Precalculus Enhanced with Graphing Utilities
Precalculus Enhanced with Graphing Utilities
6th Edition
ISBN: 9780321795465
Author: Michael Sullivan, Michael III Sullivan
Publisher: PEARSON
Question
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Chapter A.8, Problem 52AYU
To determine

To find: How fast is each cyclist riding?

Expert Solution & Answer
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Answer to Problem 52AYU

Cycle riding is 23 miles fast.

Explanation of Solution

Given:

Two cyclists leave a city a city at the same time, one going east and the other going west. The westbound cyclist bikes 5 mph faster than the eastbound cyclist. After 6 hours they are 246 miles apart.

Calculation:

West bound:

Rate = x + 5 mph; time = 6 hours; distance = 6( x + 5 ) = 6x + 30 miles.

East bound:

Rate = x mph; time = 6 hours; distance = 6x miles.

Equation:

Distance + Distance = 246 miles

6x + 30 + 6x = 246

12x = 216

x = 18

Therefore x + 5 = 23 mph.

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