Draw all constitutional isomers having molecular formula C 4 H 10 0. Classify each compound as a 1°, 2°, or 3° alcohol, or a symmetrical or unsymmetrical ether.

Question

Want to see more full solutions like this?

Answer 1

Textbook Question

Chapter 9, Problem 9.1P

Draw all constitutional isomers having molecular formula C₄H₁₀0. Classify each compound as a 1°, 2°, or 3° alcohol, or a symmetrical or unsymmetrical ether.

Expert Solution & Answer

Interpretation Introduction

Interpretation:

To draw all the constitutional isomers for the molecular formula C₄H₁₀O and classify each compound as a 1°, 2°, or 3° alcohol, or a symmetrical or unsymmetrical ether.

Concept introduction:

Constitutional isomers also known as structural isomers. They are molecules that have the same chemical formula but their atoms are arranged differently. They are three main types of constitutional isomers.

a) Chain isomers – the carbon chain has a different order of carbon and hydrogen atoms.

Organic Chemistry, Chapter 9, Problem 9.1P , additional homework tip 1

b) Position isomers- a functional group of the isomers is in a different location on the molecules.

Organic Chemistry, Chapter 9, Problem 9.1P , additional homework tip 2

c) Functional isomers- the isomers contain a different functional group.

Organic Chemistry, Chapter 9, Problem 9.1P , additional homework tip 3

Answer to Problem 9.1P

Molecular formula C₄H₁₀O may be an alcohol and ether and seven isomers are shown below.

Organic Chemistry, Chapter 9, Problem 9.1P , additional homework tip 4

Strucutre,

A= 2^oalcohol

B=1^oalcohol

C=1^oalcohol

D=3^oalcohol

E=Symmetrical ether

F=Unsymmetrical ether

G=Unsymmetrical ether

Explanation of Solution

Organic Chemistry, Chapter 9, Problem 9.1P , additional homework tip 5

Alcohol are classified into 1^o, 2^o and 3^oalcohol based on the number of the carbon atom bonded to carbon with OH functional group. Whereas the ether are symmetrical and unsymmetreical ethers. The ether that have two identical R groups is said to be symmetrical ether and having different R group is said to unsymmetrical ether.

Strucutre,

A= 2^oalcohol

B=1^oalcohol

C=1^oalcohol

D=3^oalcohol

E=Symmetrical ether

F=Unsymmetrical ether

G=Unsymmetrical ether

Conclusion

Thus seven constitutional isomers with functional groups alcohol and ether are obtained for the molecular formula C₄H₁₀O. And the structure,

A= 2^oalcohol

B=1^oalcohol

C=1^oalcohol

D=3^oalcohol

E=Symmetrical ether

F=Unsymmetrical ether

G=Unsymmetrical ether

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Students have asked these similar questions

In the analysis of Mg content in a 25 mL sample, a titration volume of 5 mL was obtained using 0.01 M EDTA. Calculate the Mg content in the sample if the Ca content is 20 ppm

Predict the organic products that form in the reaction below: H. H+ + OH H+ Y Note: You may assume you have an excess of either reactant if the reaction requires more than one of those molecules to form the products. In the drawing area below, draw the skeletal ("line") structures of the missing organic products X and Y. You may draw the structures in any arrangement that you like, so long as they aren't touching. Explanation Check Click and drag to start drawing a structure. G X C © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | Access +

111 Carbonyl Chem Choosing reagants for a Wittig reaction What would be the best choices for the missing reagents 1 and 3 in this synthesis? 1. PPh3 3 1 2 2. n-BuLi • Draw the missing reagents in the drawing area below. You can draw them in any arrangement you like. Do not draw the missing reagent 2. If you draw 1 correctly, we'll know what it is. • Note: if one of your reagents needs to contain a halogen, use bromine. Explanation Check Click and drag to start drawing a structure. × ©2025 McGraw Hill LLC. All Rights Reserved. Terms of Use

Answer 2

Textbook Question

Chapter 9, Problem 9.1P

Draw all constitutional isomers having molecular formula C₄H₁₀0. Classify each compound as a 1°, 2°, or 3° alcohol, or a symmetrical or unsymmetrical ether.

Expert Solution & Answer

Interpretation Introduction

Interpretation:

To draw all the constitutional isomers for the molecular formula C₄H₁₀O and classify each compound as a 1°, 2°, or 3° alcohol, or a symmetrical or unsymmetrical ether.

Concept introduction:

Constitutional isomers also known as structural isomers. They are molecules that have the same chemical formula but their atoms are arranged differently. They are three main types of constitutional isomers.

a) Chain isomers – the carbon chain has a different order of carbon and hydrogen atoms.

Organic Chemistry, Chapter 9, Problem 9.1P , additional homework tip 1

b) Position isomers- a functional group of the isomers is in a different location on the molecules.

Organic Chemistry, Chapter 9, Problem 9.1P , additional homework tip 2

c) Functional isomers- the isomers contain a different functional group.

Organic Chemistry, Chapter 9, Problem 9.1P , additional homework tip 3

Answer to Problem 9.1P

Molecular formula C₄H₁₀O may be an alcohol and ether and seven isomers are shown below.

Organic Chemistry, Chapter 9, Problem 9.1P , additional homework tip 4

Strucutre,

A= 2^oalcohol

B=1^oalcohol

C=1^oalcohol

D=3^oalcohol

E=Symmetrical ether

F=Unsymmetrical ether

G=Unsymmetrical ether

Explanation of Solution

Organic Chemistry, Chapter 9, Problem 9.1P , additional homework tip 5

Alcohol are classified into 1^o, 2^o and 3^oalcohol based on the number of the carbon atom bonded to carbon with OH functional group. Whereas the ether are symmetrical and unsymmetreical ethers. The ether that have two identical R groups is said to be symmetrical ether and having different R group is said to unsymmetrical ether.

Strucutre,

A= 2^oalcohol

B=1^oalcohol

C=1^oalcohol

D=3^oalcohol

E=Symmetrical ether

F=Unsymmetrical ether

G=Unsymmetrical ether

Conclusion

Thus seven constitutional isomers with functional groups alcohol and ether are obtained for the molecular formula C₄H₁₀O. And the structure,

A= 2^oalcohol

B=1^oalcohol

C=1^oalcohol

D=3^oalcohol

E=Symmetrical ether

F=Unsymmetrical ether

G=Unsymmetrical ether

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 3

Textbook Question

Chapter 9, Problem 9.1P

Draw all constitutional isomers having molecular formula C₄H₁₀0. Classify each compound as a 1°, 2°, or 3° alcohol, or a symmetrical or unsymmetrical ether.

Expert Solution & Answer

Interpretation Introduction

Interpretation:

To draw all the constitutional isomers for the molecular formula C₄H₁₀O and classify each compound as a 1°, 2°, or 3° alcohol, or a symmetrical or unsymmetrical ether.

Concept introduction:

Constitutional isomers also known as structural isomers. They are molecules that have the same chemical formula but their atoms are arranged differently. They are three main types of constitutional isomers.

a) Chain isomers – the carbon chain has a different order of carbon and hydrogen atoms.

Organic Chemistry, Chapter 9, Problem 9.1P , additional homework tip 1

b) Position isomers- a functional group of the isomers is in a different location on the molecules.

Organic Chemistry, Chapter 9, Problem 9.1P , additional homework tip 2

c) Functional isomers- the isomers contain a different functional group.

Organic Chemistry, Chapter 9, Problem 9.1P , additional homework tip 3

Answer to Problem 9.1P

Molecular formula C₄H₁₀O may be an alcohol and ether and seven isomers are shown below.

Organic Chemistry, Chapter 9, Problem 9.1P , additional homework tip 4

Strucutre,

A= 2^oalcohol

B=1^oalcohol

C=1^oalcohol

D=3^oalcohol

E=Symmetrical ether

F=Unsymmetrical ether

G=Unsymmetrical ether

Explanation of Solution

Organic Chemistry, Chapter 9, Problem 9.1P , additional homework tip 5

Alcohol are classified into 1^o, 2^o and 3^oalcohol based on the number of the carbon atom bonded to carbon with OH functional group. Whereas the ether are symmetrical and unsymmetreical ethers. The ether that have two identical R groups is said to be symmetrical ether and having different R group is said to unsymmetrical ether.

Strucutre,

A= 2^oalcohol

B=1^oalcohol

C=1^oalcohol

D=3^oalcohol

E=Symmetrical ether

F=Unsymmetrical ether

G=Unsymmetrical ether

Conclusion

Thus seven constitutional isomers with functional groups alcohol and ether are obtained for the molecular formula C₄H₁₀O. And the structure,

A= 2^oalcohol

B=1^oalcohol

C=1^oalcohol

D=3^oalcohol

E=Symmetrical ether

F=Unsymmetrical ether

G=Unsymmetrical ether

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 4

Textbook Question

Chapter 9, Problem 9.1P

Draw all constitutional isomers having molecular formula C₄H₁₀0. Classify each compound as a 1°, 2°, or 3° alcohol, or a symmetrical or unsymmetrical ether.

Expert Solution & Answer

Interpretation Introduction

Interpretation:

To draw all the constitutional isomers for the molecular formula C₄H₁₀O and classify each compound as a 1°, 2°, or 3° alcohol, or a symmetrical or unsymmetrical ether.

Concept introduction:

Constitutional isomers also known as structural isomers. They are molecules that have the same chemical formula but their atoms are arranged differently. They are three main types of constitutional isomers.

a) Chain isomers – the carbon chain has a different order of carbon and hydrogen atoms.

Organic Chemistry, Chapter 9, Problem 9.1P , additional homework tip 1

b) Position isomers- a functional group of the isomers is in a different location on the molecules.

Organic Chemistry, Chapter 9, Problem 9.1P , additional homework tip 2

c) Functional isomers- the isomers contain a different functional group.

Organic Chemistry, Chapter 9, Problem 9.1P , additional homework tip 3

Answer to Problem 9.1P

Molecular formula C₄H₁₀O may be an alcohol and ether and seven isomers are shown below.

Organic Chemistry, Chapter 9, Problem 9.1P , additional homework tip 4

Strucutre,

A= 2^oalcohol

B=1^oalcohol

C=1^oalcohol

D=3^oalcohol

E=Symmetrical ether

F=Unsymmetrical ether

G=Unsymmetrical ether

Explanation of Solution

Organic Chemistry, Chapter 9, Problem 9.1P , additional homework tip 5

Alcohol are classified into 1^o, 2^o and 3^oalcohol based on the number of the carbon atom bonded to carbon with OH functional group. Whereas the ether are symmetrical and unsymmetreical ethers. The ether that have two identical R groups is said to be symmetrical ether and having different R group is said to unsymmetrical ether.

Strucutre,

A= 2^oalcohol

B=1^oalcohol

C=1^oalcohol

D=3^oalcohol

E=Symmetrical ether

F=Unsymmetrical ether

G=Unsymmetrical ether

Conclusion

Thus seven constitutional isomers with functional groups alcohol and ether are obtained for the molecular formula C₄H₁₀O. And the structure,

A= 2^oalcohol

B=1^oalcohol

C=1^oalcohol

D=3^oalcohol

E=Symmetrical ether

F=Unsymmetrical ether

G=Unsymmetrical ether

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 5

Textbook Question

Answer 6

Textbook Question

Answer 7

Expert Solution & Answer

Interpretation Introduction

Interpretation:

To draw all the constitutional isomers for the molecular formula C₄H₁₀O and classify each compound as a 1°, 2°, or 3° alcohol, or a symmetrical or unsymmetrical ether.

Concept introduction:

Constitutional isomers also known as structural isomers. They are molecules that have the same chemical formula but their atoms are arranged differently. They are three main types of constitutional isomers.

a) Chain isomers – the carbon chain has a different order of carbon and hydrogen atoms.

Organic Chemistry, Chapter 9, Problem 9.1P , additional homework tip 1

b) Position isomers- a functional group of the isomers is in a different location on the molecules.

Organic Chemistry, Chapter 9, Problem 9.1P , additional homework tip 2

c) Functional isomers- the isomers contain a different functional group.

Organic Chemistry, Chapter 9, Problem 9.1P , additional homework tip 3

Answer to Problem 9.1P

Molecular formula C₄H₁₀O may be an alcohol and ether and seven isomers are shown below.

Organic Chemistry, Chapter 9, Problem 9.1P , additional homework tip 4

Strucutre,

A= 2^oalcohol

B=1^oalcohol

C=1^oalcohol

D=3^oalcohol

E=Symmetrical ether

F=Unsymmetrical ether

G=Unsymmetrical ether

Explanation of Solution

Organic Chemistry, Chapter 9, Problem 9.1P , additional homework tip 5

Alcohol are classified into 1^o, 2^o and 3^oalcohol based on the number of the carbon atom bonded to carbon with OH functional group. Whereas the ether are symmetrical and unsymmetreical ethers. The ether that have two identical R groups is said to be symmetrical ether and having different R group is said to unsymmetrical ether.

Strucutre,

A= 2^oalcohol

B=1^oalcohol

C=1^oalcohol

D=3^oalcohol

E=Symmetrical ether

F=Unsymmetrical ether

G=Unsymmetrical ether

Conclusion

Thus seven constitutional isomers with functional groups alcohol and ether are obtained for the molecular formula C₄H₁₀O. And the structure,

A= 2^oalcohol

B=1^oalcohol

C=1^oalcohol

D=3^oalcohol

E=Symmetrical ether

F=Unsymmetrical ether

G=Unsymmetrical ether

Answer 8

Expert Solution & Answer

Interpretation Introduction

Interpretation:

To draw all the constitutional isomers for the molecular formula C₄H₁₀O and classify each compound as a 1°, 2°, or 3° alcohol, or a symmetrical or unsymmetrical ether.

Concept introduction:

Constitutional isomers also known as structural isomers. They are molecules that have the same chemical formula but their atoms are arranged differently. They are three main types of constitutional isomers.

a) Chain isomers – the carbon chain has a different order of carbon and hydrogen atoms.

Organic Chemistry, Chapter 9, Problem 9.1P , additional homework tip 1

b) Position isomers- a functional group of the isomers is in a different location on the molecules.

Organic Chemistry, Chapter 9, Problem 9.1P , additional homework tip 2

c) Functional isomers- the isomers contain a different functional group.

Organic Chemistry, Chapter 9, Problem 9.1P , additional homework tip 3

Answer to Problem 9.1P

Molecular formula C₄H₁₀O may be an alcohol and ether and seven isomers are shown below.

Organic Chemistry, Chapter 9, Problem 9.1P , additional homework tip 4

Strucutre,

A= 2^oalcohol

B=1^oalcohol

C=1^oalcohol

D=3^oalcohol

E=Symmetrical ether

F=Unsymmetrical ether

G=Unsymmetrical ether

Explanation of Solution

Organic Chemistry, Chapter 9, Problem 9.1P , additional homework tip 5

Alcohol are classified into 1^o, 2^o and 3^oalcohol based on the number of the carbon atom bonded to carbon with OH functional group. Whereas the ether are symmetrical and unsymmetreical ethers. The ether that have two identical R groups is said to be symmetrical ether and having different R group is said to unsymmetrical ether.

Strucutre,

A= 2^oalcohol

B=1^oalcohol

C=1^oalcohol

D=3^oalcohol

E=Symmetrical ether

F=Unsymmetrical ether

G=Unsymmetrical ether

Conclusion

Thus seven constitutional isomers with functional groups alcohol and ether are obtained for the molecular formula C₄H₁₀O. And the structure,

A= 2^oalcohol

B=1^oalcohol

C=1^oalcohol

D=3^oalcohol

E=Symmetrical ether

F=Unsymmetrical ether

G=Unsymmetrical ether

Answer 9

Expert Solution & Answer

Answer 10

Expert Solution & Answer

Answer 11

Interpretation Introduction

Interpretation:

To draw all the constitutional isomers for the molecular formula C₄H₁₀O and classify each compound as a 1°, 2°, or 3° alcohol, or a symmetrical or unsymmetrical ether.

Concept introduction:

Constitutional isomers also known as structural isomers. They are molecules that have the same chemical formula but their atoms are arranged differently. They are three main types of constitutional isomers.

a) Chain isomers – the carbon chain has a different order of carbon and hydrogen atoms.

Organic Chemistry, Chapter 9, Problem 9.1P , additional homework tip 1

b) Position isomers- a functional group of the isomers is in a different location on the molecules.

Organic Chemistry, Chapter 9, Problem 9.1P , additional homework tip 2

c) Functional isomers- the isomers contain a different functional group.

Organic Chemistry, Chapter 9, Problem 9.1P , additional homework tip 3

Answer 12

Answer to Problem 9.1P

Molecular formula C₄H₁₀O may be an alcohol and ether and seven isomers are shown below.

Organic Chemistry, Chapter 9, Problem 9.1P , additional homework tip 4

Strucutre,

A= 2^oalcohol

B=1^oalcohol

C=1^oalcohol

D=3^oalcohol

E=Symmetrical ether

F=Unsymmetrical ether

G=Unsymmetrical ether

Answer 13

Explanation of Solution

Organic Chemistry, Chapter 9, Problem 9.1P , additional homework tip 5

Alcohol are classified into 1^o, 2^o and 3^oalcohol based on the number of the carbon atom bonded to carbon with OH functional group. Whereas the ether are symmetrical and unsymmetreical ethers. The ether that have two identical R groups is said to be symmetrical ether and having different R group is said to unsymmetrical ether.

Strucutre,

A= 2^oalcohol

B=1^oalcohol

C=1^oalcohol

D=3^oalcohol

E=Symmetrical ether

F=Unsymmetrical ether

G=Unsymmetrical ether