Chapter 9.4, Problem 9IP

a.

To determine

To determine the relationship between pressure and depth.

Answer to Problem 9IP

The relationship between pressure and depth is $y=0.45x$

Explanation of Solution

Given:

Depth(ft)	Pressure(psi)
X	Y
33	14.7
66	29.4
99	44.1
132	58.8

Calculation:

The relationship between pressure and depth.

Taking one point from above table $x=33$ and $y=14.7$ .

  $\begin{array}{l}p=\frac{14.7}{33}\\ =0.45\end{array}$

Therefore,

The equation is $y=0.45x$

b.

To determine

To determine the pressure at depth of $900$ feet.

Answer to Problem 9IP

Pressure is $405$ psi.

Explanation of Solution

Given:

The equation $y=0.45x$

  $x=900feet$

Calculation:

The pressure at depth of $900$ feet.

The equation $y=0.45x$

When the $x=900\text{ feet}$ value of $y$ .

  $\begin{array}{l}y=0.45\times 900\\ y=405psi\end{array}$

Therefore,

Approximate water pressure at this depth is $405psi$ .