Organic Chemistry: Principles And Mechanisms: Study Guide/solutions Manual (second)
Organic Chemistry: Principles And Mechanisms: Study Guide/solutions Manual (second)
2nd Edition
ISBN: 9780393655551
Author: KARTY, Joel
Publisher: W. W. Norton & Company
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Chapter B, Problem B.2P
Interpretation Introduction

(a)

Interpretation:

The numbering system for the given molecule is to be determined.

Concept introduction:

In case of molecules containing a C=C  or CC bond, the longest continuous carbon chain or largest ring that contains the double or triple bond is considered as the root. It is possible that the longest carbon chain has more carbons than specified by the root. But the double or triple bond must be a part of the root. The root is named from the name of the analogous alkane or cycloalkane by replacing the suffix ane by ene if a double bond is present. The suffix ane is replaced by yne if a triple bond is present.

If the root is a chain, the numbering begins from that end of the chain, which encounters the C=C  or CC bond at the earliest. If there is a tie, then the chain is numbered such that the substituents get the lowest locator numbers.

If the root is a ring, then the double or triple bonded carbon atoms are always numbered as C1 and C2. This must be done such that the locator numbers for the substituents are minimized.

Interpretation Introduction

(b)

Interpretation:

The numbering system for the given molecule is to be determined.

Concept introduction:

In case of molecules containing a C=C  or CC bond, the longest continuous carbon chain or largest ring that contains the double or triple bond is considered as the root. It is possible that the longest carbon chain has more carbons than specified by the root. But the double or triple bond must be a part of the root. The root is named from the name of the analogous alkane or cycloalkane by replacing the suffix ane by ene if a double bond is present. The suffix ane is replaced by yne if a triple bond is present.

If the root is a chain, the numbering begins from that end of the chain, which encounters the C=C  or CC bond at the earliest. If there is a tie, then the chain is numbered such that the substituents get the lowest locator numbers.

If the root is a ring, then the double or triple bonded carbon atoms are always numbered as C1 and C2. This must be done such that the locator numbers for the substituents are minimized.

Interpretation Introduction

(c)

Interpretation:

The numbering system for the given molecule is to be determined.

Concept introduction:

In case of molecules containing a C=C  or CC bond, the longest continuous carbon chain or largest ring that contains the double or triple bond is considered as the root. It is possible that the longest carbon chain has more carbons than specified by the root. But the double or triple bond must be a part of the root. The root is named from the name of the analogous alkane or cycloalkane by replacing the suffix ane by ene if a double bond is present. The suffix ane is replaced by yne if a triple bond is present.

If the root is a chain, the numbering begins from that end of the chain, which encounters the C=C  or CC bond at the earliest. If there is a tie, then the chain is numbered such that the substituents get the lowest locator numbers.

If the root is a ring, then the double or triple bonded carbon atoms are always numbered as C1 and C2. This must be done such that the locator numbers for the substituents are minimized.

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1. Calculate the accurate monoisotopic mass (using all 1H, 12C, 14N, 160 and 35CI) for your product using the table in your lab manual. Don't include the Cl, since you should only have [M+H]*. Compare this to the value you see on the LC-MS printout. How much different are they? 2. There are four isotopic peaks for the [M+H]* ion at m/z 240, 241, 242 and 243. For one point of extra credit, explain what each of these is and why they are present. 3. There is a fragment ion at m/z 184. For one point of extra credit, identify this fragment and confirm by calculating the accurate monoisotopic mass. 4. The UV spectrum is also at the bottom of your printout. For one point of extra credit, look up the UV spectrum of bupropion on Google Images and compare to your spectrum. Do they match? Cite your source. 5. For most of you, there will be a second chromatographic peak whose m/z is 74 (to a round number). For one point of extra credit, see if you can identify this molecule as well and confirm by…
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can you draw each step on a piece of a paper please this is very confusing to me
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