Concept explainers
(a)
Interpretation:
The less metallic element among
Concept introduction:
The metallic character is characterized by the tendency of metals to lose their outermost valence shell electrons. Greater the ease of electron removal, higher will be the electropositivity of the corresponding elements and vice versa.
The metallic character is characterized by the tendency of metals to lose their outermost valence shell electrons.
Down the group, the number of shells increases with the increase in the
Along the period, the electrons are added in the same outer shell and the effective nuclear charge increases due to which the electrons are attracted to the nucleus by strong electrostatic forces of attraction. Therefore the removal of the electron becomes difficult which results in the decrease of metallic character in a period.
(b)
Interpretation:
The less metallic element among
Concept introduction:
The metallic character is characterized by the tendency of metals to lose their outermost valence shell electrons. Greater the ease of electron removal, higher will be the electropositivity of the corresponding elements and vice versa.
The metallic character is characterized by the tendency of metals to lose their outermost valence shell electrons.
Down the group, the number of shells increases with the increase in the atomic number and the outermost valence electrons becomes farther from the nucleus and therefore can be removed easily. So the metallic character increases from top to bottom in a group.
Along the period, the electrons are added in the same outer shell and the effective nuclear charge increases due to which the electrons are attracted to the nucleus by strong electrostatic forces of attraction. Therefore the removal of the electron becomes difficult which results in the decrease of metallic character in a period.
(c)
Interpretation:
The less metallic element among
Concept introduction:
The metallic character is characterized by the tendency of metals to lose their outermost valence shell electrons. Greater the ease of electron removal, higher will be the electropositivity of the corresponding elements and vice versa.
The metallic character is characterized by the tendency of metals to lose their outermost valence shell electrons.
Down the group, the number of shells increases with the increase in the atomic number and the outermost valence electrons becomes farther from the nucleus and therefore can be removed easily. So the metallic character increases from top to bottom in a group.
Along the period, the electrons are added in the same outer shell and the effective nuclear charge increases due to which the electrons are attracted to the nucleus by strong electrostatic forces of attraction. Therefore the removal of the electron becomes difficult which results in the decrease of metallic character in a period.
Want to see the full answer?
Check out a sample textbook solutionChapter 9 Solutions
CHEM 212:CHEMISTSRY V 2
- Please correct answer and don't used hand raitingarrow_forwardPlease correct answer and don't used hand raitingarrow_forwardCurved arrows are used to illustrate the flow of electrons. Using the provided resonance structures, draw the curved electron-pushing arrows to show the interconversion between resonance hybrid contributors. Be sure to account for all bond-breaking and bond- making steps. Incorrect, 3 attempts remaining Select to Add Arrows HO Select to Add Arrows :0 Select to Add Arrows Please help me fix this first step! Qarrow_forward
- Please correct answer and don't used hand raitingarrow_forwardCurved arrows are used to illustrate the flow of electrons. Use the reaction conditions provided and follow the curved arrows to draw the resonance hybrid contributor. Include all lone pairs and charges as appropriate. :O Please help me fix this drawing, I have attached the three incorrect drawings I've already tried. I only get one more chance! Please help! Drawing 0:0 Incorrect, 1 attempt remaining Q OCH :0: Select to Draw O :O: Select to Draw :0: Select to Drawarrow_forwardPlease correct answer and don't used hand raitingarrow_forward
- Please correct answer and don't used hand raitingarrow_forwardPlease correct answer and don't used hand raitingarrow_forwardUse the systematic treatment of equilibrium to determine the pH and the concentrations of all species in a saturated aqueous solution of SrF2. Do not include activity coefficients. The solubility of SrF2 is governed by Ksp for the salt, hydrolysis of F- and of Sr2+, and by ion pairing between Sr2 + and F-. PK(SrF2) = 8.58, PK(HF) = 3.17, pkw = 14.00, pk for the formation of (SrOH+) = 13.18, pk for the formation of (SrF+) = 0.14 Show all your work and upload your answers here. 1 - Write the pertinent reactions. 2 - Write mass balance and charge balance equations. 3 - Write the equilibrium constant expressions. 4 - Count the equations and unknowns. 5- If the problem is solvable make suitable approximations and find the concentrations and the pH.arrow_forward
- ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistryChemistryISBN:9781259911156Author:Raymond Chang Dr., Jason Overby ProfessorPublisher:McGraw-Hill EducationPrinciples of Instrumental AnalysisChemistryISBN:9781305577213Author:Douglas A. Skoog, F. James Holler, Stanley R. CrouchPublisher:Cengage Learning
- Organic ChemistryChemistryISBN:9780078021558Author:Janice Gorzynski Smith Dr.Publisher:McGraw-Hill EducationChemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage LearningElementary Principles of Chemical Processes, Bind...ChemistryISBN:9781118431221Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. BullardPublisher:WILEY