To find:
a. If the length of the garden is to be twice its width, what will be the dimensions of the garden?
Answer to Problem 35AYU
a. The dimensions are 10 ft by 5 ft.
Explanation of Solution
Given:
A gardener has 46 feet of fencing to be used to enclose a rectangular garden that has a border 2 feet wide surrounding it.
Calculation:
a. Length of the garden is to be twice its width.
So, .
Therefore width is 5 and length is 10.
To find:
b. What will be the area of the garden?
Answer to Problem 35AYU
b. The area is 50 sq.ft.
Explanation of Solution
Given:
A gardener has 46 feet of fencing to be used to enclose a rectangular garden that has a border 2 feet wide surrounding it.
Calculation:
b. The area = (width)(length) .
To find:
c. If the length and width of then garden are to be the same, what will be the dimensions of the garden?
Answer to Problem 35AYU
c. The dimensions would be by .
Explanation of Solution
Given:
A gardener has 46 feet of fencing to be used to enclose a rectangular garden that has a border 2 feet wide surrounding it.
Calculation:
c. The dimensions of the garden length and width are same.
Therefore, the dimensions would be by .
To find:
d. What will be the area of the square garden?
Answer to Problem 35AYU
d. The area would be .
Explanation of Solution
Given:
A gardener has 46 feet of fencing to be used to enclose a rectangular garden that has a border 2 feet wide surrounding it.
Calculation:
d. The area of square is .
Chapter A.8 Solutions
Precalculus Enhanced with Graphing Utilities
Additional Math Textbook Solutions
Thomas' Calculus: Early Transcendentals (14th Edition)
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (4th Edition)
Calculus, Single Variable: Early Transcendentals (3rd Edition)
Calculus & Its Applications (14th Edition)
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