Chapter A.8, Problem 31AYU

To determine

To find: Determine the dimensions of the court.

Answer to Problem 31AYU

The double tennis court is 78 feet long and 36 feet width.

Explanation of Solution

Given:

A regulation doubles tennis court has an area of 2808 square feet. If it is 6 feet longer than twice its width.

Calculation:

$2808=\left(2w+6\right)w$

$2w^2+6w-2808=0$

Therefore the positive root of $w=36$.

So the length is 78 and width is 36.

That is the double tennis court is 78 feet long and 36 feet width.