Precalculus with Limits: A Graphing Approach
7th Edition
ISBN: 9781305071711
Author: Ron Larson
Publisher: Brooks/Cole
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Question
Chapter 9.7, Problem 17E
To determine
To identify:
Type of conic represented by the equation using graphing utility.
Expert Solution & Answer
Answer to Problem 17E
Type of conic represented by the equation using graphing utility is hyperbola.
Explanation of Solution
Given information:
Consider the following equation in polar form,
Compare with the polar equation of the conic with vertical directrix to the left of pole given by,
From the equation
So it is clear that
Since,
The graph for the given function is as below:
Chapter 9 Solutions
Precalculus with Limits: A Graphing Approach
Ch. 9.1 - Prob. 1ECh. 9.1 - Prob. 2ECh. 9.1 - Prob. 3ECh. 9.1 - Prob. 4ECh. 9.1 - Prob. 5ECh. 9.1 - Prob. 6ECh. 9.1 - Prob. 7ECh. 9.1 - Prob. 8ECh. 9.1 - Prob. 9ECh. 9.1 - Prob. 10E
Ch. 9.1 - Prob. 11ECh. 9.1 - Prob. 12ECh. 9.1 - Prob. 13ECh. 9.1 - Prob. 14ECh. 9.1 - Prob. 15ECh. 9.1 - Prob. 16ECh. 9.1 - Prob. 17ECh. 9.1 - Prob. 18ECh. 9.1 - Prob. 19ECh. 9.1 - Prob. 20ECh. 9.1 - Prob. 21ECh. 9.1 - Prob. 22ECh. 9.1 - Prob. 23ECh. 9.1 - Prob. 24ECh. 9.1 - Prob. 25ECh. 9.1 - Prob. 26ECh. 9.1 - Prob. 27ECh. 9.1 - Prob. 28ECh. 9.1 - Prob. 29ECh. 9.1 - Prob. 30ECh. 9.1 - Prob. 31ECh. 9.1 - Prob. 32ECh. 9.1 - Prob. 33ECh. 9.1 - Prob. 34ECh. 9.1 - Prob. 35ECh. 9.1 - Prob. 36ECh. 9.1 - Prob. 37ECh. 9.1 - Prob. 38ECh. 9.1 - Prob. 39ECh. 9.1 - Prob. 40ECh. 9.1 - Prob. 41ECh. 9.1 - Prob. 42ECh. 9.1 - Prob. 43ECh. 9.1 - Prob. 44ECh. 9.1 - Prob. 45ECh. 9.1 - Prob. 46ECh. 9.1 - Prob. 47ECh. 9.1 - Prob. 48ECh. 9.1 - Prob. 49ECh. 9.1 - Prob. 50ECh. 9.1 - Prob. 51ECh. 9.1 - Prob. 52ECh. 9.1 - Prob. 53ECh. 9.1 - Prob. 54ECh. 9.1 - Prob. 55ECh. 9.1 - Prob. 56ECh. 9.1 - Prob. 57ECh. 9.1 - Prob. 58ECh. 9.1 - Prob. 59ECh. 9.1 - Prob. 60ECh. 9.1 - Prob. 61ECh. 9.1 - Prob. 62ECh. 9.1 - Prob. 63ECh. 9.1 - Prob. 64ECh. 9.1 - Prob. 65ECh. 9.1 - Prob. 66ECh. 9.1 - Prob. 67ECh. 9.1 - Prob. 68ECh. 9.1 - Prob. 69ECh. 9.1 - Prob. 70ECh. 9.1 - Prob. 71ECh. 9.1 - Prob. 72ECh. 9.1 - Prob. 73ECh. 9.1 - Prob. 74ECh. 9.1 - Prob. 75ECh. 9.1 - Prob. 76ECh. 9.1 - Prob. 77ECh. 9.1 - Prob. 78ECh. 9.1 - Prob. 79ECh. 9.1 - Prob. 80ECh. 9.1 - Prob. 81ECh. 9.1 - Prob. 82ECh. 9.1 - Prob. 83ECh. 9.1 - Prob. 84ECh. 9.1 - Prob. 85ECh. 9.1 - Prob. 86ECh. 9.1 - Prob. 87ECh. 9.1 - Prob. 88ECh. 9.1 - Prob. 89ECh. 9.1 - Prob. 90ECh. 9.1 - Prob. 91ECh. 9.1 - Prob. 92ECh. 9.1 - Prob. 93ECh. 9.1 - Prob. 94ECh. 9.1 - Prob. 95ECh. 9.1 - Prob. 96ECh. 9.1 - Prob. 97ECh. 9.1 - Prob. 98ECh. 9.1 - Prob. 99ECh. 9.1 - Prob. 100ECh. 9.1 - Prob. 101ECh. 9.1 - Prob. 102ECh. 9.1 - Prob. 103ECh. 9.1 - Prob. 104ECh. 9.1 - Prob. 105ECh. 9.1 - Prob. 106ECh. 9.1 - Prob. 107ECh. 9.1 - Prob. 108ECh. 9.1 - Prob. 109ECh. 9.1 - Prob. 110ECh. 9.1 - Prob. 111ECh. 9.1 - Prob. 112ECh. 9.1 - Prob. 113ECh. 9.1 - Prob. 114ECh. 9.1 - Prob. 115ECh. 9.1 - 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Prob. 3ECh. 9.4 - Prob. 4ECh. 9.4 - Prob. 5ECh. 9.4 - Prob. 6ECh. 9.4 - Prob. 7ECh. 9.4 - Prob. 8ECh. 9.4 - Prob. 9ECh. 9.4 - Prob. 10ECh. 9.4 - Prob. 11ECh. 9.4 - Prob. 12ECh. 9.4 - Prob. 13ECh. 9.4 - Prob. 14ECh. 9.4 - Prob. 15ECh. 9.4 - Prob. 16ECh. 9.4 - Prob. 17ECh. 9.4 - Prob. 18ECh. 9.4 - Prob. 19ECh. 9.4 - Prob. 20ECh. 9.4 - Prob. 21ECh. 9.4 - Prob. 22ECh. 9.4 - Prob. 23ECh. 9.4 - Prob. 24ECh. 9.4 - Prob. 25ECh. 9.4 - Prob. 26ECh. 9.4 - Prob. 27ECh. 9.4 - Prob. 28ECh. 9.4 - Prob. 29ECh. 9.4 - Prob. 30ECh. 9.4 - Prob. 31ECh. 9.4 - Prob. 32ECh. 9.4 - Prob. 33ECh. 9.4 - Prob. 34ECh. 9.4 - Prob. 35ECh. 9.4 - Prob. 36ECh. 9.4 - Prob. 37ECh. 9.4 - Prob. 38ECh. 9.4 - Prob. 39ECh. 9.4 - Prob. 40ECh. 9.4 - Prob. 41ECh. 9.4 - Prob. 42ECh. 9.4 - Prob. 43ECh. 9.4 - Prob. 44ECh. 9.4 - Prob. 45ECh. 9.4 - Prob. 46ECh. 9.4 - Prob. 47ECh. 9.4 - Prob. 48ECh. 9.4 - Prob. 49ECh. 9.4 - Prob. 50ECh. 9.4 - Prob. 51ECh. 9.4 - Prob. 52ECh. 9.4 - Prob. 53ECh. 9.4 - Prob. 54ECh. 9.4 - Prob. 55ECh. 9.4 - Prob. 56ECh. 9.4 - Prob. 57ECh. 9.4 - Prob. 58ECh. 9.4 - Prob. 59ECh. 9.4 - Prob. 60ECh. 9.4 - Prob. 61ECh. 9.4 - Prob. 62ECh. 9.4 - Prob. 63ECh. 9.4 - Prob. 64ECh. 9.4 - Prob. 65ECh. 9.4 - Prob. 66ECh. 9.4 - Prob. 67ECh. 9.4 - Prob. 68ECh. 9.4 - Prob. 69ECh. 9.4 - Prob. 70ECh. 9.4 - Prob. 71ECh. 9.4 - Prob. 72ECh. 9.4 - Prob. 73ECh. 9.4 - Prob. 74ECh. 9.5 - Prob. 1ECh. 9.5 - Prob. 2ECh. 9.5 - Prob. 3ECh. 9.5 - Prob. 4ECh. 9.5 - Prob. 5ECh. 9.5 - Prob. 6ECh. 9.5 - Prob. 7ECh. 9.5 - Prob. 8ECh. 9.5 - Prob. 9ECh. 9.5 - Prob. 10ECh. 9.5 - Prob. 11ECh. 9.5 - Prob. 12ECh. 9.5 - Prob. 13ECh. 9.5 - Prob. 14ECh. 9.5 - Prob. 15ECh. 9.5 - Prob. 16ECh. 9.5 - Prob. 17ECh. 9.5 - Prob. 18ECh. 9.5 - Prob. 19ECh. 9.5 - Prob. 20ECh. 9.5 - Prob. 21ECh. 9.5 - Prob. 22ECh. 9.5 - Prob. 23ECh. 9.5 - Prob. 24ECh. 9.5 - Prob. 25ECh. 9.5 - Prob. 26ECh. 9.5 - Prob. 27ECh. 9.5 - Prob. 28ECh. 9.5 - Prob. 29ECh. 9.5 - Prob. 30ECh. 9.5 - Prob. 31ECh. 9.5 - Prob. 32ECh. 9.5 - Prob. 33ECh. 9.5 - Prob. 34ECh. 9.5 - Prob. 35ECh. 9.5 - Prob. 36ECh. 9.5 - Prob. 37ECh. 9.5 - Prob. 38ECh. 9.5 - Prob. 39ECh. 9.5 - Prob. 40ECh. 9.5 - Prob. 41ECh. 9.5 - Prob. 42ECh. 9.5 - Prob. 43ECh. 9.5 - Prob. 44ECh. 9.5 - Prob. 45ECh. 9.5 - Prob. 46ECh. 9.5 - Prob. 47ECh. 9.5 - Prob. 48ECh. 9.5 - Prob. 49ECh. 9.5 - Prob. 50ECh. 9.5 - Prob. 51ECh. 9.5 - Prob. 52ECh. 9.5 - Prob. 53ECh. 9.5 - Prob. 54ECh. 9.5 - Prob. 55ECh. 9.5 - Prob. 56ECh. 9.5 - Prob. 57ECh. 9.5 - Prob. 58ECh. 9.5 - Prob. 59ECh. 9.5 - Prob. 60ECh. 9.5 - Prob. 61ECh. 9.5 - Prob. 62ECh. 9.5 - Prob. 63ECh. 9.5 - Prob. 64ECh. 9.5 - Prob. 65ECh. 9.5 - Prob. 66ECh. 9.5 - Prob. 67ECh. 9.5 - Prob. 68ECh. 9.5 - Prob. 69ECh. 9.5 - Prob. 70ECh. 9.5 - Prob. 71ECh. 9.5 - Prob. 72ECh. 9.5 - Prob. 73ECh. 9.5 - Prob. 74ECh. 9.5 - Prob. 75ECh. 9.5 - Prob. 76ECh. 9.5 - Prob. 77ECh. 9.5 - Prob. 78ECh. 9.5 - Prob. 79ECh. 9.5 - Prob. 80ECh. 9.5 - Prob. 81ECh. 9.5 - Prob. 82ECh. 9.5 - Prob. 83ECh. 9.5 - Prob. 84ECh. 9.5 - Prob. 85ECh. 9.5 - Prob. 86ECh. 9.5 - Prob. 87ECh. 9.5 - Prob. 88ECh. 9.5 - 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Prob. 1CTCh. 9 - Prob. 2CTCh. 9 - Prob. 3CTCh. 9 - Prob. 4CTCh. 9 - Prob. 5CTCh. 9 - Prob. 6CTCh. 9 - Prob. 7CTCh. 9 - Prob. 8CTCh. 9 - Prob. 9CTCh. 9 - Prob. 10CTCh. 9 - Prob. 11CTCh. 9 - Prob. 12CTCh. 9 - Prob. 13CTCh. 9 - Prob. 14CTCh. 9 - Prob. 15CTCh. 9 - Prob. 16CTCh. 9 - Prob. 17CTCh. 9 - Prob. 18CTCh. 9 - Prob. 19CTCh. 9 - Prob. 20CTCh. 9 - Prob. 21CTCh. 9 - Prob. 22CTCh. 9 - Prob. 23CTCh. 9 - Prob. 24CTCh. 9 - Prob. 25CTCh. 9 - Prob. 1CLTCh. 9 - Prob. 2CLTCh. 9 - Prob. 3CLTCh. 9 - Prob. 4CLTCh. 9 - Prob. 5CLTCh. 9 - Prob. 6CLTCh. 9 - Prob. 7CLTCh. 9 - Prob. 8CLTCh. 9 - Prob. 9CLTCh. 9 - Prob. 10CLTCh. 9 - Prob. 11CLTCh. 9 - Prob. 12CLTCh. 9 - Prob. 13CLTCh. 9 - Prob. 14CLTCh. 9 - Prob. 15CLTCh. 9 - Prob. 16CLTCh. 9 - Prob. 17CLTCh. 9 - Prob. 18CLTCh. 9 - Prob. 19CLTCh. 9 - Prob. 20CLTCh. 9 - Prob. 21CLTCh. 9 - Prob. 22CLTCh. 9 - Prob. 23CLTCh. 9 - Prob. 24CLTCh. 9 - Prob. 25CLTCh. 9 - Prob. 26CLTCh. 9 - Prob. 27CLTCh. 9 - Prob. 28CLTCh. 9 - Prob. 29CLTCh. 9 - Prob. 30CLTCh. 9 - 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- Calculate the limit lim X-a x-a 5 using the following factorization formula where n is a positive integer and x-➡a a is a real number. x-a = (x-a) (x1+x-2a+x lim x-a X - a x-a 5 = n- + xa an-2 + an−1)arrow_forwardThe function s(t) represents the position of an object at time t moving along a line. Suppose s(1) = 116 and s(5)=228. Find the average velocity of the object over the interval of time [1,5]. The average velocity over the interval [1,5] is Vav = (Simplify your answer.)arrow_forwardFor the position function s(t) = - 16t² + 105t, complete the following table with the appropriate average velocities. Then make a conjecture about the value of the instantaneous velocity at t = 1. Time Interval Average Velocity [1,2] Complete the following table. Time Interval Average Velocity [1, 1.5] [1, 1.1] [1, 1.01] [1, 1.001] [1,2] [1, 1.5] [1, 1.1] [1, 1.01] [1, 1.001] ப (Type exact answers. Type integers or decimals.) The value of the instantaneous velocity at t = 1 is (Round to the nearest integer as needed.)arrow_forward
- Find the following limit or state that it does not exist. Assume b is a fixed real number. (x-b) 40 - 3x + 3b lim x-b x-b ... Select the correct choice below and, if necessary, fill in the answer box to complete your choice. (x-b) 40 -3x+3b A. lim x-b x-b B. The limit does not exist. (Type an exact answer.)arrow_forwardx4 -289 Consider the function f(x) = 2 X-17 Complete parts a and b below. a. Analyze lim f(x) and lim f(x), and then identify the horizontal asymptotes. x+x X--∞ lim 4 X-289 2 X∞ X-17 X - 289 lim = 2 ... X∞ X - 17 Identify the horizontal asymptotes. Select the correct choice and, if necessary, fill in the answer box(es) to complete your choice. A. The function has a horizontal asymptote at y = B. The function has two horizontal asymptotes. The top asymptote is y = and the bottom asymptote is y = ☐ . C. The function has no horizontal asymptotes. b. Find the vertical asymptotes. For each vertical asymptote x = a, evaluate lim f(x) and lim f(x). Select the correct choice and, if necessary, fill in the answer boxes to complete your choice. earrow_forwardExplain why lim x²-2x-35 X-7 X-7 lim (x+5), and then evaluate lim X-7 x² -2x-35 x-7 x-7 Choose the correct answer below. A. x²-2x-35 The limits lim X-7 X-7 and lim (x+5) equal the same number when evaluated using X-7 direct substitution. B. Since each limit approaches 7, it follows that the limits are equal. C. The numerator of the expression X-2x-35 X-7 simplifies to x + 5 for all x, so the limits are equal. D. Since x²-2x-35 X-7 = x + 5 whenever x 7, it follows that the two expressions evaluate to the same number as x approaches 7. Now evaluate the limit. x²-2x-35 lim X-7 X-7 = (Simplify your answer.)arrow_forwardA function f is even if f(x) = f(x) for all x in the domain of f. If f is even, with lim f(x) = 4 and x-6+ lim f(x)=-3, find the following limits. X-6 a. lim f(x) b. +9-←x lim f(x) X-6 a. lim f(x)= +9-←x (Simplify your answer.) b. lim f(x)= X→-6 (Simplify your answer.) ...arrow_forwardEvaluate the following limit. lim X-X (10+19) Select the correct answer below and, if necessary, fill in the answer box within your choice. 10 A. lim 10+ = 2 ☐ (Type an integer or a simplified fraction.) X-∞ B. The limit does not exist.arrow_forwardFind the following limit or state that it does not exist. x² +x-20 lim x-4 x-4 Select the correct choice below and, if necessary, fill in the answer box to complete your choice. A. lim x²+x-20 x-4 (Type an exact answer.) x→4 B. The limit does not exist.arrow_forwardDetermine the intervals on which the following function is continuous. f(x) = x - 5x + 6 2 X-9 On what interval(s) is f continuous? (Simplify your answer. Type your answer in interval notation. Use a comma to separate answers as needed.)arrow_forwardFind the following limit or state that it does not exist. 2 3x² +7x+2 lim X-2 6x-8 Select the correct choice below and, if necessary, fill in the answer box to complete your choice. A. lim 3x²+7x+2 6x-8 (Simplify your answer.) X-2 B. The limit does not exist.arrow_forwardFind the following limit or state that it does not exist. X-2 lim x-2 5x+6 - 4 Select the correct choice below and, if necessary, fill in the answer box to complete your choice. O A. lim X-2 X-2 15x+6 = (Type an exact answer.) - 4 B. The limit does not exist.arrow_forwardarrow_back_iosSEE MORE QUESTIONSarrow_forward_ios
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