The mass of each compound in the mixture of 10.0 g of NaNO 3 and KF dissolve in 100.0 g of water that find the temperature rise by 2.22 °C should be determined. NaNO 3(s) → NaNO 3(aq) ΔH = +20 .4 kJ/mol KF (s) → KF (aq) ΔH = -17 .7 kJ/mol Concept introduction: The Gibb’s equation of thermodynamic purposed a relation between ΔS , ΔH and ΔG with temperature. With the help of this equation the change in ΔS , ΔH and ΔG can be predicted. For any reaction, the ΔH and ΔS can be calculated with the help of: ΔrS°= Σ ΔrS°product - ∑ ΔrS°reactant ΔrH°= Σ ΔrH°product - ∑ ΔrH°reactant The change in temperature for the addition of two substances at two different temperatures can be calculated with the help of calorimetric equation: Q = m × C × ΔT Here: Q = heat change m = mass C = specific heat ΔT=change in T
The mass of each compound in the mixture of 10.0 g of NaNO 3 and KF dissolve in 100.0 g of water that find the temperature rise by 2.22 °C should be determined. NaNO 3(s) → NaNO 3(aq) ΔH = +20 .4 kJ/mol KF (s) → KF (aq) ΔH = -17 .7 kJ/mol Concept introduction: The Gibb’s equation of thermodynamic purposed a relation between ΔS , ΔH and ΔG with temperature. With the help of this equation the change in ΔS , ΔH and ΔG can be predicted. For any reaction, the ΔH and ΔS can be calculated with the help of: ΔrS°= Σ ΔrS°product - ∑ ΔrS°reactant ΔrH°= Σ ΔrH°product - ∑ ΔrH°reactant The change in temperature for the addition of two substances at two different temperatures can be calculated with the help of calorimetric equation: Q = m × C × ΔT Here: Q = heat change m = mass C = specific heat ΔT=change in T
Solution Summary: The author explains how the Gibb's equation of thermodynamic purposed a relation between S,
Science that deals with the amount of energy transferred from one equilibrium state to another equilibrium state.
Chapter 9, Problem 9.148MP
Interpretation Introduction
Interpretation:
The mass of each compound in the mixture of 10.0 g of NaNO3 and KF dissolve in 100.0 g of water that find the temperature rise by 2.22 °C should be determined.
The Gibb’s equation of thermodynamic purposed a relation between ΔS, ΔH and ΔG with temperature. With the help of this equation the change in ΔS, ΔH and ΔG can be predicted. For any reaction, the ΔH and ΔS can be calculated with the help of:
7)
8)
FCI II
-C-C-C=C-C
||
Br Br
||
-C=C-Br
-CEC-C-C-
10)
11)
F Br
i
OH
مله
12)
Br
i
13)
14)
15)
CH3CHFCHFC=CH
C(OH)Br2CHF(CH2)4CH2CH3
CH3(CH2)3CH=CH(CH2)2CH3
Name
1) 3-fluoro, 1-butene
2) 2-heptene
2,3-difluoro-
1-pentene
4) 6-iodo,4-methyl-
2-decyne
5) 4,4-dibromo-
1,2-butandiol
Complete structural formula
F
-C=C-C-C-
Line formula
Condensed structural formula
N
F
CH2=CHCHFCH3
1.
Part 1: Naming Organic Compounds
он
H₁C-C-CH3
CH3
Br
CI CI
2. Br-CH-CH-CH₂
H₂C-CH-C= -CH-CH2-CH3
3.
HC-CH-CH-C-OH
5. H₂C-CH-CH₂-OH
7.
OH
4.
CH
CH₂-CH₂
6.
сно
CH-CH-CH-CH₂-CH₂
H₁₂C-CH-CH-CH-CH₁₂-CH₁₂
8.
OH
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Calorimetry Concept, Examples and Thermochemistry | How to Pass Chemistry; Author: Melissa Maribel;https://www.youtube.com/watch?v=nSh29lUGj00;License: Standard YouTube License, CC-BY