
(a)
To find: the polar equation of the orbit of a planet
(a)

Answer to Problem 63E
The polar equation of the orbit of a planet Neptune is
The planet Pluto is
Explanation of Solution
Given:
Calculation:
For Neptune: Use the equation given values.
For Pluto: Use the equation given values.
Conclusion:
Therefore, the polar equation of the orbit of a planet Neptune is
(b)
To find: the perihelion and aphelion distances for each planet.
(b)

Answer to Problem 63E
The perihelion and aphelion distances of Neptune planet is
Explanation of Solution
Calculation:
For Neptune: Use the formula from exercise 49 to find the perihelion.
For Pluto: Use the formula from exercise 49 to find the perihelion.
Conclusion:
Therefore, the perihelion and aphelion distances of Neptune planet is
(c)
To graph: Neptune’s and Pluto’s equations of orbit
(c)

Answer to Problem 63E
Explanation of Solution
Calculation:
Graph the equations for the orbits of both planets.
Red: Neptune
Blue: Pluto
Conclusion:
Therefore, the equation is drawn.
(d)
To prove: the Pluto called the ninth planet and Neptune the eighth planet.
(d)

Answer to Problem 63E
On average, Pluto is farther from the sun than Neptune is.
Explanation of Solution
Pluto's perihelion is less than Neptune's perihelion and aphelion, so there is a point at which Pluto is closer to the sun than Neptune is. On average, Pluto is farther from the sun than Neptune is.
Conclusion:
Therefore, On average, Pluto is farther from the sun than Neptune is.
(e)
To explain: whether the orbits of Neptune and Pluto intersect and collide.
(e)

Answer to Problem 63E
Pluto and Neptune will not collide.
Explanation of Solution
Pluto and Neptune will not collide. Even though the graph in part c shows that their orbits intersect, it does not show what happens in three-dimensional space.
Conclusion:
Therefore, Pluto and Neptune will not collide.
Chapter 9 Solutions
Precalculus with Limits: A Graphing Approach
- Ra X 2) slots per pole per phase 3/31 180 Ko Sin (1) Kdl 1 sin (4) sin(3) Sin (30) اذا مرید شرح الكتب بس 0 بالفراغ 3) Cos (30) 0.866 4) Rotating 5) Synchronous speed, 120 Fo lasa! G s.1000-950 20:05 1000 Capper losses: 5kw Rotor input lookw 0.05 ined sove in peaper I need a detailed solution on paper please 6) 1 ۳/۱ وه اذا ميريد شرح الكتب فقط look DC 7) rotov Find the general solution of the following equations: +4y=tan2x 3 7357 Find the general solution of the following equations: - Qll y + y (³) = 0. 101arrow_forwardB: 18060 msl Kd Ka, Sin (n) I sin () sin(30) Sin (30) اذا ميريد شرح الكتب بس 0 بالفراغ 3) Cos (30) 0.866 4) Rotating 5) Synchronous speed, 120 x 50 G 5005 1000 s = 1000-950 Copper bosses 5kW /0001 Rotor input 5 : loo kw 0.05 6) 1 اذا ميريد شرح الكتب فقط ١٥٠ 7) rotov DC ined sove in Deaper I need a detailed solution on paper please dy x+2y-4 = dx 2x-y-3 Find the general solution of the following equations: 02//yl-4y+13y=esinarrow_forward1) R₂ = X2 2) slots per pole per phase = 3/31 B msl kd 180 60 Kal Sin (1) I sin () sin(30) Sin (30) اذا ميريد شرح الكتب بس 0 بالفراغ 3) Cos (30) 0.866 4) Rotating 5) Synchronous speed, 120 x 50 G 5005 1000 s = 1000-950 Copper bosses 5kW Rotor input: 5 0.05 loo kw 6) 1 /0001 اذا ميريد شرح الكتب فقط look 7) rotov DC ined sove in peaper I need a detailed solution on paper please Q1// Find the solution of: 'y' = x² +376 x4+316 xyo Q2 Find the solution of the initial-valued problems: ex-y y' +exarrow_forward
- R₂ = X2 2) slots per pole per phase = 3/31 B-18060 msl kd Kasi Sin (1) I sin (6) sin(30) Sin (30) اذا ميريد شرح الكتب بس 0 بالفراغ 3) Cos (30) 0.866 4) Rotating 5) Synchronous speed s = 1000-950 1000 Copper losses: 5kw Rotor input 5 0.05 6) 1 120 x 50 G loo kw ined sove in peaper I need a detailed solution on paper please Q3// x²y// +xy/ + (x² - ½) y = x³/². اذا ميريد شرح الكتب فقط look 7) rotor DC Q4// x²y// - (2x+x²)y/ + (2 + x)y = x³. dy 2x+2y+4 = dx 2x-y-3arrow_forward۳/۱ R2X2 2) slots per pole per phase = 3/31 B, 18060 msl Kas Sin() 1sin() sin(30) Sin (30) kd اذا ميريد شرح الكتب بس 0 بالفراغ 3) Cos (30) 0.866 4) Rotating 5) Synchronous speeds S = 1000-950 1000 Copper bosses 5kw 120*50 loca G Rotor input 5 loo kw 6) 1 0.05 اذا ميريد شرح الكتب فقط lookw 7) rotor DC ined sove in peaper I need a detailed solution on paper please 064 Q1// Find the solution of QI/Find the solution of Inxy= 7357 x+2y³ y' = xy3arrow_forwardR₂ = X2 2) slots per pole per phase 3/31 msl 180 60 Kd Ka Sin (1) Isin (6) sin(30) Sin (30) اذا ميريد شرح الكتب بس 0 بالفراغ 3) Cos (30) 0.866 4) Rotating 5) Synchronous speed, 120*50 1000 6 S = 1000-950 1000 Copper bosses: 5kw Rotor input 5 0.05 : loo kw 6) 1 اذا ميريد شرح الكتب فقط 100 7) rotor DC ined sove in peaper I need a detailed solution on paper please Find the general solution of the following equations: Q2lyl-4y+13y=esinx. Find the general solution of the following equations: " Qly (49) - 16y= 0. 151arrow_forward
- ۳/۱ R₂ = X2 2) slots per pole per phase = 3/31 B-18060 msl kd Kasi Sin (1) I sin (6) sin(30) Sin (30) اذا ميريد شرح الكتب بس 0 بالفراغ 3) Cos (30) 0.866 4) Rotating 5) Synchronous speed s = 1000-950 1000 Copper losses: 5kw Rotor input 5 0.05 6) 1 120 x 50 G loo kw اذا میرید شرح الكتب فقط look 7) rotor DC ined sove in peaper I need a detailed solution on paper dy please 04 12=-cosx.y + 2cosx with y(x) = 1 か 'Oy + xlny + xe")dx + (xsiny + xlnx +*dy=0. 01arrow_forward٣/١ R2X2 2) slots per pole per phase = 3/31 B, 18060 msl kd Kas Sin (1) 1sin() sin(30) Sin (30) اذا ميريد شرح الكتب بس 0 بالفراغ 3) Cos (30) 0.866 4) Rotating 5) Synchronous speeds S = 1000-950 1000 Copper bosses 5kw 120*50 loca G Rotor input 5 loo kw 0.05 6) 1 اذا ميريد شرح الكتب فقط lookw 7) rotor ined sove in peaper I need a detailed solution on paper please DC 口 04 on its wheels as shown in figure. The the door is 8 m below the free surface o is located at the center of the d no water leaks an accident and lands at the bottom of the lake 12m high and I m wide, and the top edge of water Determine the hydrostatic force on the discuss if the driver can open the door, if ong person can lift 100 kg, the passenger The door can be approximated as a vertical rec | 279|-|(23+2+12+20=2) AA Find the general solution of the following equations: 11 - 1/4+xy/-(1-x²³)= 0. 2arrow_forward۳/۱ : +0 العنوان I need a detailed drawing with explanation R₂ = X2 2) slots per pole per phase 3/31 Le msl 180 60 Kd Ka Sin (1) Isin (6) sin(30) Sin (30) اذا ميريد شرح الكتب بس 0 بالفراغ 3) Cos (30) 0.866 4) Rotating 5) Synchronous speed, 120*50 1000 6 S = 1000-950 1000 Copper bosses: 5kw Rotor input 5 loo kw 0.05 6) 1 اذا ميريد شرح الكتب فقط ١٥٠ 7) rotov DC ined sove in peaper I need a detailed solution on paper please 064 Q1// Find the solution of: ( texty Q1// Find the solution of: '' y' -2y= 22% √y³arrow_forward
- R2X2 2) slots per pole per phase = 3/31 B-180-60 msl kd Ka, Sin (1) I sin (6) sin(30) Sin (30) اذا ميريد شرح الكتب بس 0 بالفراغ 3) Cos (30) 0.866 4) Rotating 5) Synchronous speed s = 1000-950 1000 Copper losses 5kw 120 50 G Rotor input 5 loo kw 6) 1 ۳/۱ 0.05 إذا ميريد شرح الكتب فقط look 7) rotov DC ined sove in peaper I need a detailed solution on paper please Find the general solution of the following equations: " yll + 4y = tan2x. Find the general solution of the following equations: 01-24+7=0 T el [A] G ха =T Marrow_forwardR₂ = X2 2) slots per pole per phase = 3/31 B-18060 msl kd Kasi Sin (1) I sin (6) sin(30) Sin (30) اذا ميريد شرح الكتب بس 0 بالفراغ 3) Cos (30) 0.866 4) Rotating 5) Synchronous speed s = 1000-950 1000 Copper losses: 5kw Rotor input 5 0.05 6) 1 120 x 50 G loo kw اذا میرید شرح الكتب فقط look 7) rotor DC ined sove in peaper I need a detailed solution on paper please 0 64 Solve the following equations: = dx x²+y2 with y(0) = 1. 7357 Solve the following equations: dy x³+3xy² Q1// = dx 3x²y+y³° 01arrow_forward٣/١ R2X2 2) slots per pole per phase = 3/3 1 B18060 msl Kd 3 Kol Sin (1) 1sin() sin(30) Sin (30) اذا میرید شرح الكتب بس 0 بالفراغ 3) cos (30) 0.866 4) Rotating 5) Synchronous speeds 120*50 G looo 1000-950 1000 50:05 Copper losses: 5kw Rotor input 5 loo kw 0.05 6) 1 اذا ميريد شرح الكتب فقط look 7) rotor DC ined sove in peaper I need a detailed solution on paper please 0 64 (Find the solution of the initial-valued problems: xy' + 2y = x³e* ;y(1) = 0 Q1// Find the solution of: (1) y' + ytqpx = see²x y³arrow_forward
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