(a)
Interpretation:
The synthetic route for the preparation of given transformation should be determined.
Concept Introduction:
Hydrogenation reaction: The hydrogenation is a reduction reaction which results in an addition of hydrogen. Several organic compounds is hydrogenated, it becomes more saturated.
Linder’s catalyst: The
Soda amide: The
(b)
Interpretation:
The synthetic route for the preparation of given transformation should be determined.
Concept Introduction:
Soda amide: The NaNH2/NH3 is a strong base and excellent nucleophile. Its used deprotonated of weak acids and also for elimination reaction.
Anti- Markovnikov addition: These rules describe the regiochemistry where the substituent is bonded to a less substituted carbon, rather than the more substituted carbon. This placed is quite unusual as carbon cations which are commonly formed during alkene or alkyne reactions tend to favor the more substituted carbon.
(c)
Interpretation:
The synthetic route for the preparation of given transformation should be determined.
Concept Introduction:
Markovnikov addition: The addition reaction of parotic acids to a different alkene or alkyne, the hydrogen atom of
Soda amide: The NaNH2/NH3 is a strong base and excellent nucleophile. Its used deprotonated of weak acids and also for elimination reaction.
(d)
Interpretation:
The synthetic route for the preparation of given transformation should be determined.
Concept Introduction:
Soda amide: The NaNH2/NH3 is a strong base and excellent nucleophile. Its used deprotonated of weak acids and also for elimination reaction.
Metal and ammonia reaction: The alkyne involves sodium (Na)/NH3. This end up reducing to alkyne to give the trans (E) alkene.
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Chapter 9 Solutions
ORGANIC CHEMISTRY-NEXTGEN+BOX (2 SEM.)
- Q5. Predict the organic product(s) for the following transformations. If no reaction will take place (or the reaction is not synthetically useful), write "N.R.". Determine what type of transition state is present for each reaction (think Hammond Postulate). I Br₂ CH3 F2, light CH3 Heat CH3 F₂ Heat Br2, light 12, light CH3 Cl2, light Noarrow_forwardNonearrow_forwardIn the phase diagram of steel (two components Fe and C), region A is the gamma austenite solid and region B contains the gamma solid and liquid. Indicate the degrees of freedom that the fields A and B have,arrow_forward
- For a condensed binary system in equilibrium at constant pressure, indicate the maximum number of phases that can exist.arrow_forwardPart V. Label ad match the carbons in compounds Jane and Diane w/ the corresponding peak no. in the Spectra (Note: use the given peak no. To label the carbons, other peak no are intentionally omitted) 7 4 2 -0.13 -0.12 -0.11 -0.10 -0.08 8 CI Jane 1 -0.09 5 210 200 190 180 170 160 150 140 130 120 110 100 -8 90 f1 (ppm) 11 8 172.4 172.0 f1 (ppr HO CI NH Diane 7 3 11 80 80 -80 -R 70 60 60 2 5 -8 50 40 8. 170 160 150 140 130 120 110 100 90 -0 80 70 20 f1 (ppm) 15 30 -20 20 -60 60 -0.07 -0.06 -0.05 -0.04 -0.03 -0.02 -0.01 -0.00 -0.01 10 -0.17 16 15 56 16 -0.16 -0.15 -0.14 -0.13 -0.12 -0.11 -0.10 -0.09 -0.08 -0.07 -0.06 -0.05 -0.04 17.8 17.6 17.4 17.2 17.0 f1 (ppm) -0.03 -0.02 550 106 40 30 20 20 -0.01 -0.00 F-0.01 10 0arrow_forwardConsider the reaction of 2-methylpropane with a halogen. With which halogen will the product be almost exclusively 2-halo-2-methylpropane? 1. F2 2. Cl2 3. Br2 4. I2arrow_forward
- Nonearrow_forwardNonearrow_forwardn Feb 3 A T + 4. (2 pts) Draw the structure of the major component of the Limonene isolated. Explain how you confirmed the structure. 5. (2 pts) Draw the fragment corresponding to the base peak in the Mass spectrum of Limonene. 6. (1 pts) Predict the 1H NMR spectral data of R-Limonene. Proton NMR: 5.3 pon multiplet (H Ringarrow_forward
- Part VI. Ca H 10 O is the molecular formula of compound Tom and gives the in the table below. Give a possible structure for compound Tom. 13C Signals summarized C1 C2 C3 C4 C5 C6 C7 13C shift (ppm) 23.5 27.0 33.0 35.8 127 162 205 DEPT-90 + DEPT-135 + +arrow_forward2. Using the following data to calculate the value of AvapH o of water at 298K. AvapH o of water at 373K is 40.7 kJ/mol; molar heat capacity of liquid water at constant pressure is 75.2J mol-1 K-1 and molar heat capacity of water vapor at constant pressure is 33.6 J mol-1 K-1.arrow_forwardPart VII. Below are the 'HNMR 13 3 C-NMR, COSY 2D- NMR, and HSQC 20-NMR (Similar with HETCOR but axes are reversed) spectra of an organic compound with molecular formula C6H13 O. Assign chemical shift values to the H and c atoms of the compound. Find the structure. Show complete solutions. Predicted 1H NMR Spectrum ли 4.7 4.6 4.5 4.4 4.3 4.2 4.1 4.0 3.9 3.8 3.7 3.6 3.5 3.4 3.3 3.2 3.1 3.0 2.9 2.8 2.7 2.6 2.5 2.4 2.3 2.2 2.1 2.0 1.9 1.8 1.7 1.6 1.5 1.4 1.3 1.2 1.1 1.0 0.9 0.8 f1 (ppm)arrow_forward
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