Chapter 9.4, Problem 43PPS

To determine

Find the distance.

Answer to Problem 43PPS

  $d=20$

Explanation of Solution

Given Information: Area = $100f{t}^2$ and Area = $0.25d^2$

Calculation:

Area = $100f{t}^2$ and Area = $0.25d^2$

Now,

  $100=0.25d^2$

So,

  $d^2=\frac{100}{0.25}$

Now, simplify

  $d^2=400$

As square root of 400 is 20.

  $d^2={20}^2$

Hence,

  $d=20$