been enlarged in size. The center of dilation is (0.0) 8 10 Xarrow_forwardIn the graph below triangle I'J'K' is the image of triangle UK after a dilation. 104Y 9 CO 8 7 6 5 I 4 3 2 J -10 -9 -8 -7 -6 -5 -4 -3 -21 1 2 3 4 5 6 7 8 9 10 2 K -3 -4 K' 5 -6 What is the center of dilation? (0.0) (-5. 2) (-8. 11 (9.-3) 6- 10arrow_forwardQll consider the problem -abu+bou+cu=f., u=0 ondor I prove atu, ul conts. @ if Blu,v) = (b. 14, U) + ((4,0) prove that B244) = ((c- — ob)4;4) ③if c±vbo prove that acuius v. elliptic.arrow_forwardarrow_back_iosSEE MORE QUESTIONSarrow_forward_ios
Recommended textbooks for you
Elementary Geometry For College Students, 7eGeometryISBN:9781337614085Author:Alexander, Daniel C.; Koeberlein, Geralyn M.Publisher:Cengage,
Elementary Geometry for College StudentsGeometryISBN:9781285195698Author:Daniel C. Alexander, Geralyn M. KoeberleinPublisher:Cengage Learning
Elementary Geometry For College Students, 7e
Geometry
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Cengage,
Elementary Geometry for College Students
Geometry
ISBN:9781285195698
Author:Daniel C. Alexander, Geralyn M. Koeberlein
Publisher:Cengage Learning
01 - Angles and Angle Measure in Degrees - Part 1 - Types of Angles & What is an Angle?; Author: Math and Science;https://www.youtube.com/watch?v=hy95VyPet-M;License: Standard YouTube License, CC-BY