Concept explainers
(a)
Interpretation:
The flowchart of the process needs to be prepared, considering absorption and distillation as a single unit.
Concept introduction:
Flow chart is diagrammatic representation of the reaction taking place in the reactor.
The calculation of flowchart is based on the relation
It helps to determine the amount of product formed with respect to the amount of reactant fed to the reactor.
(b)
Interpretation:
The operating temperature of methanol vaporizer needs to be determined.
Concept introduction
Raoult’s law: This law implies that a given temperature the value of vapor pressure is equal to the product of mole fraction of components and total pressure.
The relationship is gives as
Here,
Antoine equation used to determine the temperature using partial pressure in
A, B and C are the constants with respect to components and temperature
If the vapor pressure in
This relationship correlates the temperature with vapor pressure.
(c)
Interpretation:
The feed rate of stream in
Concept introduction:
Mole fraction
Here,
The below equation used to calculate the amount of heat transfer
(d)
Interpretation:
The steam rate generation in
Concept introduction:
Relation gives the amount of heat generation:
Here,
Enthalpy of reactant and product depends upon the specific heat and the temperature difference.
(e)
Interpretation:
The impact of steam on outlet temperature needs to be explained.
Concept introduction:
The amount of heat transfer
The concept is based on heat exchangers.
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Chapter 9 Solutions
ELEM.PRIN.OF CHEMICAL PROC.-W/ACCESS
- please, provide me with right resultsarrow_forwardEx. HW. A vertical glass tube, 2cm ID & 5m long in heated uniformly over its length. The water enter at (200-204 C) & 68.9 bar calculated the pressure drop if the flowrate 0.15 Kg/s & the power applied as a heat to the fluid is 100KW using the homogeneous model. Given that enthalpy at inlet temp.=0.87MJ/Kg, enthalpy saturation temp (285C)=1.26 MJ/Kg and μl=0.972*10-4 Ns/m2, μG=2.89*10-5 Ns/m2, UG=2.515*10-2m3/Kg and the change in UG over range of pressure=-4.45*10-4m3/Kg/bar.arrow_forward4. An experimental test rig is used to examine two-phase flow regimes in horizontal pipelines. A particular experiment involved uses air and water at a temperature of 25°C, which flow through a horizontal glass tube with an internal diameter of 25.4 mm and a length of 40 m. Water is admitted at a controlled rate of 0.026 kgs at one end and air at a rate of 5 x 104 kgs in the same direction. The density of water is 1000 kgm³, and the density of air is 1.2 kgm. Determine the mass flow rate, the mean density, gas void fraction, and the superficial velocities of the air and water. Answer: 0.02605 kgs 1, 61.1 kgm³, 0.94, 0.822 ms-1, 0.051 ms-1arrow_forward
- and the viscosity of the water is 1.24 × 104 Nsm 2. Answer: Slug flow 1. Determine the range of mean density of a mixture of air in a 50:50 oil-water liquid phase across a range of gas void fractions. The den- sity of oil is 900 kgm³, water is 1000 kgm³, and gas is 10 kgm³.arrow_forwardA chemical reaction takes place in a container of cross-sectional area 50.0 cm2. As a result of the reaction, a piston is pushed out through 15 cm against an external pressure of 121 kPa. Calculate the work done (in J) by the system.arrow_forwardExample 7.2 Steam is generated in a high pressure boiler containing tubes 2.5 m long and 12.5 mm internal diameter. The wall roughness is 0.005 mm. Water enters the tubes at a pressure of 55.05 bar and a temperature of 270°C, and the water flow rate through each tube is 500 kg/h. Each tube is heated uniformly at a rate of 50 kW. Calle (a) Estimate the pressure drop across each tube (neglecting end effects) using (i) the homogeneous flow model and (ii) the Martinelli-Nelson correlation. (b) How should the calculation be modified if the inlet temperature were 230°C at the same pressure?arrow_forward
- Please solve this question by simulation in aspen hysysarrow_forward(11.35. For a binary gas mixture described by Eqs. (3.37) and (11.58), prove that: 4812 Pу132 ✓ GE = 812 Py1 y2. ✓ SE dT HE-12 T L = = (812 - 7 1/8/123) d² 812 Pylyz C=-T Pylyz dT dT² See also Eq. (11.84), and note that 812 = 2B12 B11 - B22. perimental values of HE for binary liquid mixtures ofarrow_forwardplease provide me the solution with more details. because the previous solution is not cleararrow_forward
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