The atomic radius of calcium in its cubic close packing structure is given and its density has to be determined. Concept introduction: In packing of atoms in a crystal structure, the atoms are imagined as spheres. The two major types of close packing of the spheres in the crystal are – hexagonal close packing and cubic close packing. Cubic close packing structure has face-centered cubic (FCC) unit cell. In face-centered cubic unit cell, each of the six corners is occupied by every single atom. Each face of the cube is occupied by one atom. Each atom in the corner is shared by eight unit cells and each atom in the face is shared by two unit cells. Thus the number of atoms per unit cell in FCC unit cell is, 8 × 1 8 atoms in corners + 6 × 1 2 atoms in faces = 1 + 3 = 4 atoms The edge length of one unit cell is given by a = 2R 2 where a = edge length of unit cell R = radius of atom

Question

b) Certain cyclic compounds are known to be conformationally similar to carbohydrates, although they are not themselves carbohydrates. One example is Compound C shown below, which could be imagined as adopting four possible conformations. In reality, however, only one of these is particularly stable. Circle the conformation you expect to be the most stable, and provide an explanation to justify your choice. For your explanation to be both convincing and correct, it must contain not only words, but also "cartoon" orbital drawings contrasting the four structures. Compound C Possible conformations (circle one): Дет

Answer 1

Question

Chapter 9, Problem 51E

Interpretation Introduction

Interpretation:

        The atomic radius of calcium in its cubic close packing structure is given and its density has to be determined.

Concept introduction:

        In packing of atoms in a crystal structure, the atoms are imagined as spheres. The two major types of close packing of the spheres in the crystal are – hexagonal close packing and cubic close packing. Cubic close packing structure has face-centered cubic (FCC) unit cell.

       In face-centered cubic unit cell, each of the six corners is occupied by every single atom. Each face of the cube is occupied by one atom.

       Each atom in the corner is shared by eight unit cells and each atom in the face is shared by two unit cells. Thus the number of atoms per unit cell in FCC unit cell is,

                  $8 × 18 atoms in corners + 6 × 12 atoms in faces = 1 + 3 = 4 atoms        The edge length of one unit cell is given by a = 2R 2 where  a = edge length of unit cell R = radius of atom$

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