Chapter E, Problem 12.5EX

To determine

To find the lateral area of the pyramid with edge 16 and height 6.

Answer to Problem 12.5EX

Option (b)

Explanation of Solution

Given information: The side and the height of the regular square pyramid is 16 and 6 respectively.

Concept used:

  $\text{Lateral}\text{area of the}\text{pyramid}=\frac{1}{2}\times \text{perimeter}\times \text{slant}\text{height}$

Here, slant height = $l=\sqrt{8^2+6^2}=10$

  $\text{Lateral}\text{area of the}\text{pyramid}=\frac{1}{2}\times \text{perimeter}\times \text{slant}\text{height}\text{=}\frac{1}{2}\times 4\times 16\times 10=320$

Hence, the lateral area of the pyramid is 320 square units.