Biology: The Unity and Diversity of Life (MindTap Course List)
15th Edition
ISBN: 9781337408332
Author: Cecie Starr, Ralph Taggart, Christine Evers, Lisa Starr
Publisher: Cengage Learning
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Question
Chapter 9, Problem 4CT
Summary Introduction
To determine: The amino acid sequence that can be translated from the given mRNA
Concept introduction:
The genetic information of DNA is based on the nucleotide base sequences. These sequences are transcribed into mRNA triplets and are called as codons. These mRNA triplet nucleotides are then translated to form a polypeptide.
Expert Solution & Answer
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Translate the following mRNA nucleotide sequence into an amino acid sequence, starting at the second base:
5’ - UGUCAUGCUCGUCUUGAAUCUUGUGAUGCUCGUUGGAUUAAUUGU - 3’
For the messenger RNA sequence below, find the beginning of the amino acid coding sequence and translate the sequence using the
genetic code provided below.
5' - AAUUAUGGGCAAUAUGCCGGGCcGGUUAAGCG - 3'
Second Letter
A
UGU cys u
UGC
Phe UCU
UU
U UUC
UUA
UAU
Tyr
Ser UAC
UAA
UAG
Leu
UCA
Stop UGA Stop
UUG
UCG
Stop UGG
Trp
CUU
CU
CAU
His
CGU
c cuc
Leu ccc
ССА
CCG
Pro
CÁC
CAA
CAG
CGC
CGA
CGG
Arg
CUA
CUG
Gin
1st
3rd
letter
Ser u letter
AUU
ACU
AAU
AAC
AAA
AAG
Asn
A AUC
AUA
AUG
lle ACC
ACA
AGU
AGC
AGA
AGG
Thr
Lys
Arg
Met ACG
GUU
G GUC
GUA
GUG
GCU
GAU
GAC
GAA
Asp
GGU
Val
GCC
Ala
GGC
Gly
GCA
GGA
Glu
GCG
GAG
GGG
G
Consider the following coding 71 nucleotide DNA template sequence (It does not contain a translational start):
5’- GTTTCCCCTATGCTTCATCACGAGGGCACTGACATGTGTAAACGAAATTCCAACCTGAGCGGCGT GTTGAG-3’
By in vitro translating the mRNA, you determined that the translated peptide is 15 amino acids long. What is the expected peptide sequence in single letter abbreviations?
Chapter 9 Solutions
Biology: The Unity and Diversity of Life (MindTap Course List)
Ch. 9 - RIPs as Cancer Drugs Researchers are taking a page...Ch. 9 - RIPs as Cancer Drugs Researchers are taking a page...Ch. 9 - RIPs as Cancer Drugs Researchers are taking a page...Ch. 9 - RIPs as Cancer Drugs Researchers are taking a page...Ch. 9 - A chromosome contains many different genes that...Ch. 9 - A binding .site for RNA polymerase is called a ___...Ch. 9 - In cells, most RNA molecules are ___ ; most DNA...Ch. 9 - Prob. 4SQCh. 9 - The main function of a DNA molecule is to ________...Ch. 9 - The main function of an mRNA molecule is to ___ ....
Ch. 9 - Prob. 7SQCh. 9 - Prob. 8SQCh. 9 - Prob. 9SQCh. 9 - Anticodons pair with ___ . a. mRNA codons b. DNA...Ch. 9 - Prob. 11SQCh. 9 - Prob. 12SQCh. 9 - Prob. 13SQCh. 9 - Energy that drives translation is provided mainly...Ch. 9 - Match the terms with the best description. ______...Ch. 9 - Researchers are designing and testing antisense...Ch. 9 - An anticodon has the sequence GCG. What amino acid...Ch. 9 - Each position of a codon can be occupied by one of...Ch. 9 - Prob. 4CTCh. 9 - Translate the .sequence of bases in the previous...Ch. 9 - Can you .spell your name (or someone else's) using...Ch. 9 - Bacteria use the.same stop codons as eukaryotes....
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- For the following DNA bases, give the complementary mRNA code that would be transcribed from these bases: AGCTAATCGGCTACCAGGTACGGATATTCCarrow_forwardUsing the genetic code table provided below, identify the open reading frame in this mRNA sequence, and write out the encoded 9 amino acid long peptide sequence: 5'- CGACAUGCCUAAAAUCAUGCCAUGGAGGGGGUAACCUUUU C A G U UUU Phe UCU Ser UUC Phe UCC Ser UAC UCA Ser UAA UCG Ser UAG UUA Leu Leu G C CUU Leu CUC Leu CCC CUA Leu CUG Leu AUU lle AUC lle AUA lle AUG Met ACG ACU Thr ACC Thr ACA Thr Thr A UAU Tyr UGU Cys Tyr UGC Cys CCU Pro CAU His CGU Arg Pro CAC His Pro CAA Gln CGC Arg CGA Arg CCA CCG Pro CAG Gln CGG Arg GUU Val GCU Ala GAU GUC Val GCC Ala GAC GUA Val GCA Ala GAA GUG Val GCG Ala GAG Stop UGA Stop UGG AAU Asn AAC AAA AAG AGU Asn AGC G Lys Lys Asp Asp Glu Glu Stop A Trp Ser Ser AGA Arg AGG Arg GGU Gly GGC Gly UCAG GGA Gly GGG Gly с U C A G U C A G U C A Garrow_forwardUsing the codon table, identify a 5’-3’ sequence of nucleotides in the dna template strand for mRna coding for the polypeptide sequence NH2-PHe-Pro-lys-COOH.arrow_forward
- Indicate the amino acid sequence of the protein encoded by the following mRNA molecule. Use the genetic code table and assume that the very first “AUG” the ribosome encounters will serve as the start codon and specify methionine. 5’-AAUUCAUGCCCAAAUUUGGGGCACGAAGCUUCUUAGGCUAGUCCUAAAAAA-3’arrow_forwardThe DNA sequence below is transcribed from left to right (the partner/coding strand is shown). Using this sequence, write the sequence of the polypeptide that results from this gene. Be sure to appropriately label the ends of the molecule. 5'-ATGCACGGCGACTAG-3' Second letter A UAU Tyr UAC First letter U A G U UUU1 UUC UUA LOU Leu CUU CUC CUA CUG Phe GUU GUC GUA GUG Leu AUU AUC lle AUA AUG Met Val C UCU UCC UCA UCG CCU CCC CCA CCG ACU ACC ACA ACG GCU GCC GCA GCG Ser Pro Thr Ala CAU His CAC CAA CAG Gin AAU Asn AAC AAA 1 Lys AAG LYS G {}a UAA Stop UGA Stop A UAG Stop UGG Trp GAU 1 GAC Asp GAA GIU Glu GAGJ UGU UGC CGU CGC CGA CGG AGU AGC AGA AGG Cys GGU GGC GGA GGG Arg Ser Arg DOA DOA DOA DUTO Third letter Glyarrow_forwardGiven the following DNA sequence of the template strand for a given gene: 5' TTTCCGTCTCAGGGCTGAAAATGTTTGCTCATCGAACGC3' Part A ) Write the mRNA that will be transcribed from the DNA sequence above (be sure to label the 5' and 3' ends). Part B ) Use the genetic code to write the peptide sequence translated in a cell from the mRNA in part A. Please use the 3 letter abbreviation for each amino acid. Part C: How would the peptide synthesized in a cell be different if the mRNA was translated in vitro (i.e. not in the cell)?arrow_forward
- For the following mRNA sequences, what is the amino acid sequence formed? Consult genetic code table for reference. 5' AGUCCGUAC 3' 5' AAUUGCUUC 3'arrow_forwardFor the following mRNA sequence (reading from left to right) what will be the amino acid sequence following translation? (Use chart provided) AUGCCAGUUGAAUAA First position U C A UUU UUC UUA UUG CUU CUC CUA CUG U >Phe GUU GUC GUA GUG >Leu >Leu AUU ACU AUC lle ACC AUA ACA AUG Met/start ACG >Val UCU UCC UCA UCG ©2019 Pearson Education, Inc. CCU CCC CCA CCG GCU GCC GCA GCG Second position A >Ser >Pro Thr >Ala UAU UGU U UAC UGC C UAA Stop UGA Stop A UAG Stop UGG Trp G CAU CAC CAA CAG AAU AAC AAA AAG GAU GAC GAA GAG Tyr >His >Gin >Asn >Lys >Asp >Glu CGU CGC CGA CGG AGU AGC AGA AGG G GGU GGC GGA GGG >Cys Arg >Ser >Arg >Gly DOAG SCAG U с А UCA с А G Third position Correct answer not given Met-Val-Tyr-Pro Met-His-Phe-Ala-Arg Pro-Val-Met-Leu-His Met-Pro-Val-Gluarrow_forwardUsing the genetic code, interpret the following set of nucleotides. AUGGGUCCAUGGCGUAGGCCAAAUGAUGAGGAAUGAarrow_forward
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