
Calculate the equation of tangent line to the parabola.

Answer to Problem 23RE
The equation of the tangent is y=−2x+2 .
Explanation of Solution
Given: It is given in the question that the equation is x2=−2y and the point is (2,−2) .
Concept Used:
In this, use the concept of parabola and also make the equation in standard form and from that find the vertex and focus.
Calculation: Here, the equation is x2=−2y .
Rewrite the equation of the parabola in standard from,
x2=−2yx2=4(−12)y
Now, find the vertex and focus from the above standard form: Vertex:(0,0);Focus=(0,−12) .
Now, write the equation for d1 , the distance between the focus and the desired y − intersept.
d1=12+b
Also, find d2 , the distance between the given point and the focus.
d2=√(2−0)2+(−2−−12)2d2=√4+(−32)2d2=√4+94=52
Now, equate d1 and d2 and solve for b.
12+b=52
b=52−12=2
Now, find the slope of the line by using b.
m=−2−(2)2−0=−42=−2
Now, make the equation:
y=−2x+2
Now, to find x − intercept of the line, let y=0 and solve for x :
−2x+2=0−2x=−2x=1
Conclusion:
The equation is y=−2x+2 .
Chapter 9 Solutions
Precalculus with Limits: A Graphing Approach
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