Introduction to Chemistry
4th Edition
ISBN: 9781259288722
Author: BAUER
Publisher: MCG
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Chapter 9, Problem 88QP
Interpretation Introduction
Interpretation:
The balloon at a higher temperature, the difference in the densities of the balloons and the representation of gas particles are to be stated.
Concept Introduction:
The volume of agas is directly proportional to the temperature of the gas when the pressure of the gas is fixed. This is also known as the Charles’ Law. In mathematical terms, it is represented as shown below:
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Using reaction free energy to predict equilibrium composition
Consider the following equilibrium:
2NO2 (g) = N2O4(g)
AGº = -5.4 kJ
Now suppose a reaction vessel is filled with 4.53 atm of dinitrogen tetroxide (N2O4) at 279. °C. Answer the following questions about this system:
Under these conditions, will the pressure of N2O4 tend to rise or fall?
Is it possible to reverse this tendency by adding NO2?
In other words, if you said the pressure of N2O4 will tend to rise, can that
be changed to a tendency to fall by adding NO2? Similarly, if you said the
pressure of N2O4 will tend to fall, can that be changed to a tendency to
'2'
rise by adding NO2?
If you said the tendency can be reversed in the second question, calculate
the minimum pressure of NO 2 needed to reverse it.
Round your answer to 2 significant digits.
00
rise
☐ x10
fall
yes
no
☐ atm
G
Ar
1
Why do we analyse salt?
Curved arrows are used to illustrate the flow of electrons. Using
the provided starting and product structures, draw the curved
electron-pushing arrows for the following reaction or
mechanistic step(s).
Be sure to account for all bond-breaking and bond-making
steps.
H
H
CH3OH, H+
H
Select to Add Arrows
H°
0:0
'H
+
Q
HH
■ Select to Add Arrows
CH3OH,
H*
H.
H
CH3OH, H+
HH
■ Select to Add Arrows i
Please select a drawing or reagent from the question area
Chapter 9 Solutions
Introduction to Chemistry
Ch. 9 - Prob. 1QCCh. 9 - Prob. 2QCCh. 9 - Prob. 3QCCh. 9 - Prob. 4QCCh. 9 - Prob. 5QCCh. 9 - Prob. 1PPCh. 9 - Prob. 2PPCh. 9 - What pressure is needed to compress 455 mL of...Ch. 9 - Prob. 4PPCh. 9 - Prob. 5PP
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