Chapter 9.7, Problem 37CCR

To determine

To represent : the number of columns of text need to be written in a week by an inequality, and solve it.

Answer to Problem 37CCR

The inequality for the given situation:

  $\$20x+\$600\ge \$1000$

The solution of the inequality is $x\ge 20$ , that is, the writer should write at least $20$ columns of text that week.

Explanation of Solution

Given information :

A writer is paid $\$20$ per column of text plus $\$600$ per week. The payment need for a week is to be at $\$1000$ .

Calculation :

As per the question,

Let the number of columns written in a weekbe $x$ .

The writeris paid $\$20$ per column of text plus $\$600$ per week.

Total payment needed is to be at least $\$1000$ .

That is, $\$20x+\$600\ge \$1000$

Solving the inequality:

  $\begin{array}{l}\$20x+\$600\ge \$1000\text{ [Write the inequality]}\\ \text{\$20}x+\$600-\$600\ge \$1000-\$600\text{ [Subtract \$600 from both sides]}\\ \text{ \$20}x\ge \$400\text{ [Simplify]}\\ x\ge 20\text{ [Divide both sides by \$20]}\end{array}$

The solution of the inequality is $x\ge 20$ .

Thus, the writer should write at least $20$ columns of text that week.