Chapter 9, Problem 9.20P

Interpretation Introduction

(a)

Interpretation:

To sketch the shapes of $QversusT$ curves.

Concept introduction:

Metallic Iron is followed by the following reaction.

$FeO\left(s\right)+CO\left(g\right)\to Fe\left(s\right)+C{O}_2\left(g\right)$

The flowchart for the process is shown below:

Interpretation Introduction

(b)

Interpretation:

To derive the expressions for enthalpies ${\hat{H}}_1,{\hat{H}}_2,{\hat{H}}_{3}and{\hat{H}}_4$ as functions of Temperature.

Concept introduction:

:Metallic Iron is followed by the following reaction.

$FeO\left(s\right)+CO\left(g\right)\to Fe\left(s\right)+C{O}_2\left(g\right)$

The flowchart for the process is shown below:

An outlet-enthalpy table is shown below:

Interpretation Introduction

(c)

Interpretation:

To interpret the heat duty $Q$.

Concept introduction:

Metallic Iron is followed by the following reaction.

$FeO\left(s\right)+CO\left(g\right)\to Fe\left(s\right)+C{O}_2\left(g\right)$

The flowchart for the process is shown below:

The expressions for enthalpies ${\hat{H}}_1,{\hat{H}}_2,{\hat{H}}_{3}and{\hat{H}}_4$ as functions of Temperature are

${\hat{H}}_1=\left(0.0528T+3.1215\times {10}^{-6}{T}^2+\frac{318.8}{T}-17.081\right)\frac{KJ}{mol}$

${\hat{H}}_2=\left(0.0276T+2.51\times {10}^{-6}{T}^2-8.451\right)\frac{KJ}{mol}$

${\hat{H}}_3=\left(0.01728T+1.335\times {10}^{-5}{T}^2-6.335\right)\frac{KJ}{mol}$

${\hat{H}}_4=\left(0.04326T+5.73\times {10}^{-6}{T}^2+\frac{818}{T}-16.145\right)\frac{KJ}{mol}$

Interpretation Introduction

(d)

Interpretation:

To prepare the spreadsheet for the given data and shapes of the graphs predicted according to part $\left(a\right)$.

Concept introduction:

:Metallic Iron is followed by the following reaction.

$FeO\left(s\right)+CO\left(g\right)\to Fe\left(s\right)+C{O}_2\left(g\right)$

The flowchart for the process is shown below: