EBK ORGANIC CHEMISTRY: PRINCIPLES AND M
EBK ORGANIC CHEMISTRY: PRINCIPLES AND M
2nd Edition
ISBN: 9780393630817
Author: KARTY
Publisher: W.W.NORTON+CO. (CC)
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Chapter A, Problem A.46P
Interpretation Introduction

(a)

Interpretation:

The IUPAC name of the given molecule is to be written.

Concept introduction:

The root name of the molecule is the name of the alkane, which depends on the longest continuous chain of carbon atoms or the ring structure. The name of the substituent attached to the parent ring is written as a prefix to the left side of the root. The parent ring is numbered such that the carbon atom to which the substituent is attached gets the lowest possible number. This number is written on the left side of the substituent and separated by a hyphen. If more than one substituent is present, then the numbering is determined by the alphabetical order of substituents.

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Answer to Problem A.46P

The IUPAC name of the given molecule is 2, 3-dinitropentane.

Explanation of Solution

The given molecule is

EBK ORGANIC CHEMISTRY: PRINCIPLES AND M, Chapter A, Problem A.46P , additional homework tip  1

In this molecule, the longest continuous chain of carbon atoms has five carbon atoms. Hence, the root is pentane. The parent chain has two identical substituents; thus the chain is numbered so as to provide the lowest set of locants.

EBK ORGANIC CHEMISTRY: PRINCIPLES AND M, Chapter A, Problem A.46P , additional homework tip  2

Hence, the IUPAC name is 2, 3-dinitropentane.

Conclusion

The IUPAC name of the given molecule is written as 2, 3-dinitropentane, using the root, prefix, and locator number.

Interpretation Introduction

(b)

Interpretation:

The IUPAC name of the given molecule is to be written.

Concept introduction:

The root name of the molecule is the name of the alkane, which depends on the longest continuous chain of carbon atoms. The name of the substituent attached to the parent chain is written as a prefix to the left side of the root. The chain is numbered such that the carbon atom to which the substituent is attached gets the lowest possible number. This number is written on the left side of the substituent and separated by a hyphen. If more than one substituent is present, then the numbering is determined by the alphabetical order of substituents.

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Answer to Problem A.46P

The IUPAC name of the given molecule is 2, 2-diiodo-5-nitrohexane.

Explanation of Solution

The given molecule is

EBK ORGANIC CHEMISTRY: PRINCIPLES AND M, Chapter A, Problem A.46P , additional homework tip  3

In this molecule, the longest continuous chain of carbon atoms has six carbon atoms. Hence, the root is hexane. The parent chain has three substituents; thus the chain is numbered so as to provide the lowest set of locants.

EBK ORGANIC CHEMISTRY: PRINCIPLES AND M, Chapter A, Problem A.46P , additional homework tip  4

The substituents are arranged in an alphabetical order with respective locant.

Hence, the IUPAC name is 2, 2-diiodo-5-nitrohexane.

Conclusion

The IUPAC name of the given molecule is written as 2, 2-diiodo-5-nitrohexane, using the root, prefix, and locator number.

Interpretation Introduction

(c)

Interpretation:

The IUPAC name of the given molecule is to be written.

Concept introduction:

The root name of the molecule is the name of the alkane, which depends on the longest continuous chain of carbon atoms. The name of the substituent attached to the parent chain is written as a prefix to the left side of the root. The chain is numbered such that the carbon atom to which the substituent is attached gets the lowest possible number. This number is written on the left side of the substituent and separated by a hyphen. If more than one substituent is present, then the numbering is determined by the alphabetical order of substituents.

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Answer to Problem A.46P

The IUPAC name of the given molecule is 1, 2-dichloro-1-methylcyclopentane.

Explanation of Solution

The given molecule is

EBK ORGANIC CHEMISTRY: PRINCIPLES AND M, Chapter A, Problem A.46P , additional homework tip  5

In this molecule, the five carbons ring is a parent. Hence, the root is cyclopentane. The ring has three substituents; thus, the ring is numbered so as to provide the lowest set of locants.

EBK ORGANIC CHEMISTRY: PRINCIPLES AND M, Chapter A, Problem A.46P , additional homework tip  6

The substituents are arranged in alphabetical order with respective locant.

Hence, the IUPAC name is 1, 2-dichloro-1-methylcyclopentane.

Conclusion

The IUPAC name of the given molecule is written as 1, 2-dichloro-1-methylcyclopentane, using the root, prefix, and locator number.

Interpretation Introduction

(d)

Interpretation:

The IUPAC name of the given molecule is to be written.

Concept introduction:

The root name of the molecule is the name of the alkane, which depends on the longest continuous chain of carbon atoms or the ring structure. The name of the substituent attached to the parent ring is written as a prefix to the left side of the root. The parent ring is numbered such that the carbon atom to which the substituent is attached gets the lowest possible number. This number is written on the left side of the substituent and separated by a hyphen. If more than one substituent is present, then the numbering is determined by the alphabetical order of substituents.

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Answer to Problem A.46P

The IUPAC name of the given molecule is 3, 4-dibromo-1, 2-dimethoxypentane.

Explanation of Solution

The given molecule is

EBK ORGANIC CHEMISTRY: PRINCIPLES AND M, Chapter A, Problem A.46P , additional homework tip  7

In this molecule, the five carbons ring is a parent. Hence, the root is cyclopentane. The parent chain has four substituents; thus, the chain is numbered so as to provide the lowest set of locants according to alphabetical order.

EBK ORGANIC CHEMISTRY: PRINCIPLES AND M, Chapter A, Problem A.46P , additional homework tip  8

The substituents are arranged in alphabetical order with respective locant.

Hence, the IUPAC name is 3, 4-dibromo-1, 2-dimethoxypentane.

Conclusion

The IUPAC name of the given molecule is written as 3, 4-dibromo-1, 2-dimethoxypentane, using the root, prefix, and locator number.

Interpretation Introduction

(e)

Interpretation:

The IUPAC name of the given molecule is to be written.

Concept introduction:

The root name of the molecule is the name of the alkane, which depends on the longest continuous chain of carbon atoms. The name of the substituent attached to the parent chain is written as a prefix to the left side of the root. The chain is numbered such that the carbon atom to which the substituent is attached gets the lowest possible number. This number is written on the left side of the substituent and separated by a hyphen. If more than one substituent is present, then the numbering is determined by the alphabetical order of substituents.

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Answer to Problem A.46P

The IUPAC name of the given molecule is 1, 1, 4, 4-tetrabromopentane.

Explanation of Solution

The given molecule is

EBK ORGANIC CHEMISTRY: PRINCIPLES AND M, Chapter A, Problem A.46P , additional homework tip  9

In this molecule, the five carbons ring is a parent. Hence, the root is cyclopentane. The parent chain has four identical substituents; thus, the chain is numbered so as to provide the lowest set of locants according to alphabetical order.

EBK ORGANIC CHEMISTRY: PRINCIPLES AND M, Chapter A, Problem A.46P , additional homework tip  10

Hence, the IUPAC name is 1, 1, 4, 4-tetrabromopentane.

Conclusion

The IUPAC name of the given molecule is written as 1, 1, 4, 4-tetrabromopentane, using the root, prefix, and locator number.

Interpretation Introduction

(f)

Interpretation:

The IUPAC name of the given molecule is to be written.

Concept introduction:

The root name of the molecule is the name of the alkane, which depends on the longest continuous chain of carbon atoms or the ring structure. The name of the substituent attached to the parent ring is written as a prefix to the left side of the root. The parent ring is numbered such that the carbon atom to which the substituent is attached gets the lowest possible number. This number is written on the left side of the substituent and separated by a hyphen. If more than one substituent is present, then the numbering is determined by the alphabetical order of substituents in a way to provide the lowest set of locants.

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Answer to Problem A.46P

The IUPAC name of the given molecule is 1, 1, 2-trinitrocyclobutane.

Explanation of Solution

The given molecule is

EBK ORGANIC CHEMISTRY: PRINCIPLES AND M, Chapter A, Problem A.46P , additional homework tip  11

In this molecule, the four carbons ring is a parent. Hence, the root is cyclobutane. The ring has three identical substituents; thus, the ring is numbered so as to provide the lowest set of locants.

EBK ORGANIC CHEMISTRY: PRINCIPLES AND M, Chapter A, Problem A.46P , additional homework tip  12

Hence, the IUPAC name is 1, 1, 2-trinitrocyclobutane.

Conclusion

The IUPAC name of the given molecule is written as 1, 1, 2-trinitrocyclobutane, using the root, prefix, and locator number.

Interpretation Introduction

(g)

Interpretation:

The IUPAC name of the given molecule is to be written.

Concept introduction:

The root name of the molecule is the name of the alkane, which depends on the longest continuous chain of carbon atoms or the ring structure. The name of the substituent attached to the parent ring is written as a prefix to the left side of the root. The parent ring is numbered such that the carbon atom to which the substituent is attached gets the lowest possible number. This number is written on the left side of the substituent and separated by a hyphen. If more than one substituent is present, then the numbering is determined by the alphabetical order of substituents.

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Answer to Problem A.46P

The IUPAC name of the given molecule is 1-cyclobutyl-2-fluorocyclopentane.

Explanation of Solution

The given molecule is

EBK ORGANIC CHEMISTRY: PRINCIPLES AND M, Chapter A, Problem A.46P , additional homework tip  13

In this molecule, the five carbons ring is a parent. Hence, the root is cyclopentane. The ring has two substituents; thus, the ring is numbered so as to provide the lowest set of locants according to alphabetical order.

EBK ORGANIC CHEMISTRY: PRINCIPLES AND M, Chapter A, Problem A.46P , additional homework tip  14

The substituents are arranged in alphabetical order with respective locant.

Hence, the IUPAC name is 1-cyclobutyl-2-fluorocyclopentane.

Conclusion

The IUPAC name of the given molecule is written as 1-cyclobutyl-2-fluorocyclopentane, using the root, prefix, and locator number.

Interpretation Introduction

(h)

Interpretation:

The IUPAC name of the given molecule is to be written.

Concept introduction:

The root name of the molecule is the name of the alkane, which depends on the longest continuous chain of carbon atoms. The name of the substituent attached to the parent chain is written as a prefix to the left side of the root. The chain is numbered such that the carbon atom to which the substituent is attached gets the lowest possible number. This number is written on the left side of the substituent and separated by a hyphen. If more than one substituent is present, then the numbering is determined by the alphabetical order of substituents.

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Answer to Problem A.46P

The IUPAC name of the given molecule is 2, 2, 3, 3, 4, 4-hexafluoropentane.

Explanation of Solution

The given molecule is

EBK ORGANIC CHEMISTRY: PRINCIPLES AND M, Chapter A, Problem A.46P , additional homework tip  15

In this molecule, the longest continuous chain of carbon atoms has five carbon atoms. Hence, the root is pentane. The parent chain has six identical substituents; thus, the chain is numbered so as to provide the lowest set of locants.

EBK ORGANIC CHEMISTRY: PRINCIPLES AND M, Chapter A, Problem A.46P , additional homework tip  16

Hence, the IUPAC name is 2, 2, 3, 3, 4, 4-hexafluoropentane.

Conclusion

The IUPAC name of the given molecule is written as 2, 2, 3, 3, 4, 4-hexafluoropentane, using the root, prefix, and locator number.

Interpretation Introduction

(i)

Interpretation:

The IUPAC name of the given molecule is to be written.

Concept introduction:

The root name of the molecule is the name of the alkane, which depends on the longest continuous chain of carbon atoms. The name of the substituent attached to the parent chain is written as a prefix to the left side of the root. The chain is numbered such that the carbon atom to which the substituent is attached gets the lowest possible number. This number is written on the left side of the substituent and separated by a hyphen. If more than one substituent is present, then the numbering is determined by the alphabetical order of substituents.

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Answer to Problem A.46P

The IUPAC name of the given molecule is 1, 1, 1, 2-tetrabromo-2-cyclopropylethane.

Explanation of Solution

The given molecule is

EBK ORGANIC CHEMISTRY: PRINCIPLES AND M, Chapter A, Problem A.46P , additional homework tip  17

In this molecule, the longest continuous chain of carbon atoms has two carbon atoms. Hence, the root is ethane. The parent chain has five substituents; thus, the chain is numbered so as to provide the lowest set of locants.

EBK ORGANIC CHEMISTRY: PRINCIPLES AND M, Chapter A, Problem A.46P , additional homework tip  18

The substituents are arranged in alphabetical order with respective locant.

Hence, the IUPAC name is 1, 1, 1, 2-tetrabromo-2-cyclopropylethane.

Conclusion

The IUPAC name of the given molecule is written as 1, 1, 1, 2-tetrabromo-2-cyclopropylethane, using the root, prefix, and locator number.

Interpretation Introduction

(j)

Interpretation:

The IUPAC name of the given molecule is to be written.

Concept introduction:

The root name of the molecule is the name of the alkane, which depends on the longest continuous chain of carbon atoms. The name of the substituent attached to the parent chain is written as a prefix to the left side of the root. The chain is numbered such that the carbon atom to which the substituent is attached gets the lowest possible number. This number is written on the left side of the substituent and separated by a hyphen. If more than one substituent is present, then the numbering is determined by the alphabetical order of substituents.

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Answer to Problem A.46P

The IUPAC name of the given molecule is 1, 2, 3-tricyclopropoxycyclopropane.

Explanation of Solution

The given molecule is

EBK ORGANIC CHEMISTRY: PRINCIPLES AND M, Chapter A, Problem A.46P , additional homework tip  19

In this molecule, the middle ring of three carbons is a parent. Hence, the root is cyclopropane. The ring has three identical substituents.

EBK ORGANIC CHEMISTRY: PRINCIPLES AND M, Chapter A, Problem A.46P , additional homework tip  20

Hence, the IUPAC name is 1, 2, 3-tricyclopropoxycyclopropane.

Conclusion

The IUPAC name of the given molecule is written as 1, 2, 3-tricyclopropoxycyclopropane, using the root, prefix, and locator number.

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