Loose Leaf for Engineering Circuit Analysis Format: Loose-leaf
9th Edition
ISBN: 9781259989452
Author: Hayt
Publisher: Mcgraw Hill Publishers
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Chapter 9, Problem 5E
You go to construct the circuit in Exercise 1, only to find no 1 kΩ resistors. In fact, all you can find in addition to the capacitor and inductor is a 1-meter-long piece of 24 AWG soft solid copper wire. Connecting it in parallel to the two components you did find, compute the value of α, ω0, s1 and s2, and verify that the circuit is still overdamped.
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Example2:-
8. = e.A nia +2.1 =
Find the maximum steady-state power capability of a system consisting of a
generator equivalent reactance of 0.4pu connected to an infinite bus through a
series reactance of 1.0 p.u. The terminal voltage of the generator is held at1.10 p.u.
and the voltage of the infinite bus is 1.0 p.u.
B) A 60-Hz generator is supplying 60% of P max to an infinite bus through a reactive network.
A fault occurs which increases the reactance of the network between the generator internal
voltage and the infinite bus by 400%. When the fault is cleared, the maximum power that can
be delivered is 80% of the original maximum value. Determine the critical clearing angle for
the condition described.
In the circuit shown, let Vs-9, R₁-8, R2-2, and R3-4. Use Nodal analysis to determine the current lo. In
particular find:
V2=
10=
A
The relative tolerance for this problem is 5 %.
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V₁
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Chapter 9 Solutions
Loose Leaf for Engineering Circuit Analysis Format: Loose-leaf
Ch. 9.1 - A parallel RLC circuit contains a 100 2 resistor...Ch. 9.2 - After being open for a long time, the switch in...Ch. 9.2 - Prob. 3PCh. 9.2 - Prob. 4PCh. 9.3 - (a) Choose R1 in the circuit of Fig. 9.14 so that...Ch. 9.4 - Prob. 6PCh. 9.5 - Prob. 7PCh. 9.5 - Prob. 8PCh. 9.6 - Let is = 10u(t) 20u(t) A in Fig. 9.31. Find (a)...Ch. 9.6 - Let vs = 10 + 20u(t) V in the circuit of Fig....
Ch. 9.7 - Alter the capacitor value and voltage source in...Ch. 9 - For a certain source-free parallel RLC circuit, R...Ch. 9 - Element values of 10 mF and 2 nH are employed in...Ch. 9 - If a parallel RLC circuit is constructed from...Ch. 9 - Prob. 4ECh. 9 - You go to construct the circuit in Exercise 1,...Ch. 9 - A parallel RLC circuit has inductance 2 mH and...Ch. 9 - Prob. 7ECh. 9 - A parallel RLC circuit has R = 1 k, L = 50 mH. and...Ch. 9 - Prob. 9ECh. 9 - Prob. 10ECh. 9 - The current flowing through a 5 resistor in a...Ch. 9 - For the circuit of Fig.9.40, obtain an expression...Ch. 9 - Consider the circuit depicted in Fig. 9.40. (a)...Ch. 9 - With regard to the circuit represented in Fig....Ch. 9 - (a) Assuming the passive sign convention, obtain...Ch. 9 - With regard to the circuit presented in Fig. 9.42,...Ch. 9 - Obtain expressions for the current i(t) and...Ch. 9 - FIGURE 9.43 Replace the 14 resistor in the...Ch. 9 - Design a complete source-free parallel RLC circuit...Ch. 9 - For the circuit represented by Fig. 9.44, the two...Ch. 9 - Prob. 21ECh. 9 - Prob. 22ECh. 9 - A critically damped parallel RLC circuit is...Ch. 9 - A source-free parallel RLC circuit has an initial...Ch. 9 - A critically damped parallel RLC circuit is...Ch. 9 - For the circuit of Fig. 9.45, is(t) = 30u(t) mA....Ch. 9 - Prob. 27ECh. 9 - The circuit of Fig. 9.44 is rebuilt such that the...Ch. 9 - Prob. 29ECh. 9 - Prob. 30ECh. 9 - The source-free circuit depicted in Fig. 9.1 is...Ch. 9 - (a) Graph the current i for the circuit described...Ch. 9 - Analyze the circuit described in Exercise 31 to...Ch. 9 - A source-free parallel RLC circuit has capacitance...Ch. 9 - Prob. 35ECh. 9 - Obtain an expression for vL(t), t 0, for the...Ch. 9 - For the circuit of Fig. 9.47, determine (a) the...Ch. 9 - (a) Design a parallel RLC circuit that provides a...Ch. 9 - The circuit depicted in Fig. 9.48 is just barely...Ch. 9 - When constructing the circuit of Fig. 9.48, you...Ch. 9 - The circuit of Fig. 9.22a is constructed with a...Ch. 9 - Prob. 42ECh. 9 - Prob. 43ECh. 9 - The simple three-element series RLC circuit of...Ch. 9 - Prob. 45ECh. 9 - Prob. 46ECh. 9 - Prob. 47ECh. 9 - With reference to the series RLC circuit of Fig....Ch. 9 - Obtain an expression for i1 as labeled in Fig....Ch. 9 - The circuit in Fig. 9.52 has the switch in...Ch. 9 - For the circuit in Fig. 9.52, determine the value...Ch. 9 - In the series circuit of Fig. 9.53, set R = 1 ....Ch. 9 - Evaluate the derivative of each current and...Ch. 9 - Consider the circuit depicted in Fig. 9.55. If...Ch. 9 - Prob. 55ECh. 9 - In the circuit shown in Fig. 9.56, (a) obtain an...Ch. 9 - Prob. 57ECh. 9 - For the circuit represented in Fig. 9.57, (a)...Ch. 9 - FIGURE 9.57 Replace the 1 resistor in Fig. 9.57...Ch. 9 - A circuit has an inductive load of 2 H, a...Ch. 9 - (a) Adjust the value of the 3 resistor in the...Ch. 9 - Determine expressions for vC(t) and iL(t) in Fig....Ch. 9 - The capacitor in the LC circuit in Fig. 9.60 has...Ch. 9 - Suppose that the switch in the circuit in Fig....Ch. 9 - The capacitor in the circuit of Fig. 9.63 is set...Ch. 9 - The physical behavior of automotive suspension...Ch. 9 - A lossless LC circuit can be used to provide...
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- 1. Choose all nodes that must be included, if any, to construct the supernode for Nodal analysis. OV1, V3 OV1, V2 ○ V2, V3 OV1, V2, V4 OV1, V2, V3 O V2, V3, V4 2. Write KCL equation (Nodal equation) at super-node. Write your expression in terms of node voltages V1, V2, V3 and V4 and of the form (G11 V1+G12 V2+G13 V3+G14 V4 = 11), then enter the corresponding values: At super-node KCL: 1/Q G11 1/0 G12 1/Ω G13 1/Q G14 A 3. Use the above equation, the circuit and and super-node inner expression to calculate V3 and then lo : V3= V 10 = R3 Vst + A V₁ + VS2 V₂ V3 w W R₁ R₂ R4 ww R5 V4 V$3arrow_forwardEnter the matrix values (numerical) to solve for voltages at nodes v1, and v2, for the circuit shown, using Nodal equations. In the matrix, row 1, and row 2, correspond to node v1, and node v2 current expressions, respectively. Let Is1=14, Is2=7, R₁=5, R₂-8, R3=2, and R4-5. [G11 G12] [Vi₁ The matrix values are shown here: = G21 G22 [V2] [41] [12] {Hint: As discussed in class and to avoid sign errors, assume nodal currents are locally defined at each node (leaving) and use node labeling as indicated in the circuit. } The relative tolerance for this problem is 5%. VI R2 ww Isl 12 NODE v1 G11 G12 RI 1/Q 1/0 A 4= NODE v2 G21- 1/Q G22 1/0 12 W A === www R3 R4 www Use Cramer's rule (matrix), substitution, or any other method to calculate the voltages: v1 = V v2= V Is2arrow_forwardOnly expert should attemptarrow_forward
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