(a)
Interpretation:
The need of
Concept Introduction:
A buffer solution is a mixture of weak acid or base with its conjugate base that resists any change in pH of the solution even after the addition of a little amount of acid or base. Thus, there is no change in pH of buffer solution even after the addition of acid or base to the solution.
This is because weak acid reacts with excess ions to form its conjugate base and water whereas, the conjugate base reacts with excess ions to form a respective weak acid.
(b)
Interpretation:
The effect on concentration of
Concept Introduction:
A buffer solution is a mixture of weak acid or base with its conjugate base that resists any change in pH of the solution even after the addition of a little amount of acid or base. Thus, there is no change in pH of buffer solution even after the addition of acid or base to the solution.
This is because weak acid reacts with excess ions to form its conjugate base and water whereas the conjugate base reacts with excess ions to form a respective weak acid.
(c)
Interpretation:
The effect on concentration of
Concept Introduction:
A buffer solution is a mixture of weak acid or base with its conjugate base that resists any change in pH of the solution even after the addition of a little amount of acid or base. Thus, there is no change in pH of buffer solution even after the addition of acid or base to the solution.
This is because weak acid reacts with excess ions to form its conjugate base and water whereas, the conjugate base reacts with excess ions to form a respective weak acid.
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General, Organic, & Biological Chemistry
- Enough water is added to the buffer in Question 30 to make the total volume 5.00 L. (a) Calculate the pH of the buffer. (b) Calculate the pH of the buffer after adding 0.0250 mol of HCl to 0.376 L of the buffer. (c) Calculate the pH of the buffer after adding 0.0250 mol of KOH to 0.376 L of the buffer. (d) Compare your answers to Question 30 (a-c) with your answers to (a-c) of this problem. (e) Comment on the effect of dilution on the pH of a buffer and on its buffer capacity. Âarrow_forwardWater is accidentally added to 350.00 mL of a stock solution of 6.00 M HCI. A 75.00-mL sample of the diluted solution is titrated to pH 7.00 with 78.8 mL of 4.85 M NaOH. How much water was accidentally added? (Assume that volumes are additive.)arrow_forwardA solution made up of 1.0 M NH3 and 0.50 M (NH4)2SO4 has a pH of 9.26. a Write the net ionic equation that represents the reaction of this solution with a strong acid. b Write the net ionic equation that represents the reaction of this solution with a strong base. c To 100. mL of this solution, 10.0 mL of 1.00 M HCl is added. How many moles of NH3 and NH4+ are present in the reaction system before and after the addition of the HCl? What is the pH of the resulting solution? d Why did the pH change only slightly upon the addition of HCl?arrow_forward
- A friend asks the following: Consider a buffered solution made up of the weak acid HA and its salt NaA. If a strong base like NaOH is added, the HA reacts with the OH to form A. Thus the amount of acid (HA) is decreased, and the amount of base (A) is increased. Analogously, adding HCI to the buffered solution forms more of the acid (HA) by reacting with the base (A). Thus how can we claim that a buffered solution resists changes in the pH of the solution? How would you explain buffering to this friend?arrow_forwardEach box represents an acid solution at equilibrium. Squares represent H+ ions. Circles represent anions. (Although the anions have different identities in each figure, they are all represented as circles.) Water molecules are not shown. Assume that all solutions have the same volume. (a) Which figure represents the strongest acid? (b) Which figure represents the acid with the smallest Ka? (c) Which figure represents the acid with the lowest pH?arrow_forwardMethyl orange, HMO, is a common acid-base indicator. In solution it ionizes according to the equation: HMOaqH+aq+MO-aqredyellow If methyl orange is added to distilled water, the solution turns yellow. If 1 drop or two of 6 M HCl is added to the yellow solution, it turns red. If to that solution one adds a few drops of 6 M NaOH, the color reverts to yellow. a. Why does adding 6 M HCl to the yellow solution of methyl orange tend to cause the color to change to red? Note that in solution HCl exists as H+ and Cl- ions. b. Why does adding 6 M NaOH to the red solution tend to make it turn back to yellow? Note that in solution NaOH exists as Na+ and OH- ions. How does increasing OH- shift Reaction 3 in the discussion section? How would the resulting change in H+ affect the dissociation reaction of HMO?arrow_forward
- A quantity of 0.25 M sodium hydroxide is added to a solution containing 0.15 mol of acetic acid. The final volume of the solution is 375 mL and the pH of this solution is 4.45. a What is the molar concentration of the sodium acetate? b How many milliliters of sodium hydroxide were added to the original solution? c What was the original concentration of the acetic acid?arrow_forwardA solution of KOH has a pH of 13.29. It requires 27.66 mL of 0.2500 M HCI to reach the equivalence point. (a) What is the volume of the KOH solution? (b) What is the pH at the equivalence point? (c) What is [K+] and [Cl-] at the equivalence point? Assume volumes are additive.arrow_forwardUse the same symbols as in Question 61 ( = anion, =OH) for the box below. (a) Fill in a similar box (representing one liter of the same solution) after 2 mol of H+ (2) have been added. Indicate whether the resulting solution is an acid, base, or buffer. (b) Follow the directions of part (a) for the resulting solution after 2 mol of OH- (2 ) have been added. (c) Follow the directions of part (a) for the resulting solution after 5 mol of OH- (5 ) have been added. (Hint: Write the equation for the reaction before you draw the results.)arrow_forward
- 8-71 Explain why you do not need to know the chemical formula of a buffer compound to use it.arrow_forward1. What is the pH after 25.0 ml of 0.100 M NaOH has been added to 50.0 ml of 0.100 M HCl? 1.00 1.48 7.00 13.00arrow_forwardHow many moles of sodium acetate must be added to 2.0 L of 0.10 M acetic acid to give a solution that has a pH equal to 4.90? Ignore the volume change due to the addition of sodium acetate.arrow_forward
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