Chapter A.8, Problem 28AYU

To determine

To find: Two cars enter the Florida Turnpike at Commercial Boulevard at 8:00 AM, each heading for Wildwood. One car’s average speed is 10 miles per hour more than the other’s. The faster car arrives at 11:00 AM, $\frac{1}{2}$ hour before the other car. What was the average speed of each car? How far did each travel?

Answer to Problem 28AYU

60 mph is the speed of the slower car, 70 mph is the speed of the faster car and travels 210 miles.

Explanation of Solution

$3\left(x+10\right)=3.5x$

$3x+30=3.5x$

$30=0.5x$

$x=60\text{mph}$ is the speed of the slower car.

Then $60+10=70\text{mph}$ is the speed of the faster car.

Therefore, distance $=3*70=210 \text{miles}$.