Concept explainers
(a)
Interpretation:
The alcohol in the given pair that undergoes an elimination reaction more rapidly when heated with
Concept introduction:
Dehydration reaction:
Removal of water molecule from the alcohol in the presence of strong acid like sulfuric acid is known as dehydration reaction.
Carbocation: It is carbon ion that bears a positive charge on it.
The increasing stability order of carbocation is as follows,
Primary carbocation < secondary carbocation < tertiary carbocation
(b)
Interpretation:
The alcohol in the given pair that undergoes an elimination reaction more rapidly when heated with
Concept introduction:
Dehydration reaction:
Removal of water molecule from the alcohol in the presence of strong acid like sulfuric acid is known as dehydration reaction.
Carbocation: It is carbon ion that bears a positive charge on it.
The increasing stability order of carbocation is as follows,
Primary carbocation < secondary carbocation < tertiary carbocation
(c)
Interpretation:
The alcohol in the given pair that undergoes an elimination reaction more rapidly when heated with
Concept introduction:
Dehydration reaction:
Removal of water molecule from the alcohol in the presence of strong acid like sulfuric acid is known as dehydration reaction.
Carbocation: It is carbon ion that bears a positive charge on it.
The increasing stability order of carbocation is as follows,
Primary carbocation < secondary carbocation < tertiary carbocation
(d)
Interpretation:
The alcohol in the given pair that undergoes an elimination reaction more rapidly when heated with
Concept introduction:
Dehydration reaction:
Removal of water molecule from the alcohol in the presence of strong acid like sulfuric acid is known as dehydration reaction.
Carbocation: It is carbon ion that bears a positive charge on it.
The increasing stability order of carbocation is as follows,
Primary carbocation < secondary carbocation < tertiary carbocation
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Chapter 9 Solutions
Essential Organic Chemistry (3rd Edition)
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- Don't used Ai solution and hand raitingarrow_forward75.0 grams of an unknown metal was heated to 95.0°C, it was then placed into 150.0 grams of water at23.1°C, when the metal and water reached thermal equilibrium, the temperature was 27.8°C. Calculatethe specific heat of the metal. (Assume that the specific heat of water is 4.18 J/g °C)arrow_forwardPlease correct answer and don't used hand raitingarrow_forward
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