Chapter E, Problem 8.1EX

To determine

To find the length of hypotenuse of right triangle.

Answer to Problem 8.1EX

Option (a)

Explanation of Solution

Given information: A right triangle with shorter side has length 7 units.

Concept used:

In right angles triangle,

$\sin \theta$	$\cos \theta$	$\tan \theta$
P	B	P
H	H	B

Where, P, B and H be the perpendicular, base and hypotenuse of right angled triangle.

By Pythagoras theorem, $B^2+P^2=H^2$

Since base is the smallest side of the right angle triangle.

  $\begin{array}{l}\cos {60}^{°}=\frac{B}{H}\\ \frac{1}{2}=\frac{7}{H}\\ H=14\end{array}$

Hence, the length of the hypotenuse is 14 units.