Campbell Essential Biology (6th Edition) - standalone book
6th Edition
ISBN: 9780133917789
Author: Eric J. Simon, Jean L. Dickey, Jane B. Reece, Kelly A. Hogan
Publisher: PEARSON
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Chapter 9, Problem 15SQ
Both parents of a boy arc
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In addition to the allelic pair determining pattern baldness in man (B,b), consider early baldness to be due to another autosomal allele (E) on a different pair of chromosomes and also dominant in males but recessive in females. The phenotype for ee may be late or nonbaldness depending on sex and the genotype for B, b alleles. Two doubly heterozygous persons marry.
What is the phenotype of the male parent?
What is the phenotype of the female parent?
Give the phenotypic ratio expected among male children of couples such as this one. Show corresponding genotypes for each phenotype mentioned in your phenotypic ratio.
Give the phenotypic ratio expected among female children of couples such as this one. Show corresponding genotypes for each phenotype mentioned in your phenotypic ratio.
Answer
Using the pedigree chart attached:
Above is a pedigree for colorblindness. Based on the pedigree, is the disease dominant or recessive and is it sex-linked or autosomal? Why? Furthermore, what is the probability that 18 on this chart is affected but the condition, and what is the probability that 18 is a carrier? Why? Are the probability of being a carrier and an affected individual different? Why?
Chapter 9 Solutions
Campbell Essential Biology (6th Edition) - standalone book
Ch. 9 - The genetic makeup of an organism is called its...Ch. 9 - Which of Mendels laws is represented by each...Ch. 9 - Edward was found to be heterozygous (Ss) for the...Ch. 9 - Whether an allele is dominant or recessive depends...Ch. 9 - Prob. 5SQCh. 9 - Prob. 6SQCh. 9 - Prob. 7SQCh. 9 - Prob. 8SQCh. 9 - Adult height in people is at least partially...Ch. 9 - A purebred brown mouse is repeatedly mated with a...
Ch. 9 - How could you determine the genotype of one of the...Ch. 9 - Tim and Jan have freckles (a dominant trait), but...Ch. 9 - Incomplete dominance is seen in the inheritance of...Ch. 9 - Why was Henry VIII wrong to blame his wives for...Ch. 9 - Both parents of a boy arc phenotypically normal,...Ch. 9 - Heather was surprised to discover that she...Ch. 9 - Prob. 17SQCh. 9 - In 1981, a stray cat with unusual curled-back ears...Ch. 9 - Prob. 19PSCh. 9 - There are now nearly 200 recognized breeds of dog,...Ch. 9 - Gregor Mendel never saw a gene, yet he concluded...Ch. 9 - Prob. 22BS
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- The following pedigree shows the pattern of inheritance of red-green color blindness in a family. Females are shown as circles and males as squares; the squares or circles of individuals affected by the trait are filled in black. What is the chance that a son of the third-generation female indicated by the arrow will be color blind if the father is not color blind? If he is color blind?arrow_forwardAn allele responsible for Marfan syndrome Section 13.4 is inherited in an autosomal dominant pattern. What is the chance that a child will inherit the allele if one parent does not carry it and the other is heterozygous?arrow_forwardVariations on a Theme by Mendel Pea plants usually have white or red flowers. A strange pea-plant variant is found that has pink flowers. A selfcross of this plant yields the following phenotypes: 30 red flowers 62 pink flowers 33 white flowers What are the genotypes of the parents? What is the genotype of the progeny with red flowers?arrow_forward
- A pedigree analysis was performed on the family of a man with schizophrenia. Based on the known concordance statistics, would his MZ twin be at high risk for the disease? Would the twins risk decrease if he were raised in an environment different from that of his schizophrenic brother?arrow_forwardThe blood serum from one individual (let’s call this person individual 1) is known to agglutinate the red blood cells from a secondindividual (individual 2). List the pairwise combinations of possible genotypes that individuals 1 and 2 could have. If individual 1is the parent of individual 2, what are his or her possiblegenotypes?arrow_forwardA man, Penoy, whose sister died in early childhood from a recessive lethal disease marries a woman Esmae, who has the same family history. Because Penoy has survived beyond childhood, he does not have the disease, but he may be a carrier (i.e. heterozygous, as may also be the case with Esmae). What is the probability that their first child will suffer from the disease? [Hint: first calculate the probability that Penoy is heterozygous; then determine the probability that both parents are carriers. Remember that he has survived to adulthood when calculating this probability].arrow_forward
- Hemophilia is caused by an X-linked recessive mutation in humans. If a man whose paternal uncle (father's brother) was a hemophiliac marries a woman whose brother is also a hemophiliac, what is the probability that their first child will have hemophilia? (Assume that no other cases of hemophilia exist in the pedigree.) 1/3 0 1/8 0 1/4 1/2arrow_forwardThis is a typical pedigree for a family that carries neurofibromatosis. Is individual I-2 most likely homozygous or heterozygous? Why? Explain.arrow_forwardTwo phenotypically normal people marry. Unknown to them, they have a common great-grandfather who suffered from a rare disorder (1 in 30,000 affected in the general population) that is inherited as an auto- somal recessive trait (dd). Assume that the people marrying into this pedigree are all DD, that there has been no earlier consanguinity, and that no affected (dd) individuals have occurred. What is the probability that the first child of this couple (a baby girl) will. be affected? Draw the pedigree.arrow_forward
- Which of the Pedigree diagrams below is most likely to show a family with Sickle Cell Anaemia?arrow_forward1 6 Achondroplasia is the most common form of dwarfism in miniature horses. Achondroplasia dwarf horses have normal sized bodies and heads, but noticeably smaller upper legs and ears. This form of dwarfism is an autosomal dominant trait. The pedigree shows the offspring of one horse without dwarfism, Individual 1, and one with dwarfism, Individual 2. The horses with achondroplasia are shorter. B A Dwarf, Homozygous dominant C 7 Dwarf, Heterozygous Non-Dwarf, Homozygous recessive D Non-Dwarf, Heterozygous 3 Which of the following is the correct pairing of phenotype and genotype of Individual 5 in the pedigree? 11 1 4 2 5 7 of 11 ? > Submit €arrow_forwardAcatalasia is caused by a rare autosomal recessive gene. In heterozygous condition catalase activity is decreased slightly. A woman with a normal catalase activity have a husband with low catalase activity. What is the probability of children birth without anomaly in the family, if grandparents from both sides have reduced activity of catalase? Diagram the cross and mention the genotypes of all individuals in the family?arrow_forward
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