Campbell Essential Biology (6th Edition) - standalone book
6th Edition
ISBN: 9780133917789
Author: Eric J. Simon, Jean L. Dickey, Jane B. Reece, Kelly A. Hogan
Publisher: PEARSON
expand_more
expand_more
format_list_bulleted
Concept explainers
Videos
Textbook Question
Chapter 9, Problem 12SQ
Tim and Jan have freckles (a dominant trait), but their son Michael does not. Show with a Punnett square how this is possible. If Tim and Jan have two more children, what is the probability that both of them will have freckles?
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
Tim and Jan both have freckles, but their son Michael does not. Show with a Punnett square how this is possible. If Tim and Jan have another child, what is the probability that it will have freckles?
Mary and Dai both have freckles (a dominant trait). Their first child, Mariko, does not have freckles. Show using a Punnett square show how this is possible. If they have two more children who DO freckles (making for one without and two with) what is the probability that the NEXT child will NOT have freckles?
Frank and Susan both have freckles but they're firstborn son Lawrence does not demonstrate the characteristics. What are the most likely genotype of Frank Susan and Lawrence?
Chapter 9 Solutions
Campbell Essential Biology (6th Edition) - standalone book
Ch. 9 - The genetic makeup of an organism is called its...Ch. 9 - Which of Mendels laws is represented by each...Ch. 9 - Edward was found to be heterozygous (Ss) for the...Ch. 9 - Whether an allele is dominant or recessive depends...Ch. 9 - Prob. 5SQCh. 9 - Prob. 6SQCh. 9 - Prob. 7SQCh. 9 - Prob. 8SQCh. 9 - Adult height in people is at least partially...Ch. 9 - A purebred brown mouse is repeatedly mated with a...
Ch. 9 - How could you determine the genotype of one of the...Ch. 9 - Tim and Jan have freckles (a dominant trait), but...Ch. 9 - Incomplete dominance is seen in the inheritance of...Ch. 9 - Why was Henry VIII wrong to blame his wives for...Ch. 9 - Both parents of a boy arc phenotypically normal,...Ch. 9 - Heather was surprised to discover that she...Ch. 9 - Prob. 17SQCh. 9 - In 1981, a stray cat with unusual curled-back ears...Ch. 9 - Prob. 19PSCh. 9 - There are now nearly 200 recognized breeds of dog,...Ch. 9 - Gregor Mendel never saw a gene, yet he concluded...Ch. 9 - Prob. 22BS
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, biology and related others by exploring similar questions and additional content below.Similar questions
- The Eastwoods are going to have a child. She has chestnut hair (MBdMBk), and he has dark brown hair. Find their child's possible hair colors and the probabilities of each. (Enter exact numbers as integers, fractions, or decimals.) blond strawberry blond bright red light brown reddish brown dark red medium brown chestnut auburn dark brown shiny dark brown glossy dark brown black shiny black glossy blackarrow_forwardA couple has three children, all of whom have brown eyes and blond hair. Both parents are heterozygous for brown eyes (Bb), but one is blond (rr) and the other is a redhead (Rr). What is the probability that the next child will be a brown-eyed redhead? For full credit, you must show all workarrow_forwardHemophilia is a sex-linked recessive trait. A male hemophiliac and phenotypically normal female have a son with hemophilia. They would like to have one more child. What is the probability of having a child without hemophilia? Explain using a Punnett square. Is it possible for a girl to be born with hemophilia? Explain.arrow_forward
- Mark has an autosomal recessive condition called sickle cell anemia, a serious blood disorder that is associated with painful complications. His spouse has not experienced symptoms of sickle cell anemia but their first child developed the disease. What conclusions can be drawn about the mother's genotype and the probability of having a second child with the condition? Answer Choices: A: her genotype is heterozygous and there is a 25% percent chance of having another child with the disorder B: her genotype is heterozygous and there is a 50% percent chance of having another child with the disorder C: her genotype is heterozygous and there is a 75% percent chance of having another child with the disorder D: she lacks the allele for sickle cell anemia in that she lacks symptoms of the disease. There is a 0% percent chance of having another child with the disorderMark has an autosomal recessive condition called sickle cell anemia, a serious blood disorder that is associated with…arrow_forwardBob and Joan know from a blood test that they are each heterozygous (carriers) for the autosomal recessive gene that causes sickle cell disease. If their first three children are healthy, what is the probability that their fourth child will have the disease?arrow_forwardBryan has albinism, an autosomal recessive trait, which means he is homozygous recessive for albinism and his genotype is aa. Bryan's parents, Frank and Amy, do not have albinism however they must both be heterozygous. Bryan's sister, Allice, is a carrier for albinism. If Allice has offspring with Jim, who has no family history of albinism, what are the chances that their offspring are carriers for albinism? What are the chances that they children will get albinism? Use Punnett squares.arrow_forward
- Jan and Michael are both carriers for the cystic fibrosis allele. If Jan and Michael have three children with the disease and then Jan becomes pregant with fratnernal twins, what is the probability that both twins will also have the disease?arrow_forwardUnattached earlobes (E) are dominant over attached earlobes (e) [Figure (a) and (b)]. If a woman with unattached earlobes and a man with attached earlobes have children, what percentage of their children has the possibility of having unattached earlobes if the mother is homozygous for the trait?arrow_forwardMarly is doing a paternity test to determine who could be her father. She is going just off of word of mouth for now so there is no way for her to figure out the genotypes of ther potential fathers. She knows for certain that she is type A with the genotype (A^I A^i). Her potential fathers are Gayle who is a Type O, Jake who is type A,and Mark who is Type AB. Who could be the potential father?arrow_forward
- There is a couple, the blood type of a male is A+ and the female is o+. What are all the possible blood types of their children in the future? Illustrate the inheritance in a Punnett Square showing all the possible blood types from the offspring of the male and female.arrow_forwardA recently married couple are both heterozygous for cystic fibrosis, a recessive genetic disorder. They would like to start a family and would like to have two children. What is the probability that both their first and second child would have cystic fibrosis?arrow_forwardJan and Michael are both carriers for the cystic fibrosis allele. If Jan and Michael have five children, what the probability that three or more of the children will have the disease?arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Human Biology (MindTap Course List)BiologyISBN:9781305112100Author:Cecie Starr, Beverly McMillanPublisher:Cengage Learning
Human Biology (MindTap Course List)
Biology
ISBN:9781305112100
Author:Cecie Starr, Beverly McMillan
Publisher:Cengage Learning
How to solve genetics probability problems; Author: Shomu's Biology;https://www.youtube.com/watch?v=R0yjfb1ooUs;License: Standard YouTube License, CC-BY
Beyond Mendelian Genetics: Complex Patterns of Inheritance; Author: Professor Dave Explains;https://www.youtube.com/watch?v=-EmvmBuK-B8;License: Standard YouTube License, CC-BY