Chapter 9.9, Problem 14PPS

To determine

Solve the function.

Answer to Problem 14PPS

  $-x^2-2^x+7$

Explanation of Solution

Given Information: $f\left(x\right)=-x^2+9$ , $g\left(x\right)=2^x+2$ and $h\left(x\right)=3x^2-6x-9$

Formula Used: $\left(f-g\right)\left(x\right)=f(x)-g\left(x\right)$

Calculation:

  $f\left(x\right)=-x^2+9$ , $g\left(x\right)=2^x+2$ and $h\left(x\right)=3x^2-6x-9$

Now, Use formula

  $\left(f-g\right)\left(x\right)=f(x)-g\left(x\right)$

Now, put the value of $f(x)$ and $g(x)$

  $\left(f-g\right)\left(x\right)=-x^2+9-2^x-2$

Hence,

  $\left(f-g\right)\left(x\right)=-x^2-2^x+7$