Introduction to Chemistry
Introduction to Chemistry
4th Edition
ISBN: 9781259288722
Author: BAUER
Publisher: MCG
Question
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Chapter 9, Problem 85QP

(a)

Interpretation Introduction

Interpretation:

The calculation of the number of moles and mass of CH4 gas.

(a)

Expert Solution
Check Mark

Explanation of Solution

Ideal gas law gives a relation between pressure P , volume V , temperature T , and the number of moles n of gas. The gas law equation is:

PVnTPV=nRT ...... 1

Where, R is the universal gas constant and its values changes in accordance with the units of pressure, volume and temperature.

The conversion factor of temperature from Celsius to Kelvin is as follows:

°C=273.15+K

For 87.5°C ,

°C=87.5°C+273.15=360.7 K

The conversion factor that is used to convert pressure value from torr to atm is as follows:

760 torr=1 atm1=1 atm760 torr

For 722 torr ,

722 torr=1760 atm×722=0.95 atm

Recall equation (1),

PV=nRT .

Substitute 7.62 L for V , 0.08206 L atm mol1K1 for R , 360.7 K for T and 0.95 atm for P in the above equation:

0.95 atm×7.62 L=n×0.08206 L atm mol1K1×360.7 Kn=0.245 mol

The mass of gas is calculated using the given formula:

n=mM

Here, m is the mass and M is the molar mass.

Substitute 0.245 mol for n and 16 g mol1 for M in the above equation.

0.245 mol=mass16 g mol1mass=3.92 g

(b)

Interpretation Introduction

Interpretation:

The calculation of the number of moles and mass of H2 gas.

(b)

Expert Solution
Check Mark

Explanation of Solution

The conversion factor of temperature from Celsius to Kelvin is as follows:

°C=273.15+K

For 87.5°C ,

°C=87.5°C+273.15=360.7 K

The conversion factor that is used to convert pressure value from torr to atm is as follows:

760 torr=1 atm1=1 atm760 torr

For 722 torr ,

722 torr=1760 atm×722=0.95 atm

Recall equation (1),

PV=nRT .

Substitute 0.135 L for V , 0.08206 L atm mol1K1 for R , 360.7 K for T and 0.95 atm for P in the above equation:

0.95 atm×0.135 L=n×0.08206 L atm mol1K1×360.7 Kn=4.33×103 mol

The mass of gas is calculated using the given formula:

n=mM

Here, m is the mass and M is the molar mass.

Substitute 4.33×103 mol for n and 2 g mol1 for M in the above equation.

4.33×103 mol=mass 2 g mol1mass=8.74×103 g

(c)

Interpretation Introduction

Interpretation:

The calculation of the number of moles and mass of N2 gas.

(c)

Expert Solution
Check Mark

Explanation of Solution

The conversion factor of temperature from Celsius to Kelvin is as follows:

°C=273.15+K

For 87.5°C ,

°C=87.5°C+273.15=360.7 K

The conversion factor that is used to convert pressure value from torr to atm is as follows:

760 torr=1 atm1=1 atm760 torr

For 722 torr ,

722 torr=1760 atm×722=0.95 atm

Recall equation (1),

PV=nRT .

Substitute 7.62 L for V , 0.08206 L atm mol1K1 for R , 360.7 K for T and 0.95 atm for P in the above equation:

0.95 atm×8.96 L=n×0.08206 L atm mol1K1×360.7 Kn=0.288 mol

The mass of gas is calculated using the given formula:

n=mM

Here, m is the mass and M is the molar mass.

Substitute 0.288 mol for n and 28 g mol1 for M in the above equation.

0.288 mol=mass28 g mol1mass=8.06 g

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Chapter 9 Solutions

Introduction to Chemistry

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