Campbell Essential Biology (6th Edition) - standalone book
6th Edition
ISBN: 9780133917789
Author: Eric J. Simon, Jean L. Dickey, Jane B. Reece, Kelly A. Hogan
Publisher: PEARSON
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Chapter 9, Problem 3SQ
Edward was found to be heterozygous (Ss) for the sickle-cell trait. The alleles represented by the letters S and s are
- a. on the X and Y chromosomes.
- b. linked.
- c. on homologous chromosomes.
- d. both present in each of Edward’s sperm cells.
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Chapter 9 Solutions
Campbell Essential Biology (6th Edition) - standalone book
Ch. 9 - The genetic makeup of an organism is called its...Ch. 9 - Which of Mendels laws is represented by each...Ch. 9 - Edward was found to be heterozygous (Ss) for the...Ch. 9 - Whether an allele is dominant or recessive depends...Ch. 9 - Prob. 5SQCh. 9 - Prob. 6SQCh. 9 - Prob. 7SQCh. 9 - Prob. 8SQCh. 9 - Adult height in people is at least partially...Ch. 9 - A purebred brown mouse is repeatedly mated with a...
Ch. 9 - How could you determine the genotype of one of the...Ch. 9 - Tim and Jan have freckles (a dominant trait), but...Ch. 9 - Incomplete dominance is seen in the inheritance of...Ch. 9 - Why was Henry VIII wrong to blame his wives for...Ch. 9 - Both parents of a boy arc phenotypically normal,...Ch. 9 - Heather was surprised to discover that she...Ch. 9 - Prob. 17SQCh. 9 - In 1981, a stray cat with unusual curled-back ears...Ch. 9 - Prob. 19PSCh. 9 - There are now nearly 200 recognized breeds of dog,...Ch. 9 - Gregor Mendel never saw a gene, yet he concluded...Ch. 9 - Prob. 22BS
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- Hemophilia in humans is due to a mutation on the X chromosome. What will be the result of mating between a normal (non-carrier) female and a hemophiliac male? A. Half of the daughters are normal and half of the sons are hemophiliacs. B. All sons are normal and all daughters are carriers. C. All daughters are normal and all sons are carriers. D. Half of the children are normal and the other half are hemophiliacs; All daughters are carriers.arrow_forwardIn humans, brown eyes (B) are dominant over blue. A brown eyed man marries a blue-eyed (b) woman and they have three children two of whom are brown-eyed and one of whom is blue-eyed. if the male has brown eyes but has a blue-eyed child, what must his genotype be?arrow_forwarda) Look at the chart above, which shows a dihybrid cross for two brown horses, which leads to brown, tan and white offspring. What kind of epistasis is this, and explain how you know? b) You have a white horse and cross it with another white horse. What color will the offspring be? Explain your answer.arrow_forward
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- which As a result of the abnormalities in chromosomes divergence in meiosis, there was formed the secondary oocyte, included 22 autosomes only. What disease can the baby have, after impregnation of this secondary oocyte by the normal spermatozoon? Select one: a. Klinfelter's syndrome b. Turner's syndrome c. Trisomy on the X-chromosome d. Down's syndrome e. Edward's syndromearrow_forwardMatch the mode of inheritance with its description. (1) autosomal recessive A. inherited by males from carrier mothers(2) autosomal dominant B. inherited from one affected parent(3) X-linked recessive C. inherited from two carrier (unaffected) parentsarrow_forwardHemophilia, disease in which the blood lacks a clotting factor, is caused by an X linked recessive gene. Joe doe not have hemophilia and Lucille is heterozygous for the condition. What is the chance that their MALE child will have hemophilia? (Note: you are calculating the probability for their MALE children only, in other words if they have 1 male child, what is the probability that he will be born with the disease?) 0% 1/4 or 25% 2/4 or 50% 3/4 or 75% 4/4 or 100%arrow_forward
- Fragile X is a disorder which causes mental impairment in affected individuals. The trait which is due to a mutation in the FMR1 gene on the X chromosome is inherited in a recessive manner. An unaffected son was born to an affected man and an unaffected woman. The woman’s mother was affected while the father was normal. a. Indicate the gene notation. b. Give the genotype of the son. c. Is it possible for the couple to have an affected daughter? affected son? Derive the genotypic and phenotypic ratios for the offspring. Show and label your solutions properly. d. If the couple has four children, what is the probability that they will have three normal daughters and one normal son?arrow_forwardMen have XY (or YX) chromosomes and women have XX chromosomes. X-linked recessive genetic diseases (such as juvenile retinoschisis) occur when there is a defective X chromosome that occurs without a paired X chromosome that is not defective. Represent a defective X chromosome with lowercase x, so a child with the xY or Yx pair of chromosomes will have the disease and a child with XX or XY or YX or xX or Xx will not have the disease. Each parent contributes one of the chromosomes to the child. Complete parts a through d below. a. If a father has the defective x chromosome and the mother has good XX chromosomes, what is the probability that a son will inherit the disease? nothing (Type an integer or a decimal. Do not round.) b. If a father has the defective x chromosome and the mother has good XX chromosomes, what is the probability that a daughter will inherit the disease? nothing (Type an integer or a decimal. Do not round.) c. If a mother has one defective x…arrow_forwardA person with Down syndrome has one less chromosome than normal. Select one: a. False O b. Truearrow_forward
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