Chapter 9, Problem 9.103E

Interpretation Introduction

(a)

Interpretation:

The number of moles of oxalic acid in the $\text{20}\text{.00-mL}$ sample is to be determined.

Concept introduction:

Molarity is the ratio of the number of moles of solute to the volume of the solution in liters.

The molarity is calculated by the formula,

$\text{Molarity}=\frac{\text{Number}\text{of}\text{moles}}{\text{Volume}\left(\text{mL}\right)}\times \frac{1000\text{mL}}{1\text{L}}$

Interpretation Introduction

(b)

Interpretation:

The molarity of the oxalic acid solution is to be determined.

Concept introduction:

Molarity is the ratio of the number of moles of solute to the volume of the solution in liters.

The molarity is calculated by the formula,

$\text{Molarity}=\frac{\text{Number}\text{of}\text{moles}}{\text{Volume}\left(\text{mL}\right)}\times \frac{1000\text{mL}}{1\text{L}}$

Interpretation Introduction

(c)

Interpretation:

The number of grams of oxalic acid in the $\text{20}\text{.00-mL}$ sample is to be determined.

Concept introduction:

The formula to calculate number of moles is,

$n=\frac{m}{M}$

Where,

• $m$ represents the mass of the substance.

• $M$ represents the molar mass of the substance