Chapter 9.6, Problem 9.16WE

Interpretation Introduction

Interpretation:

The required volume of $\text{0}\text{.203 M NaOH}$ to neutralize the $\text{25}\text{.0 mL of a 0}{\text{.188 M H}}_{\text{2}}{\text{SO}}_{\text{4}}$ solution should be calculated.

Concept introduction:

Neutralization reaction:

• The reaction of acid and base to gives salt is known as neutralization reaction.
• The equal volume and concentrations of acid is equally react with equal volume and concentrated base.
• In end point the ionic concentration is zero.

Volumetric principle:

• The relationship between initial and final concentrations and volumes of solutions in titration process are given in the volumetric equation and it is,

$\begin{array}{l}{\text{M}}_{\text{c}}{\text{×mL}}_{\text{c}}\text{=}{\text{M}}_{\text{d}}{\text{×mL}}_{\text{d}}\\ {\text{M}}_{\text{c}}\text{=}\text{Initial}\text{concentration}\\ {\text{mL}}_{\text{c}}\text{=}\text{Initial}\text{volume}\\ {\text{M}}_{\text{d}}\text{=}\text{Final}\text{concentration}\\ {\text{mL}}_{\text{d}}\text{=}\text{Final}\text{volume}\end{array}$