Explanation Consider whole molecule a system and O atom at the origin of coordinate system. Resolve the x-y coordinate for H atom. Write the expression for the center of mass in x direction. x C M = m 1 x 1 + m 2 x 2 sin θ + m 3 x 3 sin θ m 1 + m 2 + m 3 (I) Here, x C M is the center of mass of molecule, m 1 is the mass of O atom, m 2 is the mass of first H atom., m 3 is the mass of second H atom, x 1 is the distance for O atom, x 2 is the distance of first H atom on x axis, x 3 is the distance of second H atom on x axis and θ is the angle between H atom and vertical axis. Write the expression for centre of mass of objects in y direction. y C M = m 1 y 1 + m 2 y 2 cos θ + m 3 y 3 cos θ m 1 + m 2 + m 3 (II) Here, y c m for centre of mass in y direction. y 1 is the distance for O atom, y 2 is the distance of first H atom on y axis, y 3 is the distance of second H atom on y axis. Conclusion: Substitute 15.999 u for m 1 , 1.008 u for m 2 , 1.008 u for m 3 , 0 m for x 1 , 0.1 × 10 − 9 m for x 2 , 0.100 nm for x 3 and 53 ° for θ in equation (I). x C M = [ ( 15.999 u ) ( 0 m ) + ( 1.008 u ) ( 0.100 nm ) ( 10 − 9 m 1 nm ) sin 53 ° + ( 1.008 u ) ( 0.100 nm ) ( 10 − 9 m 1 nm ) sin 53 ° ] 15.999 u + 1.008 u + 1

Physics For Scientists And Engineers With Modern Physics, 9th Edition, The Ohio State University

9th Edition

ISBN: 9781305372337

Author: Raymond A. Serway | John W. Jewett

Publisher: Cengage Learning

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Physics For Scientists And Engineers With Modern Physics, 9th Edition, The Ohio State University

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Solution Summary: The author explains the centre of mass of molecule, which is 0.00673nm below the center of oxygen.

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