The elimination product formed when 3-bromo-3-methyl-1-butene reacts with CH 3 O - has to be drawn. Concept Introduction: Elimination reaction: Allylic and benzylic halides contains β- hydrogens that readily undergo E2 elimination reaction because of double bond formed in the product is relatively stable and so formed easily. E2 is single step elimination. E2 refers bimolecular elimination in which both Carbon-halogen and Carbon-hydrogen bond should broke to gives double bond.

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Answer 1

Question

Chapter 9.13, Problem 47P

(a)

Interpretation Introduction

Interpretation:

The elimination product formed when 3-bromo-3-methyl-1-butene reacts with CH3O- has to be drawn.

Concept Introduction:

Elimination reaction:

Allylic and benzylic halides contains β- hydrogens that readily undergo E2 elimination reaction because of double bond formed in the product is relatively stable and so formed easily.

E2 is single step elimination. E2 refers bimolecular elimination in which both Carbon-halogen and Carbon-hydrogen bond should broke to gives double bond.

(b)

Interpretation Introduction

Interpretation:

The elimination product formed when 3-bromo-3-methyl-1-butene reacts with CH3OH has to be drawn.

Concept Introduction:

Elimination reaction:

Allylic and benzylic halides contains β- hydrogens that readily undergo E2 elimination reaction because of double bond formed in the product is relatively stable and so formed easily.

Allylic and benzylic halides also can undergo E1 elimination because of they can form relatively stable carbocation.

E1 is dual step elimination. E1 refers unimolecular elimination in which Carbon-halogen bond should broke to gives stable carbocation.

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Answer 2

Question

Chapter 9.13, Problem 47P

(a)

Interpretation Introduction

Interpretation:

The elimination product formed when 3-bromo-3-methyl-1-butene reacts with CH3O- has to be drawn.

Concept Introduction:

Elimination reaction:

Allylic and benzylic halides contains β- hydrogens that readily undergo E2 elimination reaction because of double bond formed in the product is relatively stable and so formed easily.

E2 is single step elimination. E2 refers bimolecular elimination in which both Carbon-halogen and Carbon-hydrogen bond should broke to gives double bond.

(b)

Interpretation Introduction

Interpretation:

The elimination product formed when 3-bromo-3-methyl-1-butene reacts with CH3OH has to be drawn.

Concept Introduction:

Elimination reaction:

Allylic and benzylic halides contains β- hydrogens that readily undergo E2 elimination reaction because of double bond formed in the product is relatively stable and so formed easily.

Allylic and benzylic halides also can undergo E1 elimination because of they can form relatively stable carbocation.

E1 is dual step elimination. E1 refers unimolecular elimination in which Carbon-halogen bond should broke to gives stable carbocation.

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Answer 3

Question

Chapter 9.13, Problem 47P

(a)

Interpretation Introduction

Interpretation:

The elimination product formed when 3-bromo-3-methyl-1-butene reacts with CH3O- has to be drawn.

Concept Introduction:

Elimination reaction:

Allylic and benzylic halides contains β- hydrogens that readily undergo E2 elimination reaction because of double bond formed in the product is relatively stable and so formed easily.

E2 is single step elimination. E2 refers bimolecular elimination in which both Carbon-halogen and Carbon-hydrogen bond should broke to gives double bond.

(b)

Interpretation Introduction

Interpretation:

The elimination product formed when 3-bromo-3-methyl-1-butene reacts with CH3OH has to be drawn.

Concept Introduction:

Elimination reaction:

Allylic and benzylic halides contains β- hydrogens that readily undergo E2 elimination reaction because of double bond formed in the product is relatively stable and so formed easily.

Allylic and benzylic halides also can undergo E1 elimination because of they can form relatively stable carbocation.

E1 is dual step elimination. E1 refers unimolecular elimination in which Carbon-halogen bond should broke to gives stable carbocation.

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Answer 4

Question

Chapter 9.13, Problem 47P

(a)

Interpretation Introduction

Interpretation:

The elimination product formed when 3-bromo-3-methyl-1-butene reacts with CH3O- has to be drawn.

Concept Introduction:

Elimination reaction:

Allylic and benzylic halides contains β- hydrogens that readily undergo E2 elimination reaction because of double bond formed in the product is relatively stable and so formed easily.

E2 is single step elimination. E2 refers bimolecular elimination in which both Carbon-halogen and Carbon-hydrogen bond should broke to gives double bond.

(b)

Interpretation Introduction

Interpretation:

The elimination product formed when 3-bromo-3-methyl-1-butene reacts with CH3OH has to be drawn.

Concept Introduction:

Elimination reaction:

Allylic and benzylic halides contains β- hydrogens that readily undergo E2 elimination reaction because of double bond formed in the product is relatively stable and so formed easily.

Allylic and benzylic halides also can undergo E1 elimination because of they can form relatively stable carbocation.

E1 is dual step elimination. E1 refers unimolecular elimination in which Carbon-halogen bond should broke to gives stable carbocation.

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Answer 5

Chapter 9.13, Problem 47P

(a)

Interpretation Introduction

Interpretation:

The elimination product formed when 3-bromo-3-methyl-1-butene reacts with CH3O- has to be drawn.

Concept Introduction:

Elimination reaction:

Allylic and benzylic halides contains β- hydrogens that readily undergo E2 elimination reaction because of double bond formed in the product is relatively stable and so formed easily.

E2 is single step elimination. E2 refers bimolecular elimination in which both Carbon-halogen and Carbon-hydrogen bond should broke to gives double bond.

(b)

Interpretation Introduction

Interpretation:

The elimination product formed when 3-bromo-3-methyl-1-butene reacts with CH3OH has to be drawn.

Concept Introduction:

Elimination reaction:

Allylic and benzylic halides contains β- hydrogens that readily undergo E2 elimination reaction because of double bond formed in the product is relatively stable and so formed easily.

Allylic and benzylic halides also can undergo E1 elimination because of they can form relatively stable carbocation.

E1 is dual step elimination. E1 refers unimolecular elimination in which Carbon-halogen bond should broke to gives stable carbocation.

Answer 6

Chapter 9.13, Problem 47P

(a)

Interpretation Introduction

Interpretation:

The elimination product formed when 3-bromo-3-methyl-1-butene reacts with CH3O- has to be drawn.

Concept Introduction:

Elimination reaction:

Allylic and benzylic halides contains β- hydrogens that readily undergo E2 elimination reaction because of double bond formed in the product is relatively stable and so formed easily.

E2 is single step elimination. E2 refers bimolecular elimination in which both Carbon-halogen and Carbon-hydrogen bond should broke to gives double bond.

Answer 7

Chapter 9.13, Problem 47P

(a)

Interpretation Introduction

Interpretation:

The elimination product formed when 3-bromo-3-methyl-1-butene reacts with CH3O- has to be drawn.

Concept Introduction:

Elimination reaction:

Allylic and benzylic halides contains β- hydrogens that readily undergo E2 elimination reaction because of double bond formed in the product is relatively stable and so formed easily.

E2 is single step elimination. E2 refers bimolecular elimination in which both Carbon-halogen and Carbon-hydrogen bond should broke to gives double bond.

Answer 8

(b)

Interpretation Introduction

Interpretation:

The elimination product formed when 3-bromo-3-methyl-1-butene reacts with CH3OH has to be drawn.

Concept Introduction:

Elimination reaction:

Allylic and benzylic halides contains β- hydrogens that readily undergo E2 elimination reaction because of double bond formed in the product is relatively stable and so formed easily.

Allylic and benzylic halides also can undergo E1 elimination because of they can form relatively stable carbocation.

E1 is dual step elimination. E1 refers unimolecular elimination in which Carbon-halogen bond should broke to gives stable carbocation.

Answer 9

(b)

Interpretation Introduction

Interpretation:

The elimination product formed when 3-bromo-3-methyl-1-butene reacts with CH3OH has to be drawn.

Concept Introduction:

Elimination reaction:

Allylic and benzylic halides contains β- hydrogens that readily undergo E2 elimination reaction because of double bond formed in the product is relatively stable and so formed easily.

Allylic and benzylic halides also can undergo E1 elimination because of they can form relatively stable carbocation.

E1 is dual step elimination. E1 refers unimolecular elimination in which Carbon-halogen bond should broke to gives stable carbocation.

Answer 10

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Answer 11

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Answer 12

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Answer 13

Ch. 9.1 - Prob. 3P Ch. 9.1 - Does increasing the energy barrier for an SN2...Ch. 9.1 - Rank the following alkyl bromides from most...Ch. 9.1 - Prob. 8P Ch. 9.2 - Prob. 9P Ch. 9.2 - Prob. 10P Ch. 9.2 - Prob. 11P Ch. 9.2 - Prob. 12P Ch. 9.2 - Which substitution reaction lakes place more...Ch. 9.2 - Prob. 15P

Solution Summary: The author explains that 3-bromo-3-methyl-1-butene has - hydrogens that readily undergo E2 elimination reaction because of double bond formed in the product is relatively stable and so formed

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