Chapter 9.4, Problem 7CC

(a)

Interpretation Introduction

Interpretation:

The alkyne products formed for each given substrates when treated with a sodium amide $\left({\text{excess NaNH}}_{\text{2}}\right)$ should be identified.

Concept Introduction:

Elimination Reaction: It is just reverse reaction of addition where substituent from the given molecule is removed via E₁ (the reaction depends only on the substrate involved in the reaction) or E₂ (the reaction depends on both of the substituents in the reaction) mechanism.

Soda amide: The strong base of ${\text{NaNH}}_{\text{2}}{\text{/NH}}_{\text{3}}$ will deprotonate alkynes, alcohols and other organic functional groups with acidic protons such as esters and ketones. It is also a very strong nucleophile. It is a strong base and excellent nucleophile. It’s used deprotonated of weak acids and also for elimination reaction.

(b)

Interpretation Introduction

Interpretation:

The alkyne products formed for each given substrates when treated with a sodium amide $\left({\text{excess NaNH}}_{\text{2}}\right)$ should be identified.

Concept Introduction:

Elimination Reaction: It is just reverse reaction of addition where substituent from the given molecule is removed via E₁ (the reaction depends only on the substrate involved in the reaction) or E₂ (the reaction depends on both of the substituents in the reaction) mechanism.

Soda amide: The strong base of ${\text{NaNH}}_{\text{2}}{\text{/NH}}_{\text{3}}$ will deprotonate alkynes, alcohols and other organic functional groups with acidic protons such as esters and ketones. It is also a very strong nucleophile. It is a strong base and excellent nucleophile. It’s used deprotonated of weak acids and also for elimination reaction.