The maximum wavelength of the radiation that would be diffracted by N a C l crystal has to be determined. The frequency of radiation and the energy associated with one photon and one mole of photons of the radiation have to be calculated. This radiation belongs to which region of the spectrum has to be determined. Concept Introduction: The maximum wavelength of the radiation that would be diffracted by a crystal is equal to its unit cell edge length. Electromagnetic radiation consists of oscillating, perpendicular electric and magnetic fields that travel through space at the same rate. The frequency of electromagnetic radiation is related to its wavelength by equation as given below. ν λ = c Where, ν = Frequency of electromagnetic radiation, λ = Wavelength of electromagnetic radiation and c = Velocity of light. The energy of radiation is proportional to its frequency of radiation according to the equation as given below. E = h ν Where, h = Planck’s constant = 6.626 × 10 − 34 J s Frequency and energy range of electromagnetic radiation: Frequency Range ( H z ) Energy Range ( J ) Gamma rays 10 20 − 10 24 10 − 14 − 10 − 10 X − rays 10 17 − 10 20 10 − 17 − 10 − 14 UV 10 15 − 10 17 10 − 20 − 10 − 18 IR 10 13 − 10 14 10 − 22 − 10 − 20 Microwaves 3 × 10 11 − 10 13 10 − 25 − 10 − 22 Radiowaves < 3 × 10 11 10 − 30 − 10 − 25

Question

Want to see more full solutions like this?

Answer 1

Question

Chapter 9, Problem 71QRT

Interpretation Introduction

Interpretation:

The maximum wavelength of the radiation that would be diffracted by NaCl crystal has to be determined. The frequency of radiation and the energy associated with one photon and one mole of photons of the radiation have to be calculated. This radiation belongs to which region of the spectrum has to be determined.

Concept Introduction:

The maximum wavelength of the radiation that would be diffracted by a crystal is equal to its unit cell edge length.

Electromagnetic radiation consists of oscillating, perpendicular electric and magnetic fields that travel through space at the same rate. The frequency of electromagnetic radiation is related to its wavelength by equation as given below.

νλ=c

Where, ν= Frequency of electromagnetic radiation, λ= Wavelength of electromagnetic radiation and c= Velocity of light.

The energy of radiation is proportional to its frequency of radiation according to the equation as given below.

E=hν

Where, h= Planck’s constant =6.626×10−34J s

Frequency and energy range of electromagnetic radiation:

Frequency Range (Hz) Energy Range (J)
Gamma rays 1020−1024 10−14−10−10
X− rays 1017−1020 10−17−10−14
UV 1015−1017 10−20−10−18
IR 1013−1014 10−22−10−20
Microwaves 3×1011−1013 10−25−10−22
Radiowaves <3×1011 10−30−10−25

Expert Solution & Answer

Answer to Problem 71QRT

The frequency of radiation of one photon and one mole photons are found out to be 5.30×1017s-1 and 31.91×1040s-1 respectively. The energy associated with one photon and one mole of photons are found to be 3.51×10-16 J and 2.11×108 J respectively.

Explanation of Solution

The maximum wavelength of the radiation that would be diffracted by a crystal is equal to its unit cell edge length. So λmax for NaCl is 566 pm which is the unit cell edge length.

(a) Then, the frequency of radiation can be calculated as given below.

ν=cλ=2.998×108m/s566 pm×10−12m1 pm=5.30×1017s−1.

Therefore, the frequency of radiation of one photon is found out to be 5.30×1017s-1.

The energy associated with one photon can also be calculated as follows,

E=hν=(6.626×10−34J s)×(5.30×1017s−1)=3.51×10-16 J.

(b) The frequency of radiation of one mole photons can be calculated as follows,

1 mol photon ×5.30×1017s-11 photon×6.022×1023 photons1 mol photon=31.91×1040s-1.

The energy associated with one mole photons can also be calculated as follows,

E=hν=(6.626×10−34J s)×(31.91×1040s−1)=2.11×108 J.

The energy and frequency range are coming under X-ray region of electromagnetic spectrum.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Students have asked these similar questions

Find a mole of : H2SO4 (15 ml 3.0 M) NaOH ( 18 mL 2.5 M) Acetic anhydride (3.0 mL)

For the mechanism, show everything, lone paires, charges and arrow please

molecule 0= OH ☐ ☐ type of molecule (check all that apply) fatty acid monoglyceride diglyceride triglyceride saturated unsaturated monounsaturated ☐ polyunsaturated ☐ ☐ ☐ ☐ ☐ 010 0 0 0 0 0 0 ☐ ☐ ☐ ☐☐☐☐ U omega-3 omega-6 fatty acid monoglyceride diglyceride triglyceride saturated unsaturated monounsaturated polyunsaturated omega-3 omega-6 fatty acid monoglyceride diglyceride triglyceride saturated unsaturated monounsaturated polyunsaturated omega-3 omega-6 OH OH

Answer 2

Question

Chapter 9, Problem 71QRT

Interpretation Introduction

Interpretation:

The maximum wavelength of the radiation that would be diffracted by NaCl crystal has to be determined. The frequency of radiation and the energy associated with one photon and one mole of photons of the radiation have to be calculated. This radiation belongs to which region of the spectrum has to be determined.

Concept Introduction:

The maximum wavelength of the radiation that would be diffracted by a crystal is equal to its unit cell edge length.

Electromagnetic radiation consists of oscillating, perpendicular electric and magnetic fields that travel through space at the same rate. The frequency of electromagnetic radiation is related to its wavelength by equation as given below.

νλ=c

Where, ν= Frequency of electromagnetic radiation, λ= Wavelength of electromagnetic radiation and c= Velocity of light.

The energy of radiation is proportional to its frequency of radiation according to the equation as given below.

E=hν

Where, h= Planck’s constant =6.626×10−34J s

Frequency and energy range of electromagnetic radiation:

Frequency Range (Hz) Energy Range (J)
Gamma rays 1020−1024 10−14−10−10
X− rays 1017−1020 10−17−10−14
UV 1015−1017 10−20−10−18
IR 1013−1014 10−22−10−20
Microwaves 3×1011−1013 10−25−10−22
Radiowaves <3×1011 10−30−10−25

Expert Solution & Answer

Answer to Problem 71QRT

The frequency of radiation of one photon and one mole photons are found out to be 5.30×1017s-1 and 31.91×1040s-1 respectively. The energy associated with one photon and one mole of photons are found to be 3.51×10-16 J and 2.11×108 J respectively.

Explanation of Solution

The maximum wavelength of the radiation that would be diffracted by a crystal is equal to its unit cell edge length. So λmax for NaCl is 566 pm which is the unit cell edge length.

(a) Then, the frequency of radiation can be calculated as given below.

ν=cλ=2.998×108m/s566 pm×10−12m1 pm=5.30×1017s−1.

Therefore, the frequency of radiation of one photon is found out to be 5.30×1017s-1.

The energy associated with one photon can also be calculated as follows,

E=hν=(6.626×10−34J s)×(5.30×1017s−1)=3.51×10-16 J.

(b) The frequency of radiation of one mole photons can be calculated as follows,

1 mol photon ×5.30×1017s-11 photon×6.022×1023 photons1 mol photon=31.91×1040s-1.

The energy associated with one mole photons can also be calculated as follows,

E=hν=(6.626×10−34J s)×(31.91×1040s−1)=2.11×108 J.

The energy and frequency range are coming under X-ray region of electromagnetic spectrum.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 3

Question

Chapter 9, Problem 71QRT

Interpretation Introduction

Interpretation:

The maximum wavelength of the radiation that would be diffracted by NaCl crystal has to be determined. The frequency of radiation and the energy associated with one photon and one mole of photons of the radiation have to be calculated. This radiation belongs to which region of the spectrum has to be determined.

Concept Introduction:

The maximum wavelength of the radiation that would be diffracted by a crystal is equal to its unit cell edge length.

Electromagnetic radiation consists of oscillating, perpendicular electric and magnetic fields that travel through space at the same rate. The frequency of electromagnetic radiation is related to its wavelength by equation as given below.

νλ=c

Where, ν= Frequency of electromagnetic radiation, λ= Wavelength of electromagnetic radiation and c= Velocity of light.

The energy of radiation is proportional to its frequency of radiation according to the equation as given below.

E=hν

Where, h= Planck’s constant =6.626×10−34J s

Frequency and energy range of electromagnetic radiation:

Frequency Range (Hz) Energy Range (J)
Gamma rays 1020−1024 10−14−10−10
X− rays 1017−1020 10−17−10−14
UV 1015−1017 10−20−10−18
IR 1013−1014 10−22−10−20
Microwaves 3×1011−1013 10−25−10−22
Radiowaves <3×1011 10−30−10−25

Expert Solution & Answer

Answer to Problem 71QRT

The frequency of radiation of one photon and one mole photons are found out to be 5.30×1017s-1 and 31.91×1040s-1 respectively. The energy associated with one photon and one mole of photons are found to be 3.51×10-16 J and 2.11×108 J respectively.

Explanation of Solution

The maximum wavelength of the radiation that would be diffracted by a crystal is equal to its unit cell edge length. So λmax for NaCl is 566 pm which is the unit cell edge length.

(a) Then, the frequency of radiation can be calculated as given below.

ν=cλ=2.998×108m/s566 pm×10−12m1 pm=5.30×1017s−1.

Therefore, the frequency of radiation of one photon is found out to be 5.30×1017s-1.

The energy associated with one photon can also be calculated as follows,

E=hν=(6.626×10−34J s)×(5.30×1017s−1)=3.51×10-16 J.

(b) The frequency of radiation of one mole photons can be calculated as follows,

1 mol photon ×5.30×1017s-11 photon×6.022×1023 photons1 mol photon=31.91×1040s-1.

The energy associated with one mole photons can also be calculated as follows,

E=hν=(6.626×10−34J s)×(31.91×1040s−1)=2.11×108 J.

The energy and frequency range are coming under X-ray region of electromagnetic spectrum.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 4

Question

Chapter 9, Problem 71QRT

Interpretation Introduction

Interpretation:

The maximum wavelength of the radiation that would be diffracted by NaCl crystal has to be determined. The frequency of radiation and the energy associated with one photon and one mole of photons of the radiation have to be calculated. This radiation belongs to which region of the spectrum has to be determined.

Concept Introduction:

The maximum wavelength of the radiation that would be diffracted by a crystal is equal to its unit cell edge length.

Electromagnetic radiation consists of oscillating, perpendicular electric and magnetic fields that travel through space at the same rate. The frequency of electromagnetic radiation is related to its wavelength by equation as given below.

νλ=c

Where, ν= Frequency of electromagnetic radiation, λ= Wavelength of electromagnetic radiation and c= Velocity of light.

The energy of radiation is proportional to its frequency of radiation according to the equation as given below.

E=hν

Where, h= Planck’s constant =6.626×10−34J s

Frequency and energy range of electromagnetic radiation:

Frequency Range (Hz) Energy Range (J)
Gamma rays 1020−1024 10−14−10−10
X− rays 1017−1020 10−17−10−14
UV 1015−1017 10−20−10−18
IR 1013−1014 10−22−10−20
Microwaves 3×1011−1013 10−25−10−22
Radiowaves <3×1011 10−30−10−25

Expert Solution & Answer

Answer to Problem 71QRT

The frequency of radiation of one photon and one mole photons are found out to be 5.30×1017s-1 and 31.91×1040s-1 respectively. The energy associated with one photon and one mole of photons are found to be 3.51×10-16 J and 2.11×108 J respectively.

Explanation of Solution

The maximum wavelength of the radiation that would be diffracted by a crystal is equal to its unit cell edge length. So λmax for NaCl is 566 pm which is the unit cell edge length.

(a) Then, the frequency of radiation can be calculated as given below.

ν=cλ=2.998×108m/s566 pm×10−12m1 pm=5.30×1017s−1.

Therefore, the frequency of radiation of one photon is found out to be 5.30×1017s-1.

The energy associated with one photon can also be calculated as follows,

E=hν=(6.626×10−34J s)×(5.30×1017s−1)=3.51×10-16 J.

(b) The frequency of radiation of one mole photons can be calculated as follows,

1 mol photon ×5.30×1017s-11 photon×6.022×1023 photons1 mol photon=31.91×1040s-1.

The energy associated with one mole photons can also be calculated as follows,

E=hν=(6.626×10−34J s)×(31.91×1040s−1)=2.11×108 J.

The energy and frequency range are coming under X-ray region of electromagnetic spectrum.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 5

Chapter 9, Problem 71QRT

Interpretation Introduction

Interpretation:

The maximum wavelength of the radiation that would be diffracted by NaCl crystal has to be determined. The frequency of radiation and the energy associated with one photon and one mole of photons of the radiation have to be calculated. This radiation belongs to which region of the spectrum has to be determined.

Concept Introduction:

The maximum wavelength of the radiation that would be diffracted by a crystal is equal to its unit cell edge length.

Electromagnetic radiation consists of oscillating, perpendicular electric and magnetic fields that travel through space at the same rate. The frequency of electromagnetic radiation is related to its wavelength by equation as given below.

νλ=c

Where, ν= Frequency of electromagnetic radiation, λ= Wavelength of electromagnetic radiation and c= Velocity of light.

The energy of radiation is proportional to its frequency of radiation according to the equation as given below.

E=hν

Where, h= Planck’s constant =6.626×10−34J s

Frequency and energy range of electromagnetic radiation:

Frequency Range (Hz) Energy Range (J)
Gamma rays 1020−1024 10−14−10−10
X− rays 1017−1020 10−17−10−14
UV 1015−1017 10−20−10−18
IR 1013−1014 10−22−10−20
Microwaves 3×1011−1013 10−25−10−22
Radiowaves <3×1011 10−30−10−25

Expert Solution & Answer

Answer to Problem 71QRT

The frequency of radiation of one photon and one mole photons are found out to be 5.30×1017s-1 and 31.91×1040s-1 respectively. The energy associated with one photon and one mole of photons are found to be 3.51×10-16 J and 2.11×108 J respectively.

Explanation of Solution

The maximum wavelength of the radiation that would be diffracted by a crystal is equal to its unit cell edge length. So λmax for NaCl is 566 pm which is the unit cell edge length.

(a) Then, the frequency of radiation can be calculated as given below.

ν=cλ=2.998×108m/s566 pm×10−12m1 pm=5.30×1017s−1.

Therefore, the frequency of radiation of one photon is found out to be 5.30×1017s-1.

The energy associated with one photon can also be calculated as follows,

E=hν=(6.626×10−34J s)×(5.30×1017s−1)=3.51×10-16 J.

(b) The frequency of radiation of one mole photons can be calculated as follows,

1 mol photon ×5.30×1017s-11 photon×6.022×1023 photons1 mol photon=31.91×1040s-1.

The energy associated with one mole photons can also be calculated as follows,

E=hν=(6.626×10−34J s)×(31.91×1040s−1)=2.11×108 J.

The energy and frequency range are coming under X-ray region of electromagnetic spectrum.

Answer 6

Chapter 9, Problem 71QRT

Interpretation Introduction

Interpretation:

The maximum wavelength of the radiation that would be diffracted by NaCl crystal has to be determined. The frequency of radiation and the energy associated with one photon and one mole of photons of the radiation have to be calculated. This radiation belongs to which region of the spectrum has to be determined.

Concept Introduction:

The maximum wavelength of the radiation that would be diffracted by a crystal is equal to its unit cell edge length.

Electromagnetic radiation consists of oscillating, perpendicular electric and magnetic fields that travel through space at the same rate. The frequency of electromagnetic radiation is related to its wavelength by equation as given below.

νλ=c

Where, ν= Frequency of electromagnetic radiation, λ= Wavelength of electromagnetic radiation and c= Velocity of light.

The energy of radiation is proportional to its frequency of radiation according to the equation as given below.

E=hν

Where, h= Planck’s constant =6.626×10−34J s

Frequency and energy range of electromagnetic radiation:

Frequency Range (Hz) Energy Range (J)
Gamma rays 1020−1024 10−14−10−10
X− rays 1017−1020 10−17−10−14
UV 1015−1017 10−20−10−18
IR 1013−1014 10−22−10−20
Microwaves 3×1011−1013 10−25−10−22
Radiowaves <3×1011 10−30−10−25

Expert Solution & Answer

Answer to Problem 71QRT

The frequency of radiation of one photon and one mole photons are found out to be 5.30×1017s-1 and 31.91×1040s-1 respectively. The energy associated with one photon and one mole of photons are found to be 3.51×10-16 J and 2.11×108 J respectively.

Explanation of Solution

The maximum wavelength of the radiation that would be diffracted by a crystal is equal to its unit cell edge length. So λmax for NaCl is 566 pm which is the unit cell edge length.

(a) Then, the frequency of radiation can be calculated as given below.

ν=cλ=2.998×108m/s566 pm×10−12m1 pm=5.30×1017s−1.

Therefore, the frequency of radiation of one photon is found out to be 5.30×1017s-1.

The energy associated with one photon can also be calculated as follows,

E=hν=(6.626×10−34J s)×(5.30×1017s−1)=3.51×10-16 J.

(b) The frequency of radiation of one mole photons can be calculated as follows,

1 mol photon ×5.30×1017s-11 photon×6.022×1023 photons1 mol photon=31.91×1040s-1.

The energy associated with one mole photons can also be calculated as follows,

E=hν=(6.626×10−34J s)×(31.91×1040s−1)=2.11×108 J.

The energy and frequency range are coming under X-ray region of electromagnetic spectrum.

Answer 7

Chapter 9, Problem 71QRT

Interpretation Introduction

Interpretation:

The maximum wavelength of the radiation that would be diffracted by NaCl crystal has to be determined. The frequency of radiation and the energy associated with one photon and one mole of photons of the radiation have to be calculated. This radiation belongs to which region of the spectrum has to be determined.

Concept Introduction:

The maximum wavelength of the radiation that would be diffracted by a crystal is equal to its unit cell edge length.

Electromagnetic radiation consists of oscillating, perpendicular electric and magnetic fields that travel through space at the same rate. The frequency of electromagnetic radiation is related to its wavelength by equation as given below.

νλ=c

Where, ν= Frequency of electromagnetic radiation, λ= Wavelength of electromagnetic radiation and c= Velocity of light.

The energy of radiation is proportional to its frequency of radiation according to the equation as given below.

E=hν

Where, h= Planck’s constant =6.626×10−34J s

Frequency and energy range of electromagnetic radiation:

Frequency Range (Hz) Energy Range (J)
Gamma rays 1020−1024 10−14−10−10
X− rays 1017−1020 10−17−10−14
UV 1015−1017 10−20−10−18
IR 1013−1014 10−22−10−20
Microwaves 3×1011−1013 10−25−10−22
Radiowaves <3×1011 10−30−10−25

Answer 8

Expert Solution & Answer

Answer to Problem 71QRT

The frequency of radiation of one photon and one mole photons are found out to be 5.30×1017s-1 and 31.91×1040s-1 respectively. The energy associated with one photon and one mole of photons are found to be 3.51×10-16 J and 2.11×108 J respectively.

Answer 9

Expert Solution & Answer

Answer 10

Expert Solution & Answer

Answer 11

Explanation of Solution

The maximum wavelength of the radiation that would be diffracted by a crystal is equal to its unit cell edge length. So λmax for NaCl is 566 pm which is the unit cell edge length.

(a) Then, the frequency of radiation can be calculated as given below.

ν=cλ=2.998×108m/s566 pm×10−12m1 pm=5.30×1017s−1.

Therefore, the frequency of radiation of one photon is found out to be 5.30×1017s-1.

The energy associated with one photon can also be calculated as follows,

E=hν=(6.626×10−34J s)×(5.30×1017s−1)=3.51×10-16 J.

(b) The frequency of radiation of one mole photons can be calculated as follows,

1 mol photon ×5.30×1017s-11 photon×6.022×1023 photons1 mol photon=31.91×1040s-1.

The energy associated with one mole photons can also be calculated as follows,

E=hν=(6.626×10−34J s)×(31.91×1040s−1)=2.11×108 J.

The energy and frequency range are coming under X-ray region of electromagnetic spectrum.

Answer 12

Ch. 9.1 - Prob. 9.1CE Ch. 9.2 - Prob. 9.2CE Ch. 9.2 - Prob. 9.1PSP Ch. 9.2 - What mass (g) of ethanol, CH3CH2OH(), can be...Ch. 9.3 - Prob. 9.3CE Ch. 9.3 - Prob. 9.4CE Ch. 9.3 - Prob. 9.3PSP Ch. 9.4 - What types of solids are these substances? (a) The...Ch. 9.4 - Prob. 9.5PSP Ch. 9.4 - Prob. 9.5E

Concept explainers

Videos

Answer to Problem 71QRT

Explanation of Solution

Want to see more full solutions like this?

Chapter 9 Solutions

	Frequency Range (Hz)	Energy Range (J)
Gamma rays	1020−1024	10−14−10−10
X− rays	1017−1020	10−17−10−14
UV	1015−1017	10−20−10−18
IR	1013−1014	10−22−10−20
Microwaves	3×1011−1013	10−25−10−22
Radiowaves	<3×1011	10−30−10−25